Geometry Basics

Master area, perimeter, and volume formulas for common shapes, understand angle relationships, and solve problems involving geometric properties.

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📚 Practice Problems

1Problem 1easy

Question:

A rectangle has a length of 12 and a width of 5. What is its perimeter and area?

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Perimeter: P=2l+2w=2(12)+2(5)=24+10=34P = 2l + 2w = 2(12) + 2(5) = 24 + 10 = 34

Area: A=lw=12×5=60A = lw = 12 \times 5 = 60

Answer: Perimeter = 34, Area = 60

2Problem 2medium

Question:

Two parallel lines are cut by a transversal. One of the angles formed is 115°. What are the measures of all eight angles?

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When parallel lines are cut by a transversal, we get two types of angles:

The angle of 115° and its vertical angle are both 115°. The supplementary angles are 180°115°=65°180° - 115° = 65°.

All eight angles are either 115° or 65°:

  • Four angles of 115° (the angle, its vertical angle, and corresponding angles)
  • Four angles of 65° (supplementary to the 115° angles)

Answer: Four angles are 115° and four are 65°.

Key relationships used: vertical angles, corresponding angles, supplementary angles.

3Problem 3medium

Question:

A rectangular box has dimensions 3 × 4 × 12. What is the length of the longest diagonal inside the box?

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3D diagonal formula: d=l2+w2+h2d = \sqrt{l^2 + w^2 + h^2}

d=32+42+122=9+16+144=169=13d = \sqrt{3^2 + 4^2 + 12^2} = \sqrt{9 + 16 + 144} = \sqrt{169} = 13

Answer: The space diagonal is 13.

Alternatively: First find the diagonal of the base: 32+42=5\sqrt{3^2 + 4^2} = 5 (3-4-5 triple), then use that with the height: 52+122=169=13\sqrt{5^2 + 12^2} = \sqrt{169} = 13 (5-12-13 triple).

4Problem 4hard

Question:

The volume of a cylinder is 100π100\pi cubic cm and its height is 4 cm. What is the total surface area?

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Step 1: Find the radius using the volume formula: V=πr2hV = \pi r^2 h 100π=πr2(4)100\pi = \pi r^2 (4) r2=25r^2 = 25 r=5 cmr = 5 \text{ cm}

Step 2: Calculate total surface area (two circles + lateral surface): SA=2πr2+2πrhSA = 2\pi r^2 + 2\pi rh =2π(25)+2π(5)(4)= 2\pi(25) + 2\pi(5)(4) =50π+40π= 50\pi + 40\pi =90π282.74 cm2= 90\pi \approx 282.74 \text{ cm}^2

Answer: 90π90\pi cm² (approximately 282.74 cm²)

5Problem 5expert

Question:

Two similar triangles have corresponding sides in the ratio 3:53:5. If the area of the smaller triangle is 27 cm², what is the area of the larger triangle?

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Key property of similar figures: If corresponding sides have ratio kk, then areas have ratio k2k^2.

Side ratio: 35\frac{3}{5}

Area ratio: (35)2=925\left(\frac{3}{5}\right)^2 = \frac{9}{25}

27Alarge=925\frac{27}{A_{\text{large}}} = \frac{9}{25} Alarge=27×259=75 cm2A_{\text{large}} = \frac{27 \times 25}{9} = 75 \text{ cm}^2

Answer: 75 cm²

Remember: Side ratio = kk, Area ratio = k2k^2, Volume ratio = k3k^3.