Rotational Kinematics
Angular displacement, velocity, acceleration, and rotational kinematic equations
🌀 Rotational Kinematics
Angular Quantities
Just as linear motion has position, velocity, and acceleration, rotational motion has corresponding angular quantities.
Angular Position
Angle of rotation from reference line:
- Units: radians (rad)
- rad = 360° = one full rotation
- Conversion:
Angular Displacement
Change in angular position:
Units: radians (rad)
Positive: counterclockwise rotation Negative: clockwise rotation
Angular Velocity
Rate of change of angular position:
Average:
Instantaneous:
Units: rad/s (radians per second)
Angular Acceleration
Rate of change of angular velocity:
Average:
Instantaneous:
Units: rad/s² (radians per second squared)
Analogy with Linear Motion
| Linear Motion | Rotational Motion | |---------------|-------------------| | Position | Angular position | | Velocity | Angular velocity | | Acceleration | Angular acceleration | | Mass | Moment of inertia | | Force | Torque |
Relationship Between Linear and Angular
For a point at distance from axis of rotation:
Arc Length
(where is in radians)
Linear Velocity
Tangential velocity - velocity tangent to circular path
Tangential Acceleration
Component of acceleration tangent to circle (changes speed)
Centripetal Acceleration
Component of acceleration toward center (changes direction)
Rotational Kinematic Equations
For constant angular acceleration :
The Big Four Equations
1. Angular velocity:
2. Angular displacement:
3. Velocity-displacement:
4. Average velocity:
💡 These are EXACTLY analogous to linear kinematic equations! Just replace , , .
Comparison: Linear vs. Rotational Kinematics
| Linear (constant ) | Rotational (constant ) | |----------------------|--------------------------------| | | | | | | | | | | | |
Period and Frequency
For uniform circular motion (constant ):
Period
Time for one complete rotation:
Units: seconds
Frequency
Rotations per second:
Units: Hz (hertz) = rev/s
Relationships
Rolling Motion
For an object rolling without slipping:
Constraint condition:
where:
- = velocity of center of mass
- = radius
- = angular velocity
No slipping means:
- Point of contact is instantaneously at rest
- Distance traveled = arc length:
Problem-Solving Strategy
For Rotational Kinematics:
- Identify knowns: , , , , ,
- Identify unknown: What are you solving for?
- Choose equation: Pick the one with known quantities and unknown
- Solve algebraically
- Check units: Should be rad, rad/s, or rad/s²
- Check reasonableness: Does answer make sense?
Tip: If you know linear quantities (, , ), convert using:
⚠️ Common Mistakes
Mistake 1: Degrees vs. Radians
MUST use radians in equations! Convert degrees to radians first.
Mistake 2: Confusing and
- : tangential (changes speed)
- : centripetal (changes direction)
- Total:
Mistake 3: Wrong Sign for
- Speeding up in positive direction:
- Slowing down in positive direction:
Mistake 4: Forgetting Initial Conditions
and are not always zero!
Special Cases
Starting from Rest
:
Uniform Rotation
(constant ):
- Period:
Coming to Rest
:
- →
- →
Applications
Wheels and Gears
- Angular velocity determines linear speed
- Gear ratios change angular velocities
- connects the two
Rotating Machinery
- Turbines, engines, motors
- Angular acceleration during startup
- Constant during normal operation
Sports
- Figure skating spins (angular velocity)
- Gymnastics rotations
- Diving somersaults
Astronomy
- Planetary rotation (Earth: hr)
- Orbital motion
- Galaxy rotation
Key Formulas Summary
| Quantity | Formula | Units | |----------|---------|-------| | Angular velocity | | rad/s | | Angular acceleration | | rad/s² | | Linear velocity | | m/s | | Tangential acceleration | | m/s² | | Centripetal acceleration | | m/s² | | Period | | s | | Frequency | | Hz |
Kinematic equations (constant ):
📚 Practice Problems
1Problem 1easy
❓ Question:
A wheel starts from rest and accelerates uniformly at 2 rad/s² for 5 seconds. Find: (a) the final angular velocity, (b) the angular displacement during this time, and (c) the number of revolutions completed.
💡 Show Solution
Given Information:
- Initial angular velocity: rad/s (starts from rest)
- Angular acceleration: rad/s²
- Time: s
(a) Find final angular velocity
Step 1: Use first kinematic equation
Answer (a): Final angular velocity = 10 rad/s
(b) Find angular displacement
Step 2: Use displacement equation
Alternative: Use average velocity
Both methods agree! ✓
Answer (b): Angular displacement = 25 rad
(c) Find number of revolutions
Step 3: Convert radians to revolutions
Answer (c): Number of revolutions ≈ 4.0 revolutions
Summary: The wheel accelerates from rest to 10 rad/s, turning through 25 radians (about 4 complete rotations) in 5 seconds.
