Skip to content

Surface Area and Volume

Calculate surface area and volume of 3D shapes

Written and reviewed by the Study Mondo Education TeamLast updated
🎯⭐ INTERACTIVE LESSON

Try the Interactive Version!

Learn step-by-step with practice exercises built right in.

Start Interactive Lesson →

Surface Area and Volume

Three-dimensional shapes are all around us! Understanding surface area and volume helps you solve real-world problems involving boxes, containers, buildings, and more. Let's explore how to calculate these important measurements!


3D Shapes vs. 2D Shapes

2D shapes are flat (like squares, circles, triangles)

  • Measure: Area (square units)

3D shapes have length, width, AND height

  • Measure: Volume (cubic units) and Surface Area (square units)

Common 3D shapes:

  • Rectangular prism (box)
  • Cube
  • Cylinder
  • Cone
  • Sphere
  • Pyramid

What Is Volume?

Volume measures the amount of space inside a 3D shape.

Think of it as: How much liquid could it hold? How many unit cubes fit inside?

Units: Cubic units (cm³, in³, m³, ft³)

Example: A box that is 3 cm × 4 cm × 2 cm has volume = 24 cm³ (24 cubic centimeters of space inside)


What Is Surface Area?

Surface Area measures the total area of all the outer surfaces of a 3D shape.

Think of it as: How much wrapping paper do you need to cover it? How much paint to cover all sides?

Units: Square units (cm², in², m², ft²)

Example: A cube with 6 faces, each 2 cm × 2 cm, has surface area = 6 × 4 = 24 cm²


Rectangular Prism (Box)

A box with length (l), width (w), and height (h).

Volume Formula

V = l × w × h

Example: Find the volume of a box: length = 5 ft, width = 3 ft, height = 4 ft

Solution: V = 5 × 3 × 4 = 60 ft³

Answer: 60 cubic feet

Surface Area Formula

A rectangular prism has 6 faces (top, bottom, front, back, left, right).

SA = 2lw + 2lh + 2wh

Or think: SA = 2(lw + lh + wh)

Example: Same box (5 ft × 3 ft × 4 ft)

Solution: SA = 2(5×3) + 2(5×4) + 2(3×4) SA = 2(15) + 2(20) + 2(12) SA = 30 + 40 + 24 SA = 94 ft²

Answer: 94 square feet


Cube

A cube is a special rectangular prism where all edges are equal (s = side length).

Volume Formula

V = s³ (side × side × side)

Example: A cube with side = 6 cm

Solution: V = 6³ = 6 × 6 × 6 = 216 cm³

Answer: 216 cubic centimeters

Surface Area Formula

A cube has 6 identical square faces.

SA = 6s²

Example: Same cube (side = 6 cm)

Solution: SA = 6 × (6²) = 6 × 36 = 216 cm²

Answer: 216 square centimeters

Note: For this cube, volume and surface area have the same number, but DIFFERENT UNITS!


Cylinder

A cylinder has two circular bases and a curved side.

Volume Formula

V = πr²h

Where r = radius of the base, h = height

Example: A cylinder with radius = 4 in and height = 10 in

Solution: V = π × (4²) × 10 V = π × 16 × 10 V = 160π ≈ 502.65 in³

Answer: About 503 cubic inches

Surface Area Formula

Surface area = 2 circular bases + curved side (which "unrolls" into a rectangle)

SA = 2πr² + 2πrh

Or: SA = 2πr(r + h)

Example: Same cylinder (r = 4 in, h = 10 in)

Solution: SA = 2π(4²) + 2π(4)(10) SA = 2π(16) + 2π(40) SA = 32π + 80π SA = 112π ≈ 351.86 in²

Answer: About 352 square inches


Triangular Prism

A prism with triangular bases.

Volume Formula

V = (Area of base) × height

For triangular base: V = (1/2 × base × height of triangle) × prism height

Example: Triangular prism with:

  • Triangle base = 6 cm, triangle height = 4 cm
  • Prism height = 10 cm

Solution: V = (1/2 × 6 × 4) × 10 V = (12) × 10 V = 120 cm³

Answer: 120 cubic centimeters

Surface Area

Add: 2 triangular bases + 3 rectangular sides

Example: Calculate each face area and add them all up!


