Functions

Master function notation, evaluation, and transformations for SAT

Functions (SAT Math)

What is a Function?

A function is a relationship where each input has exactly ONE output.

Think of it like a machine:

  • You put in a number (input xx)
  • The function processes it
  • You get a result (output yy or f(x)f(x))

Function Notation

f(x)=2x+3f(x) = 2x + 3 means:

  • Function name: ff
  • Input variable: xx
  • Rule: Multiply input by 2, then add 3

Example evaluations:

  • f(5)=2(5)+3=13f(5) = 2(5) + 3 = 13
  • f(0)=2(0)+3=3f(0) = 2(0) + 3 = 3
  • f(2)=2(2)+3=1f(-2) = 2(-2) + 3 = -1

Domain and Range

Domain (inputs)

All possible xx-values that can be used in a function

Common restrictions:

  • Cannot divide by zero
  • Cannot take square root of negative (in real numbers)
  • Explicit restrictions stated in problem

Example 1: f(x)=1x3f(x) = \frac{1}{x-3}

Domain: All real numbers EXCEPT x=3x = 3 (would make denominator zero)

Example 2: f(x)=x+5f(x) = \sqrt{x + 5}

Domain: x+50x + 5 \geq 0, so x5x \geq -5

Range (outputs)

All possible yy-values the function can produce

Example: f(x)=x2f(x) = x^2

  • Domain: All real numbers
  • Range: y0y \geq 0 (squares are never negative)

Example: f(x)=x2+4f(x) = -x^2 + 4

  • Domain: All real numbers
  • Range: y4y \leq 4 (parabola opens down, vertex at y=4y = 4)

Evaluating Functions

Direct Substitution

Given: f(x)=x23x+2f(x) = x^2 - 3x + 2, find f(4)f(4)

Solution: f(4)=(4)23(4)+2=1612+2=6f(4) = (4)^2 - 3(4) + 2 = 16 - 12 + 2 = 6

Substituting Expressions

Given: f(x)=x23x+2f(x) = x^2 - 3x + 2, find f(a+1)f(a + 1)

Solution: f(a+1)=(a+1)23(a+1)+2f(a+1) = (a+1)^2 - 3(a+1) + 2 =a2+2a+13a3+2= a^2 + 2a + 1 - 3a - 3 + 2 =a2a= a^2 - a

Key: Replace EVERY xx with (a+1)(a+1)

Composite Functions

Notation: (fg)(x)=f(g(x))(f \circ g)(x) = f(g(x))

"ff composed with gg" means: do gg first, then do ff to the result

Example

Given: f(x)=2x+1f(x) = 2x + 1 and g(x)=x2g(x) = x^2

Find f(g(3))f(g(3)):

Step 1: Find g(3)g(3)
g(3)=32=9g(3) = 3^2 = 9

Step 2: Find f(9)f(9)
f(9)=2(9)+1=19f(9) = 2(9) + 1 = 19

Therefore: f(g(3))=19f(g(3)) = 19

Order Matters!

Find g(f(3))g(f(3)):

Step 1: Find f(3)f(3)
f(3)=2(3)+1=7f(3) = 2(3) + 1 = 7

Step 2: Find g(7)g(7)
g(7)=72=49g(7) = 7^2 = 49

Therefore: g(f(3))=49f(g(3))g(f(3)) = 49 \neq f(g(3))

Important: f(g(x))g(f(x))f(g(x)) \neq g(f(x)) in general!

Interpreting Function Graphs

Reading Values from Graphs

To find f(3)f(3):

  1. Find x=3x = 3 on horizontal axis
  2. Go up/down to the curve
  3. Read the yy-value

To find when f(x)=5f(x) = 5:

  1. Find y=5y = 5 on vertical axis
  2. Go left/right to the curve
  3. Read all xx-values where curve crosses y=5y = 5

Key Features

x-intercepts (zeros): Where graph crosses x-axis
f(x)=0f(x) = 0

y-intercept: Where graph crosses y-axis
f(0)f(0)

Maximum: Highest point (vertex of downward parabola)

Minimum: Lowest point (vertex of upward parabola)

Increasing: Graph goes up as you move right
Decreasing: Graph goes down as you move right

Function Transformations

Vertical Shifts

f(x)+kf(x) + k: Shift UP by kk units
f(x)kf(x) - k: Shift DOWN by kk units

Example: If f(x)=x2f(x) = x^2, then:

  • f(x)+3=x2+3f(x) + 3 = x^2 + 3 shifts parabola up 3 units

Horizontal Shifts

f(xh)f(x - h): Shift RIGHT by hh units (opposite of what you'd think!)
f(x+h)f(x + h): Shift LEFT by hh units

Example: If f(x)=x2f(x) = x^2, then:

  • f(x2)=(x2)2f(x - 2) = (x-2)^2 shifts parabola right 2 units

Reflections

f(x)-f(x): Reflect over x-axis (flip upside down)
f(x)f(-x): Reflect over y-axis (flip left-right)

Stretches

af(x)a \cdot f(x) where a>1a > 1: Vertical stretch (taller)
af(x)a \cdot f(x) where 0<a<10 < a < 1: Vertical compression (shorter)

Word Problems with Functions

Example: Cost Function

A gym charges a 50membershipfeeplus50 membership fee plus 30 per month.

