Not all discontinuities are created equal! There are three main types.
1. Removable Discontinuity (Hole)
What it is: The limit exists, but either f(a) doesn't exist or f(a) ≠ limit
Visual: An open circle (hole) in the graph
Example:f(x)=x−1
📚 Practice Problems
1Problem 1easy
❓ Question:
Identify the type of discontinuity in f(x)=x−4 at x = 4.
Explain using:
📋 AP Calculus AB — Exam Format Guide
⏱ 3 hours 15 minutes📝 51 questions📊 4 sections
Section
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Questions
Time
Weight
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MCQ
30
60 min
33.3%
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15
45 min
16.7%
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2
30 min
16.7%
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4
60 min
33.3%
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~22%
💡 Key Test-Day Tips
✓Show all work on FRQs
✓Use proper notation
✓Check units
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⚠️ Common Mistakes: Types of Discontinuity
Avoid these 4 frequent errors
🌍 Real-World Applications: Types of Discontinuity
See how this math is used in the real world
📝 Worked Example: Related Rates — Expanding Circle
Problem:
A stone is dropped into a still pond, creating a circular ripple. The radius of the ripple is increasing at a rate of 2 cm/s. How fast is the area of the circle increasing when the radius is 10 cm?
Classifying the different ways a function can be discontinuous
How can I study Types of Discontinuity effectively?▾
Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 5 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
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What course covers Types of Discontinuity?▾
Types of Discontinuity is part of the AP Calculus AB course on Study Mondo, specifically in the Limits and Continuity section. You can explore the full course for more related topics and practice resources.
Are there practice problems for Types of Discontinuity?
x2−1
At x = 1: limx→1f(x)=2 but f(1) is undefined.
Why "removable"?
You could "fix" it by defining or redefining f(1) = 2!
2. Jump Discontinuity
What it is: Left and right limits exist but are different
Visual: The graph "jumps" from one height to another
Example:f(x)={xx+2if x<1if x≥1
At x = 1:
limx→1−f(x)=1
limx→1+f(x)=3
These are different, so there's a jump!
Why not removable?
No way to pick a single value for f(1) that makes both sides happy.
3. Infinite Discontinuity (Vertical Asymptote)
What it is: At least one one-sided limit is infinite
Visual: The graph shoots off to ±∞
Example:f(x)=x−21
At x = 2: limx→2+f(x)=+∞ (infinite limit)
Why the worst?
The function completely "blows up" - can't fix it at all!
Comparison Table
Type
Limit Exists?
f(a) Exists?
Can Fix It?
Visual
Removable
Yes
Maybe, but wrong
Yes ✓
Hole ○
Jump
No (sides differ)
Maybe
No ✗
Step ⌐⌙
Infinite
No (infinite)
No
No ✗
Asymptote ↕
Identifying the Type
Step 1: Find the one-sided limits
Step 2: Apply this flowchart:
Both sides equal → Removable (if discontinuous)
Both sides different (but finite) → Jump
At least one side infinite → Infinite
Example Analysis 1
f(x)=x2−4x+2 at x = 2
Factor: x2−4=(x−2)(x+2)
f(x)=(x−2)(x+2)x+2=x−21 (after canceling)
At x = 2: The denominator → 0 while numerator → 1
One-sided limits are infinite!
Type: Infinite discontinuity (vertical asymptote at x = 2)
Example Analysis 2
f(x)={x25if x=3if x=3
limx→3f(x)=limx→3x2=9
But f(3) = 5 ≠ 9
Type: Removable discontinuity (could fix by changing f(3) to 9)
Example Analysis 3
f(x)=⌊x⌋ (floor function) at x = 2
limx→2−⌊x⌋=1 (approaching 2 from below)
limx→2+⌊x⌋=2 (at 2 and above)
Different limits!
Type: Jump discontinuity
The Intermediate Value Theorem
Important connection: If f is continuous on [a, b], it must take every value between f(a) and f(b).
Discontinuities break this! With a jump, the function "skips" values.
Practice Tip
When analyzing discontinuity:
Find where it's discontinuous (often where denominator = 0)
Calculate one-sided limits
Compare limits to each other and to f(a)
Classify the type based on your findings
x2−16
💡 Show Solution
Step 1: Check if discontinuous
f(4)=4−416−16=00
Undefined, so discontinuous! ✓
Step 2: Find the limit
Factor the numerator:
f(x)=x−4(x−4)(x+4) (for )
limx→4f(x)=limx→4(
Step 3: Analyze
Limit exists and equals 8
f(4) doesn't exist
No infinite behavior
Both one-sided limits equal 8
Type: Removable discontinuity
We could "remove" the hole by defining f(4) = 8!
2Problem 2hard
❓ Question:
Classify all discontinuities of g(x)=⎩⎨⎧x−1x254
💡 Show Solution
Let's check potential discontinuity points: x = 0 and x = 2
At x = 0:
Left limit: limx→0−(x−1)
3Problem 3easy
❓ Question:
Identify the type of discontinuity at x = 3 for f(x) = (x² - 9)/(x - 3).
💡 Show Solution
Step 1: Check if f(3) is defined:
f(3) = (9 - 9)/(3 - 3) = 0/0 (undefined)
Step 3: Classification:
• f(3) is undefined
• But lim(x→3) f(x) = 6 exists
• This is a hole in the graph
Step 4: Type of discontinuity:
This is a REMOVABLE discontinuity (also called a point discontinuity or hole)
It can be "removed" by redefining f(3) = 6
Answer: Removable discontinuity at x = 3
4Problem 4medium
❓ Question:
Classify the discontinuity at x = 2 for f(x) = { x + 1, if x < 2; 5, if x ≥ 2 }.
💡 Show Solution
Step 1: Find f(2):
f(2) = 5 (defined)
Step 2: Find lim(x→2⁻):
For x < 2, f(x) = x + 1
lim(x→2⁻) (x + 1) = 3
Step 3: Find lim(x→2⁺):
For x ≥ 2, f(x) = 5
lim(x→2⁺) 5 = 5
Yes, this page includes 5 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.