Exponential Functions
Master exponential growth and decay, interpret exponential expressions, solve exponential equations, and model real-world phenomena with exponential functions.
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Exponential Functions and Equations on the SAT
What Is an Exponential Function?
An exponential function has the form:
Where:
- = initial value (when )
- = base (growth/decay factor)
- = typically time or number of periods
Growth vs. Decay
| Condition | Type | Example | |---|---|---| | | Exponential Growth | Population doubling | | | Exponential Decay | Radioactive decay | | | No change (constant) | โ |
Growth Rate and Decay Rate
If value increases by per period:
If value decreases by per period:
Example: A car worth $25,000 depreciates by 15% per year:
Identifying Exponential Functions
| Feature | Linear | Exponential | |---|---|---| | Pattern | Add a constant | Multiply by a constant | | Equation | | | | Rate of change | Constant | Changes (accelerating) | | Graph | Straight line | Curved |
From a Table
| | (Linear) | (Exponential) | |---|---|---| | 0 | 5 | 5 | | 1 | 8 | 10 | | 2 | 11 | 20 | | 3 | 14 | 40 |
Linear: each time. Exponential: each time.
Compound Interest
| Variable | Meaning | |---|---| | | Final amount | | | Principal (initial) | | | Annual interest rate (decimal) | | | Times compounded per year | | | Time in years |
Special case โ continuous compounding:
Half-Life and Doubling Time
Half-life: where is the half-life
Doubling time: where is the doubling time
SAT Question Types
Type 1: Interpret the Function
"In , what does the 500 represent? What does 1.03 represent?"
- 500 = initial value
- 1.03 = 3% growth per period ()
Type 2: Growth/Decay Identification
"Does represent growth or decay, and by what percent?"
- Decay (because )
- Rate = decay per period
Type 3: Evaluate at a Specific Time
"If , what is ?"
Type 4: Compound Interest
"$5,000 at 4% annual interest compounded quarterly for 3 years"
Common SAT Mistakes
- Confusing growth rate with growth factor: 5% growth has factor , not
- Forgetting the initial value: , the initial value is the coefficient
- Using the wrong formula for compounding: Check what is (monthly = 12, quarterly = 4, etc.)
- Confusing linear and exponential โ check if the table adds or multiplies
- Not recognizing half-life pattern: Multiply by each half-life period
๐ Practice Problems
1Problem 1easy
โ Question:
A bacteria colony starts with 100 bacteria and doubles every hour. Write a function for the population after hours, and find the population after 5 hours.
๐ก Show Solution
Step 1: Identify the components:
- Initial value:
- Growth factor: (doubling)
Function:
Step 2: Find :
Answer: ; after 5 hours there are 3,200 bacteria.
2Problem 2medium
โ Question:
The value of a car is modeled by , where is in years. What is the annual depreciation rate, and what will the car be worth after 3 years?
๐ก Show Solution
Step 1: Identify the decay rate. The base is , so:
The car depreciates by 18% per year.
Step 2: Find :
Answer: 18% annual depreciation; worth approximately $16,541 after 3 years.
3Problem 3medium
โ Question:
Which function represents a quantity that increases by 7% each month?
A) B) C) D)
๐ก Show Solution
Key: "Increases by 7% each month" means growth rate .
The growth factor is .
A) โ this is 600% growth, not 7% โ B) โ this is 70% growth, not 7% โ C) โ this is decay (and extreme decay at that) โ D) โ this is 7% growth โ
Answer: D)
Common mistake: Using or as the base instead of .
4Problem 4hard
โ Question:
$2,000 is invested at 6% annual interest, compounded monthly. What is the value after 5 years?
๐ก Show Solution
Formula:
Values:
- (principal)
- (6% as decimal)
- (monthly compounding)
- (years)
Step 1: Substitute:
Step 2: Calculate:
Answer: Approximately $2,697.70
SAT Tip: Make sure to identify correctly: monthly = 12, quarterly = 4, semiannually = 2, annually = 1.
5Problem 5expert
โ Question:
A radioactive substance has a half-life of 8 days. If you start with 500 grams, how much remains after 20 days?
๐ก Show Solution
Half-life formula:
Values:
- grams
- days (half-life)
- days
Substitute:
Calculate:
Answer: Approximately 88.4 grams
Quick check: After 8 days: 250g. After 16 days: 125g. After 24 days: 62.5g. So after 20 days (between 16 and 24), the answer should be between 62.5 and 125. โ