Cone

A cone has one circular base and comes to a point (apex).

Volume Formula

V = (1/3)πr²h

Where r = radius, h = height (perpendicular from base to apex)

Example: A cone with radius = 3 ft and height = 8 ft

Solution: V = (1/3)π(3²)(8) V = (1/3)π(9)(8) V = (1/3)π(72) V = 24π ≈ 75.40 ft³

Answer: About 75 cubic feet

Note: Cone volume is 1/3 of a cylinder with same base and height!


Sphere

A perfectly round ball shape.

Volume Formula

V = (4/3)πr³

Where r = radius

Example: A sphere with radius = 5 m

Solution: V = (4/3)π(5³) V = (4/3)π(125) V = (500/3)π ≈ 523.60 m³

Answer: About 524 cubic meters

Surface Area Formula

SA = 4πr²

Example: Same sphere (r = 5 m)

Solution: SA = 4π(5²) SA = 4π(25) SA = 100π ≈ 314.16 m²

Answer: About 314 square meters


Pyramid

A pyramid has a base (often square) and triangular faces meeting at an apex.

Volume Formula

V = (1/3) × (Area of base) × height

For square base: V = (1/3) × s² × h

Example: Square pyramid with base side = 6 cm and height = 9 cm

Solution: V = (1/3) × (6²) × 9 V = (1/3) × 36 × 9 V = (1/3) × 324 V = 108 cm³

Answer: 108 cubic centimeters

Note: Pyramid volume is 1/3 of a prism with same base and height!


Real-World Applications

Packaging (Rectangular Prism)

Problem: A shipping box is 12 in × 8 in × 6 in. How much can it hold? How much cardboard is needed to make it?

Volume (capacity): V = 12 × 8 × 6 = 576 in³

Surface Area (cardboard): SA = 2(12×8) + 2(12×6) + 2(8×6) SA = 2(96) + 2(72) + 2(48) SA = 192 + 144 + 96 = 432 in²

Answer: Holds 576 in³, needs 432 in² of cardboard

Swimming Pool (Rectangular Prism)

Problem: A pool is 20 ft long, 10 ft wide, and 5 ft deep. How many gallons of water does it hold? (1 ft³ = 7.48 gallons)

Solution: V = 20 × 10 × 5 = 1,000 ft³ Gallons = 1,000 × 7.48 = 7,480 gallons

Answer: 7,480 gallons

Soda Can (Cylinder)

Problem: A can has radius 3 cm and height 12 cm. How much soda does it hold?

Solution: V = πr²h = π(3²)(12) = 108π ≈ 339.29 cm³

Answer: About 339 cm³ (about 339 mL)

Ice Cream Cone

Problem: An ice cream cone has radius 2 in and height 6 in. What's its volume?

Solution: V = (1/3)πr²h = (1/3)π(2²)(6) = 8π ≈ 25.13 in³

Answer: About 25 cubic inches

Basketball (Sphere)

Problem: A basketball has radius 4.7 inches. What's its volume?

Solution: V = (4/3)πr³ = (4/3)π(4.7³) ≈ 434.89 in³

Answer: About 435 cubic inches


Comparing Volume Formulas

Notice the patterns:

Prisms: V = (Base Area) × Height

  • Rectangular: V = lwh
  • Triangular: V = (1/2)bh × H
  • Cylinder: V = πr²h

Pyramids/Cones: V = (1/3) × (Base Area) × Height

  • Square pyramid: V = (1/3)s²h
  • Cone: V = (1/3)πr²h

Pattern: Pyramids and cones are 1/3 the volume of prisms/cylinders with the same base and height!

Sphere: V = (4/3)πr³ (unique formula)


Finding Unknown Dimensions

Sometimes you know the volume and need to find a dimension!

Example 1: Find Height

A rectangular prism has volume 120 cm³, length = 6 cm, width = 4 cm. Find height.