2Problem 2medium
❓ Question:
A wheel starts from rest and accelerates uniformly to 120 rpm in 8.0 seconds. (a) What is the angular acceleration in rad/s²? (b) How many revolutions does it make during this time? (c) What is the final angular velocity in rad/s?
💡 Show Solution
Solution:
Given: ω₀ = 0, ω_f = 120 rpm, t = 8.0 s
(a) Angular acceleration: Convert to rad/s: ω_f = 120 rev/min × (2π rad/rev) × (1 min/60 s) = 4π rad/s
α = (ω_f - ω₀)/t = (4π - 0)/8.0 = 1.57 rad/s² or π/2 rad/s²
(b) Number of revolutions: θ = ω₀t + ½αt² = 0 + ½(π/2)(8.0)² θ = ½(π/2)(64) = 16π rad
Convert to revolutions: 16π rad × (1 rev/2π rad) = 8.0 rev
(c) Final angular velocity: ω_f = 4π = 12.6 rad/s
Or 120 rpm as given.
3Problem 3medium
❓ Question:
A car tire with radius 0.3 m is rotating at 10 rev/s. The car brakes, and the tire comes to rest in 4 seconds with constant angular acceleration. Find: (a) the angular acceleration, and (b) the linear distance traveled during braking.
💡 Show Solution
Given Information:
- Radius: m
- Initial angular velocity: rev/s
- Final angular velocity: rad/s (comes to rest)
- Time: s
Step 0: Convert units
(a) Find angular acceleration
Step 1: Use first kinematic equation
Answer (a): Angular acceleration = −15.7 rad/s² (negative because it's slowing down)
(b) Find linear distance traveled
Step 2: Find angular displacement
Alternative: Use average velocity
Both methods agree! ✓
Step 3: Convert to linear distance
Answer (b): Linear distance traveled = 37.7 m (about 38 meters)
Check: This is reasonable for a car braking from moderate speed over 4 seconds.
Note: Number of revolutions = revolutions during braking.
4Problem 4medium
❓ Question:
A merry-go-round with radius 2.0 m rotates at 0.50 rev/s. A child stands at the outer edge. (a) What is the child's angular velocity? (b) What is the child's tangential (linear) speed? (c) What is the child's centripetal acceleration?
💡 Show Solution
Solution:
Given: r = 2.0 m, f = 0.50 rev/s
(a) Angular velocity: ω = 2πf = 2π(0.50) = π rad/s or 3.14 rad/s
(b) Tangential speed: v = rω = 2.0(π) = 2π m/s or 6.28 m/s
(c) Centripetal acceleration: a_c = v²/r = (2π)²/2.0 = 4π²/2.0 = 19.7 m/s²
Or: a_c = rω² = 2.0(π)² = 2π² = 19.7 m/s² ✓
5Problem 5hard
❓ Question:
A disk of radius 0.5 m starts from rest and rotates with constant angular acceleration. After 10 seconds, a point on the rim of the disk has a tangential speed of 15 m/s. Find: (a) the angular acceleration, (b) the angular displacement in those 10 seconds, and (c) the magnitude of the total acceleration of a point on the rim at t = 10 s.
💡 Show Solution
Given Information:
- Radius: m
- Initial angular velocity: rad/s (starts from rest)
- Time: s
- Final tangential speed: m/s
(a) Find angular acceleration
Step 1: Find final angular velocity
Step 2: Calculate angular acceleration
Answer (a): Angular acceleration = 3 rad/s²
(b) Find angular displacement
Step 3: Use displacement equation
Alternative: Use average velocity
Answer (b): Angular displacement = 150 rad
(This is revolutions)
(c) Find total acceleration at t = 10 s
Step 4: Calculate tangential acceleration
Step 5: Calculate centripetal acceleration
Step 6: Find magnitude of total acceleration
Tangential and centripetal accelerations are perpendicular:
Answer (c): Total acceleration ≈ 450 m/s²
Note: The centripetal acceleration (450 m/s²) is MUCH larger than the tangential acceleration (1.5 m/s²), so the total acceleration is essentially just the centripetal acceleration. This makes sense at high rotational speeds!
Direction: The total acceleration points slightly inward from the purely radial direction (mostly toward center, with small tangential component).
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