Circles and Arc Measures

Circle properties, equations, arc length, and sector area

Circles and Arc Measures (SAT)

Circle Basics

Key Components

  • Center: Point equidistant from all points on circle
  • Radius (rr): Distance from center to any point on circle
  • Diameter (dd): Distance across circle through center (d=2rd = 2r)
  • Chord: Line segment connecting two points on circle
  • Tangent: Line touching circle at exactly one point

Circumference (Perimeter)

C=2πr=πdC = 2\pi r = \pi d

Example: If r=5r = 5, then C=2π(5)=10πC = 2\pi(5) = 10\pi

Area

A=πr2A = \pi r^2

Example: If r=3r = 3, then A=π(3)2=9πA = \pi(3)^2 = 9\pi

Circle Equations

Standard Form

(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2

  • Center: (h,k)(h, k)
  • Radius: rr

Example: (x2)2+(y+3)2=25(x - 2)^2 + (y + 3)^2 = 25

  • Center: (2,3)(2, -3)
  • Radius: 25=5\sqrt{25} = 5

Finding Center and Radius

Given equation, identify hh, kk, and rr

Watch out for signs!

  • (x2)(x - 2) means h=+2h = +2
  • (y+3)(y + 3) means k=3k = -3

Arcs and Sectors

Arc Length

Fraction of circumference

Arc length=θ360°×2πr\text{Arc length} = \frac{\theta}{360°} \times 2\pi r

Where θ\theta is the central angle in degrees

Example: r=6r = 6, θ=60°\theta = 60° Arc length=60360×2π(6)=16×12π=2π\text{Arc length} = \frac{60}{360} \times 2\pi(6) = \frac{1}{6} \times 12\pi = 2\pi

Sector Area

Fraction of circle area

Sector area=θ360°×πr2\text{Sector area} = \frac{\theta}{360°} \times \pi r^2

Example: r=6r = 6, θ=60°\theta = 60° Sector area=60360×π(6)2=16×36π=6π\text{Sector area} = \frac{60}{360} \times \pi(6)^2 = \frac{1}{6} \times 36\pi = 6\pi

Angles in Circles

Central Angle

Vertex at center of circle

  • Measure = arc it intercepts

Inscribed Angle

Vertex on circle

  • Measure = half the arc it intercepts

Inscribed Angle Theorem: Inscribed angle=12×central angle\text{Inscribed angle} = \frac{1}{2} \times \text{central angle}

Angle in Semicircle

Any angle inscribed in a semicircle is a right angle (90°90°)

Tangent Lines

Properties:

  1. Tangent ⊥ radius at point of tangency
  2. Two tangents from external point have equal length

Power of a Point

For tangent from external point:

If tangent has length tt and point is distance dd from center with radius rr: t2=d2r2t^2 = d^2 - r^2

(This is Pythagorean theorem!)

Circle Problems on SAT

Type 1: Find Area or Circumference

Given radius or diameter, apply formulas

Type 2: Arc Length and Sector Area

Use fraction of circle based on angle

Type 3: Equation of Circle

Identify center and radius from standard form

Type 4: Inscribed Angles

Remember: inscribed angle = ½ central angle

Type 5: Tangent Lines

Use perpendicularity and Pythagorean theorem

SAT Strategies

Leave in Terms of π

Unless told to approximate, leave π in answer

Example: Area = 25π25\pi (not 78.5)

Check Units

Radius vs diameter - easy to confuse!

Use Fractions for Arcs

Arc = fraction × whole circle

60°360°=16\frac{60°}{360°} = \frac{1}{6} of circle

Draw Radii

Creates right triangles with tangents!

Memorize Formulas

  • Circumference: C=2πrC = 2\pi r
  • Area: A=πr2A = \pi r^2
  • Standard form: (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2

Common SAT Traps

Trap 1: Radius vs Diameter

Area given diameter 10:

  • Wrong: A=π(10)2=100πA = \pi(10)^2 = 100\pi
  • Right: r=5r = 5, so A=π(5)2=25πA = \pi(5)^2 = 25\pi

Trap 2: Sign Errors in Equation

(x+3)2(x + 3)^2 means center is at x=3x = -3 (not +3+3)

Trap 3: Central vs Inscribed Angle

Inscribed = ½ central

Trap 4: Forgetting to Square Radius

Area = πr2\pi r^2 not πr\pi r

Trap 5: Arc vs Sector

Arc length = distance along edge Sector area = area of "pizza slice"

SAT Tips

  • Circumference: 2πr2\pi r or πd\pi d
  • Area: πr2\pi r^2 (square the radius!)
  • Arc length: Fraction of circumference
  • Sector area: Fraction of total area
  • Inscribed angle = ½ central angle
  • Tangent ⊥ radius at point of contact
  • Leave answers in terms of π\pi unless told otherwise
  • Standard form: (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2 with center (h,k)(h,k)

📚 Practice Problems

1Problem 1easy

Question:

A circle has a diameter of 12. What is its area?

💡 Show Solution

Solution:

Given: Diameter = 12 Find radius: r=d2=122=6r = \frac{d}{2} = \frac{12}{2} = 6

Area formula: A=πr2A = \pi r^2 A=π(6)2=36πA = \pi(6)^2 = 36\pi

Answer: 36π36\pi

SAT Tip: Always convert diameter to radius first! Area uses radius, not diameter.

2Problem 2medium

Question:

What is the center and radius of the circle (x4)2+(y+1)2=9(x - 4)^2 + (y + 1)^2 = 9?

💡 Show Solution

Solution:

Standard form: (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2

Compare to given equation: (x4)2+(y(1))2=32(x - 4)^2 + (y - (-1))^2 = 3^2

Center: (h,k)=(4,1)(h, k) = (4, -1) Radius: r=9=3r = \sqrt{9} = 3

Answer: Center: (4,1)(4, -1), Radius: 33

SAT Tip: Watch the signs! (y+1)(y + 1) means k=1k = -1, not +1+1

3Problem 3hard

Question:

A circle has radius 9. A sector of this circle has a central angle of 40°40°. What is the area of the sector?

💡 Show Solution

Solution:

Sector area = (fraction of circle) × (total area)

Fraction: 40°360°=40360=19\frac{40°}{360°} = \frac{40}{360} = \frac{1}{9}

Total area: A=πr2=π(9)2=81πA = \pi r^2 = \pi(9)^2 = 81\pi

Sector area: 19×81π=9π\frac{1}{9} \times 81\pi = 9\pi

Answer: 9π9\pi

SAT Tip: Sector = "pizza slice." Find what fraction of the whole circle it is!