Solution: V = lwh 120 = 6 × 4 × h 120 = 24h h = 5 cm

Answer: Height = 5 cm

Example 2: Find Radius

A cylinder has volume 150π in³ and height = 6 in. Find radius.

Solution: V = πr²h 150π = πr²(6) 150π = 6πr² 25 = r² r = 5 in

Answer: Radius = 5 inches


Units and Conversions

Important: Keep units consistent!

Volume units:

  • 1 m³ = 1,000,000 cm³
  • 1 ft³ = 1,728 in³
  • 1 m³ = 1,000 liters
  • 1 cm³ = 1 milliliter (mL)

Example: A box is 10 cm × 10 cm × 10 cm. Find volume in cm³ and liters.

Solution: V = 10³ = 1,000 cm³ In liters: 1,000 cm³ = 1,000 mL = 1 liter

Answer: 1,000 cm³ or 1 liter


Common Mistakes to Avoid

❌ Mistake 1: Confusing volume and surface area

  • Volume = inside space (cubic units)
  • Surface Area = outside covering (square units)

❌ Mistake 2: Forgetting the 1/3 for cones and pyramids

  • Wrong: Cone V = πr²h
  • Right: Cone V = (1/3)πr²h

❌ Mistake 3: Using diameter instead of radius

  • Formulas use RADIUS (half of diameter)
  • If given diameter 10, use r = 5!

❌ Mistake 4: Wrong units

  • Volume needs CUBIC units (cm³, not cm²)
  • Surface Area needs SQUARE units (cm², not cm³)

❌ Mistake 5: Calculation errors with π

  • Use calculator's π button for accuracy
  • Or use 3.14 as approximation

❌ Mistake 6: Mixing up dimensions

  • Height vs. slant height (pyramids, cones)
  • Base vs. total height
  • Label your diagram!

Practice Tips

Tip 1: Draw and label

  • Sketch the 3D shape
  • Label all dimensions clearly
  • Mark what you're finding

Tip 2: Identify the shape

  • What 3D shape is it?
  • Which formula do you need?

Tip 3: Check what's given

  • Do you have radius or diameter?
  • Are all measurements in same units?
  • Convert if needed!

Tip 4: Use formulas correctly

  • Write the formula first
  • Substitute values
  • Calculate step-by-step

Tip 5: Check reasonableness

  • Volume should be in cubic units
  • Surface area should be in square units
  • Does the size make sense?

Tip 6: Remember special cases

  • Cube: all edges equal
  • Cylinder: circular bases
  • Cone/pyramid: includes 1/3

Quick Reference Formulas

Rectangular Prism:

  • Volume: V = lwh
  • Surface Area: SA = 2(lw + lh + wh)

Cube:

  • Volume: V = s³
  • Surface Area: SA = 6s²

Cylinder:

  • Volume: V = πr²h
  • Surface Area: SA = 2πr² + 2πrh

Cone:

  • Volume: V = (1/3)πr²h

Sphere:

  • Volume: V = (4/3)πr³
  • Surface Area: SA = 4πr²

Square Pyramid:

  • Volume: V = (1/3)s²h

Triangular Prism:

  • Volume: V = (1/2 × base × triangle height) × prism height

Problem-Solving Strategy

Step 1: Identify the 3D shape

Step 2: Determine what you're finding (volume or surface area)

Step 3: List what you know (dimensions)

Step 4: Write the appropriate formula

Step 5: Substitute values

Step 6: Calculate (show work!)

Step 7: Include correct units

Step 8: Check - does it make sense?


Composite 3D Figures

Sometimes shapes are combined!

Example: A building shaped like a rectangular prism with a square pyramid roof.

  • Prism: 10 m × 10 m × 20 m
  • Pyramid: base 10 m × 10 m, height 5 m

Total Volume: Prism: V₁ = 10 × 10 × 20 = 2,000 m³ Pyramid: V₂ = (1/3)(10²)(5) = 500/3 ≈ 166.67 m³ Total: 2,000 + 166.67 = 2,166.67 m³

Answer: About 2,167 cubic meters


When to Use Which Measurement?

