Sector Area and Arc Length

Finding areas and lengths of circle sectors

Sector Area and Arc Length

Sector

A sector is a "slice" of a circle, like a piece of pie.

It's bounded by two radii and an arc.

Arc Length

The length of the curved part of the sector.

Formula: L=θ360°×2πrL = \frac{\theta}{360°} \times 2\pi r

Or in radians: L=rθL = r\theta

Sector Area

The area of the "slice."

Formula: A=θ360°×πr2A = \frac{\theta}{360°} \times \pi r^2

Or in radians: A=12r2θA = \frac{1}{2}r^2\theta

Segment

The region between a chord and the arc it cuts off.

Area of segment = Area of sector - Area of triangle

Strategy

  1. Find the fraction of the circle: θ360°\frac{\theta}{360°}
  2. Multiply by the whole circle (circumference or area)

Common Sectors

  • Semicircle: θ=180°\theta = 180° → half circle
  • Quarter circle: θ=90°\theta = 90° → one-fourth circle

📚 Practice Problems

1Problem 1easy

Question:

Find the arc length of a sector with radius 6 and central angle 60°.

💡 Show Solution

Use the arc length formula: L=θ360°×2πrL = \frac{\theta}{360°} \times 2\pi r

L=60360×2π(6)L = \frac{60}{360} \times 2\pi(6)

L=16×12πL = \frac{1}{6} \times 12\pi

L=2πL = 2\pi

Answer: 2π2\pi (or approximately 6.28) units

2Problem 2medium

Question:

Find the area of a sector with radius 8 and central angle 135°.

💡 Show Solution

Use the sector area formula: A=θ360°×πr2A = \frac{\theta}{360°} \times \pi r^2

A=135360×π(8)2A = \frac{135}{360} \times \pi(8)^2

A=38×64πA = \frac{3}{8} \times 64\pi

A=24πA = 24\pi

Answer: 24π24\pi (or approximately 75.4) square units

3Problem 3hard

Question:

A sector has radius 10 and arc length 5π5\pi. Find the central angle and the area of the sector.

💡 Show Solution

Step 1: Find the central angle using arc length

L=θ360°×2πrL = \frac{\theta}{360°} \times 2\pi r

5π=θ360×2π(10)5\pi = \frac{\theta}{360} \times 2\pi(10)

5π=θ360×20π5\pi = \frac{\theta}{360} \times 20\pi

5=θ360×205 = \frac{\theta}{360} \times 20

5=20θ3605 = \frac{20\theta}{360}

θ=90°\theta = 90°

Step 2: Find the sector area

A=90360×π(10)2A = \frac{90}{360} \times \pi(10)^2

A=14×100π=25πA = \frac{1}{4} \times 100\pi = 25\pi

Answer: Central angle = 90°90°, Area = 25π25\pi square units