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Angular displacement, velocity, acceleration, and rotational kinematic equations
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Just as linear motion has position, velocity, and acceleration, rotational motion has corresponding angular quantities.
Angle of rotation from reference line:
A wheel starts from rest and accelerates uniformly at 2 rad/s² for 5 seconds. Find: (a) the final angular velocity, (b) the angular displacement during this time, and (c) the number of revolutions completed.
Given Information:
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Change in angular position:
Units: radians (rad)
Positive: counterclockwise rotation Negative: clockwise rotation
Rate of change of angular position:
Average:
Instantaneous:
Units: rad/s (radians per second)
Rate of change of angular velocity:
Average:
Instantaneous:
Units: rad/s² (radians per second squared)
| Linear Motion | Rotational Motion |
|---|---|
| Position | Angular position |
| Velocity | Angular velocity |
| Acceleration | Angular acceleration |
| Mass | Moment of inertia |
| Force | Torque |
For a point at distance from axis of rotation:
(where is in radians)
Tangential velocity - velocity tangent to circular path
Component of acceleration tangent to circle (changes speed)
Component of acceleration toward center (changes direction)
For constant angular acceleration :
1. Angular velocity:
2. Angular displacement:
3. Velocity-displacement:
4. Average velocity:
💡 These are EXACTLY analogous to linear kinematic equations! Just replace , , .
| Linear (constant ) | Rotational (constant ) |
|---|---|
For uniform circular motion (constant ):
Time for one complete rotation:
Units: seconds
Rotations per second:
Units: Hz (hertz) = rev/s
For an object rolling without slipping:
Constraint condition:
where:
No slipping means:
Tip: If you know linear quantities (, , ), convert using:
MUST use radians in equations! Convert degrees to radians first.
and are not always zero!
:
(constant ):
:
| Quantity | Formula | Units |
|---|---|---|
| Angular velocity | rad/s | |
| Angular acceleration | rad/s² | |
| Linear velocity | m/s | |
| Tangential acceleration | m/s² | |
| Centripetal acceleration | m/s² | |
| Period | s | |
| Frequency | Hz |
Kinematic equations (constant ):
(a) Find final angular velocity
Step 1: Use first kinematic equation
Answer (a): Final angular velocity = 10 rad/s
(b) Find angular displacement
Step 2: Use displacement equation
Alternative: Use average velocity
Both methods agree! ✓
Answer (b): Angular displacement = 25 rad
(c) Find number of revolutions
Step 3: Convert radians to revolutions
Answer (c): Number of revolutions ≈ 4.0 revolutions
Summary: The wheel accelerates from rest to 10 rad/s, turning through 25 radians (about 4 complete rotations) in 5 seconds.
A car tire with radius 0.3 m is rotating at 10 rev/s. The car brakes, and the tire comes to rest in 4 seconds with constant angular acceleration. Find: (a) the angular acceleration, and (b) the linear distance traveled during braking.
Given Information:
Step 0: Convert units
(a) Find angular acceleration
Step 1: Use first kinematic equation
Answer (a): Angular acceleration = −15.7 rad/s² (negative because it's slowing down)
(b) Find linear distance traveled
Step 2: Find angular displacement
Alternative: Use average velocity
Both methods agree! ✓
Step 3: Convert to linear distance
Answer (b): Linear distance traveled = 37.7 m (about 38 meters)
Check: This is reasonable for a car braking from moderate speed over 4 seconds.
Note: Number of revolutions = revolutions during braking.
A disk of radius 0.5 m starts from rest and rotates with constant angular acceleration. After 10 seconds, a point on the rim of the disk has a tangential speed of 15 m/s. Find: (a) the angular acceleration, (b) the angular displacement in those 10 seconds, and (c) the magnitude of the total acceleration of a point on the rim at t = 10 s.
Given Information:
(a) Find angular acceleration
Step 1: Find final angular velocity
Step 2: Calculate angular acceleration
Answer (a): Angular acceleration = 3 rad/s²
(b) Find angular displacement
Step 3: Use displacement equation
Alternative: Use average velocity
Answer (b): Angular displacement = 150 rad
(This is revolutions)
(c) Find total acceleration at t = 10 s
Step 4: Calculate tangential acceleration
Step 5: Calculate centripetal acceleration
Step 6: Find magnitude of total acceleration
Tangential and centripetal accelerations are perpendicular:
Answer (c): Total acceleration ≈ 450 m/s²
Note: The centripetal acceleration (450 m/s²) is MUCH larger than the tangential acceleration (1.5 m/s²), so the total acceleration is essentially just the centripetal acceleration. This makes sense at high rotational speeds!
Direction: The total acceleration points slightly inward from the purely radial direction (mostly toward center, with small tangential component).