Surface Area

Finding surface areas of 3D shapes

Surface Area

Rectangular Prism (Box)

SA=2lw+2lh+2whSA = 2lw + 2lh + 2wh

Or: SA=2(lw+lh+wh)SA = 2(lw + lh + wh)

Cube: SA=6s2SA = 6s^2

Cylinder

SA=2πr2+2πrhSA = 2\pi r^2 + 2\pi rh

  • 2πr22\pi r^2 = two circular bases
  • 2πrh2\pi rh = lateral (curved) surface

Lateral surface only: LA=2πrhLA = 2\pi rh

Sphere

SA=4πr2SA = 4\pi r^2

Memory aid: Same as dVdr\frac{dV}{dr} where V=43πr3V = \frac{4}{3}\pi r^3

Cone

SA=πr2+πrSA = \pi r^2 + \pi r\ell

where:

  • πr2\pi r^2 = circular base
  • πr\pi r\ell = lateral surface
  • \ell = slant height

To find slant height: =r2+h2\ell = \sqrt{r^2 + h^2} (Pythagorean theorem)

Pyramid

SA=B+12PSA = B + \frac{1}{2}P\ell

where:

  • BB = area of base
  • PP = perimeter of base
  • \ell = slant height

Strategy

  1. Identify all faces/surfaces
  2. Find area of each
  3. Add them up

📚 Practice Problems

1Problem 1easy

Question:

Find the surface area of a cube with side length 4.

💡 Show Solution

A cube has 6 congruent square faces.

SA=6s2SA = 6s^2

SA=6(4)2SA = 6(4)^2

SA=6(16)SA = 6(16)

SA=96SA = 96

Answer: 96 square units

2Problem 2medium

Question:

Find the surface area of a cylinder with radius 3 and height 8.

💡 Show Solution

Use SA=2πr2+2πrhSA = 2\pi r^2 + 2\pi rh:

SA=2π(3)2+2π(3)(8)SA = 2\pi(3)^2 + 2\pi(3)(8)

SA=2π(9)+2π(24)SA = 2\pi(9) + 2\pi(24)

SA=18π+48πSA = 18\pi + 48\pi

SA=66πSA = 66\pi

Answer: 66π66\pi (or approximately 207.3) square units

3Problem 3hard

Question:

A cone has radius 5 and height 12. Find the surface area.

💡 Show Solution

Step 1: Find slant height using Pythagorean theorem

=r2+h2\ell = \sqrt{r^2 + h^2} =52+122\ell = \sqrt{5^2 + 12^2} =25+144\ell = \sqrt{25 + 144} =169=13\ell = \sqrt{169} = 13

Step 2: Calculate surface area

SA=πr2+πrSA = \pi r^2 + \pi r\ell SA=π(5)2+π(5)(13)SA = \pi(5)^2 + \pi(5)(13) SA=25π+65πSA = 25\pi + 65\pi SA=90πSA = 90\pi

Answer: 90π90\pi (or approximately 282.7) square units