Function: C(m)=50+30mC(m) = 50 + 30m

  • CC = total cost
  • mm = number of months

Questions:

  • C(6)=50+30(6)=230C(6) = 50 + 30(6) = 230 → Cost for 6 months
  • If C(m)=200C(m) = 200, solve: 50+30m=20050 + 30m = 200m=5m = 5 months

Example: Distance Function

A car travels at 60 mph for tt hours.

Function: d(t)=60td(t) = 60t

Questions:

  • d(3)=60(3)=180d(3) = 60(3) = 180 → Distance after 3 hours
  • If d(t)=240d(t) = 240, solve: 60t=24060t = 240t=4t = 4 hours

SAT Question Types

Type 1: Evaluate f(a)f(a)

Strategy: Substitute aa for every xx and simplify

Type 2: Solve f(x)=kf(x) = k

Strategy: Set function equal to kk and solve for xx

Example: If f(x)=2x7f(x) = 2x - 7 and f(x)=11f(x) = 11: 2x7=112x - 7 = 11 2x=182x = 18 x=9x = 9

Type 3: Find f(g(x))f(g(x)) or g(f(x))g(f(x))

Strategy: Work from inside out

Type 4: Interpret Graphs

Strategy:

  • Trace with your finger
  • Check xx-value → yy-value
  • Verify answer makes sense

Type 5: Domain/Range from Graph or Equation

Strategy:

  • Domain: Look at xx-values covered
  • Range: Look at yy-values achieved
  • Check for restrictions (division by zero, square roots)

Common Mistakes

Confusing f(x+2)f(x+2) with f(x)+2f(x) + 2

  • f(x+2)f(x+2) shifts graph LEFT 2
  • f(x)+2f(x) + 2 shifts graph UP 2

Wrong order in composition

  • f(g(x))f(g(x)) means do gg FIRST
  • Not the same as g(f(x))g(f(x))!

Not using parentheses

  • f(3+1)=f(4)f(3+1) = f(4), not f(3)+1f(3) + 1

Forgetting domain restrictions

  • 1x\frac{1}{x} has no value at x=0x = 0

Misreading graphs

  • Check which axis is which
  • Verify scale (not always by 1's)

Quick Tips for SAT

Function notation is just substitution — replace xx with whatever is in parentheses
Graphs tell you everything — use them to find values quickly
Order matters in composition — inside function first, outside function second
Domain = possible inputs → check what xx CAN'T be
Range = possible outputs → check what yy values are achieved
Transformations stack — multiple shifts/stretches apply in sequence

Practice Approach

  1. Identify function type (linear, quadratic, etc.)
  2. Check what's being asked (evaluate, solve, compose, transform)
  3. Use appropriate strategy
  4. Double-check your substitution (most common error)
  5. Verify answer makes sense (domain/range, reasonableness)

📚 Practice Problems

1Problem 1easy

Question:

If f(x)=3x4f(x) = 3x - 4, what is f(6)f(6)?

💡 Show Solution

Solution:

Substitute x=6x = 6: f(6)=3(6)4f(6) = 3(6) - 4 f(6)=184f(6) = 18 - 4 f(6)=14f(6) = 14

Answer: 1414

2Problem 2medium

Question:

If g(x)=x2+2xg(x) = x^2 + 2x, what is g(3)g(-3)?

💡 Show Solution

Solution:

Substitute x=3x = -3: g(3)=(3)2+2(3)g(-3) = (-3)^2 + 2(-3) g(3)=96g(-3) = 9 - 6 g(3)=3g(-3) = 3

Answer: 33

SAT Tip: Be careful with negatives! (3)2=9(-3)^2 = 9

3Problem 3hard

Question:

If h(x)=2x+5h(x) = 2x + 5 and h(a)=17h(a) = 17, what is the value of aa?

💡 Show Solution

Solution:

Set up the equation: h(a)=17h(a) = 17 2a+5=172a + 5 = 17

Solve: 2a=122a = 12 a=6a = 6

Answer: a=6a = 6

Check: h(6)=2(6)+5=17h(6) = 2(6) + 5 = 17