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Sampling Distributions

Understand sampling distributions and the variability of sample statistics.

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📊 Sampling Distributions

What is a Sampling Distribution?

A sampling distribution is the probability distribution of a sample statistic (like xˉ\bar{x} or p^\hat{p}) calculated from all possible samples of the same size drawn from a population.

Key Insight: If you repeatedly take samples of size n and calculate the statistic each time, the results vary. That variation follows a sampling distribution.

Distribution of Sample Proportion p^\hat{p}

For a sample proportion p^\hat{p}:

Mean of the sampling distribution: μp^=p\mu_{\hat{p}} = p

The sample proportion centers on the true population proportion.

Standard Error (SE) of p^\hat{p}: SE(p^)=p(1−p)nSE(\hat{p}) = \sqrt{\frac{p(1-p)}{n}}

Conditions for approximation by normal distribution:

  • np≥10np \geq 10 (at least 10 successes)
  • n(1−p)≥10n(1-p) \geq 10 (at least 10 failures)
  • Sample is random
  • 10% rule: n ≤ 0.10N (sample ≤ 10% of population)

Distribution of Sample Mean xˉ\bar{x}

For a sample mean xˉ\bar{x}:

Mean of the sampling distribution: μxˉ=μ\mu_{\bar{x}} = \mu

The sample mean centers on the true population mean.

Standard Error (SE) of xˉ\bar{x}: SE(xˉ)=σnSE(\bar{x}) = \frac{\sigma}{\sqrt{n}}

where σ is the population standard deviation.

Conditions for approximation by normal distribution:

  • If population is normal: any sample size works
  • If population shape unknown: n ≥ 30 (Central Limit Theorem)
  • Sample is random
  • 10% rule: n ≤ 0.10N

Key Properties of Sampling Distributions

  1. Center: Both p^\hat{p} and xˉ\bar{x} are unbiased (centered on true parameter)
  2. Spread: SE decreases as n increases; larger samples give less variable statistics
  3. Shape: Approximately normal under appropriate conditions
  4. Variability formula: SE depends on population variability and sample size

Worked Example

Suppose 40% of customers prefer Brand A. You take a random sample of 100 customers.

For p^\hat{p}:

  • μp^=0.40\mu_{\hat{p}} = 0.40
  • SE(p^)=0.40⋅0.60100=0.24100=0.0024=0.049SE(\hat{p}) = \sqrt{\frac{0.40 \cdot 0.60}{100}} = \sqrt{\frac{0.24}{100}} = \sqrt{0.0024} = 0.049
  • Check conditions: np = 40 ≥ 10 ✓, n(1−p) = 60 ≥ 10 ✓

The sampling distribution of p^\hat{p} is approximately N(0.40,0.0492)N(0.40, 0.049^2).

Common Mistakes

  1. Confusing SE with standard deviation: SE is smaller than σ because of the n\sqrt{n} in denominator
  2. Forgetting conditions: Always verify the sample size conditions before using normal approximation
  3. Not recognizing center: Sample statistics are unbiased; they center on the true parameter

AP Exam Tip

Sampling distribution questions require you to identify whether you're working with xˉ\bar{x} or p^\hat{p}, then apply correct formula. Know the SE formulas and always check conditions. If conditions fail, state the issue rather than proceeding with the normal approximation.

📚 Practice Problems

1Problem 1easy

❓ Question:

What is the mean of the sampling distribution of the sample mean?

💡 Show Solution

The mean of the sampling distribution of the sample mean equals the population mean μ\mu. This is true regardless of sample size, making the sample mean an unbiased estimator of the population parameter. If the population mean is 50, then all sample means taken from this population will have an expected value of 50.

2Problem 2medium

❓ Question:

A population has standard deviation σ=12\sigma = 12. How does the standard error change when sample size increases from n=25n = 25 to n=100n = 100?

💡 Show Solution

The standard error is SE=σ/nSE = \sigma / \sqrt{n}. At n=25n = 25: SE=12/25=12/5=2.4SE = 12 / \sqrt{25} = 12 / 5 = 2.4. At n=100n = 100: SE=12/10=12/10=1.2SE = 12 / \sqrt{10} = 12 / 10 = 1.2. The standard error decreases by half when nn quadruples. Larger samples produce less variability in sample means, making the sampling distribution more concentrated around the population mean.

3Problem 3hard

❓ Question:

Two researchers sample from the same population of test scores (μ=75\mu = 75, σ=8\sigma = 8). Researcher A uses n=36n = 36 while Researcher B uses n=100n = 100. Which sampling distribution has the smaller spread? Explain why this matters for inference.

💡 Show Solution

Researcher B's sampling distribution has smaller spread because standard error SE=σ/nSE = \sigma / \sqrt{n} decreases as nn increases. For A: SE=8/6=1.33SE = 8 / 6 = 1.33. For B: SE=8/10=0.8SE = 8 / 10 = 0.8. Smaller spread means Researcher B's sample means vary less around μ=75\mu = 75, producing more precise estimates. This is why larger samples are preferred—they reduce sampling variability and make confidence intervals narrower.

Explain using:

⚠️ Common Mistakes: Sampling Distributions

Avoid these 3 frequent errors

📌 Related Topics in Unit 5: Sampling Distributions

❓ Frequently Asked Questions

What is Sampling Distributions?▾
Understand sampling distributions and the variability of sample statistics.
How can I study Sampling Distributions effectively?▾
Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 3 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
Is this Sampling Distributions study guide free?▾
Yes — all study notes, flashcards, and practice problems for Sampling Distributions on Study Mondo are free to access. No account is needed.
What course covers Sampling Distributions?▾
Sampling Distributions is part of the AP Statistics course on Study Mondo, specifically in the Unit 5: Sampling Distributions section. You can explore the full course for more related topics and practice resources.
Are there practice problems for Sampling Distributions?▾
Yes, this page includes 3 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.