Use Volume when:

  • Finding capacity (how much it holds)
  • Calculating amount of liquid, gas, or material
  • Determining weight if you know density
  • Example: How much water in a pool?

Use Surface Area when:

  • Finding amount of material to cover/wrap
  • Calculating paint needed
  • Determining cost based on outside area
  • Example: How much wrapping paper for a gift?

Real-World Careers Using These Skills

  • Architecture: Designing buildings, calculating materials
  • Engineering: Creating products, containers
  • Manufacturing: Packaging design
  • Construction: Estimating concrete, paint, materials
  • Science: Lab measurements, experiments
  • Cooking: Recipe scaling, container sizes

Summary

Volume measures space inside (cubic units)

  • How much it can hold
  • Prisms: Base Area × Height
  • Pyramids/Cones: (1/3) × Base Area × Height
  • Sphere: (4/3)πr³

Surface Area measures outside covering (square units)

  • How much material to wrap it
  • Add up all face areas
  • Rectangular prism: 2(lw + lh + wh)
  • Cylinder: 2πr² + 2πrh
  • Sphere: 4πr²

Key Skills:

  • Identify the 3D shape
  • Use correct formula
  • Keep units consistent
  • Include proper units in answer

Remember:

  • Volume = cubic units (cm³, in³, m³)
  • Surface Area = square units (cm², in², m²)
  • Radius = half the diameter
  • Cone/Pyramid volume = 1/3 of prism/cylinder

Understanding volume and surface area is essential for architecture, engineering, science, and countless real-world applications!

📚 Practice Problems

1Problem 1easy

❓ Question:

Find the volume of a rectangular prism with length 6 cm, width 4 cm, and height 5 cm.

💡 Show Solution

Use the formula: V = lwh

V = 6 × 4 × 5 V = 120 cm³

Answer: 120 cm³

2Problem 2easy

❓ Question:

Find the surface area of a cube with side length 3 inches.

💡 Show Solution

Use the formula: SA = 6s²

SA = 6 × (3²) SA = 6 × 9 SA = 54 in²

Answer: 54 in²

3Problem 3medium

❓ Question:

A cylinder has a radius of 4 cm and height of 10 cm. Find the volume. Use π ≈ 3.14.

💡 Show Solution

Use the formula: V = πr²h

V = 3.14 × (4²) × 10 V = 3.14 × 16 × 10 V = 3.14 × 160 V = 502.4 cm³

Answer: 502.4 cm³ (or about 502 cm³)

4Problem 4medium

❓ Question:

A rectangular box is 8 ft long, 5 ft wide, and 3 ft tall. How much cardboard is needed to make the box (surface area)?

💡 Show Solution

Use the formula: SA = 2(lw + lh + wh)

SA = 2(8×5 + 8×3 + 5×3) SA = 2(40 + 24 + 15) SA = 2(79) SA = 158 ft²

Answer: 158 ft²

5Problem 5hard

❓ Question:

A cone-shaped container has a radius of 6 inches and a height of 15 inches. How much liquid can it hold? Use π ≈ 3.14.

💡 Show Solution

Use the formula: V = (1/3)πr²h

V = (1/3) × 3.14 × (6²) × 15 V = (1/3) × 3.14 × 36 × 15 V = (1/3) × 3.14 × 540 V = (1/3) × 1,695.6 V = 565.2 in³

Answer: 565.2 in³ (or about 565 cubic inches)

Explain using:

📌 Related Topics in Geometry

❓ Frequently Asked Questions

What is Surface Area and Volume?▾
Calculate surface area and volume of 3D shapes
How can I study Surface Area and Volume effectively?▾
Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 5 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
Is this Surface Area and Volume study guide free?▾
Yes — all study notes, flashcards, and practice problems for Surface Area and Volume on Study Mondo are free to access. No account is needed.
What course covers Surface Area and Volume?▾
Surface Area and Volume is part of the Grade 7 Math course on Study Mondo, specifically in the Geometry section. You can explore the full course for more related topics and practice resources.
Are there practice problems for Surface Area and Volume?▾
Yes, this page includes 5 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.