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Understanding how functions change over intervals and at specific points
Learn step-by-step with practice exercises built right in.
The average rate of change of a function over the interval is:
For on :
The function increases by 4 units per unit of , on average.
The instantaneous rate of change of at is:
The expression is called the difference quotient.
As , the secant line approaches the tangent line.
Average Rate of Change (over interval ):
Instantaneous Rate of Change (at point ):
Alternative form (using instead of ):
In calculus, the instantaneous rate of change is the derivative:
Precalculus focuses on:
Find the average rate of change of over the interval .
Use the average rate of change formula:
A ball is thrown upward. Its height (in feet) after seconds is given by . Find the average velocity of the ball between and seconds.
Write an expression for the instantaneous rate of change of at . Then estimate it using .
Find the average rate of change of f(x) = xยฒ + 3x on the interval [1, 4].
Step 1: Use the average rate of change formula: Average rate = [f(b) - f(a)] / (b - a)
Step 2: Identify a and b: a = 1, b = 4
Step 3: Calculate f(1): f(1) = 1ยฒ + 3(1) = 1 + 3 = 4
Step 4: Calculate f(4): f(4) = 4ยฒ + 3(4) = 16 + 12 = 28
Step 5: Find the average rate of change: Average rate = (28 - 4) / (4 - 1) = 24 / 3 = 8
Answer: 8
A particle moves along a line with position function s(t) = tยณ - 6tยฒ + 9t. Find the instantaneous velocity at t = 2.
Step 1: Recall that instantaneous velocity is the derivative: v(t) = s'(t)
Step 2: Find the derivative of s(t) = tยณ - 6tยฒ + 9t: s'(t) = 3tยฒ - 12t + 9
Step 3: Evaluate at t = 2: v(2) = 3(2)ยฒ - 12(2) + 9 = 3(4) - 24 + 9 = 12 - 24 + 9 = -3
Step 4: Interpret: The instantaneous velocity at t = 2 is -3 units/time The negative value indicates the particle is moving in the negative direction.
Answer: -3 units/time
Avoid these 4 frequent errors
See how this math is used in the real world
A stone is dropped into a still pond, creating a circular ripple. The radius of the ripple is increasing at a rate of cm/s. How fast is the area of the circle increasing when the radius is cm?
where and .
Step 1: Find :
Step 2: Find :
Step 3: Calculate the average rate of change:
Answer: The average rate of change is .
Interpretation: On average, the function increases by 8 units for every 1 unit increase in over the interval .
Average velocity = average rate of change of position:
Step 1: Find :
Step 2: Find :
Step 3: Calculate average velocity:
Answer: The average velocity is ft/s.
Interpretation: The ball is at the same height at and . It went up and came back down to the same height, so the average velocity is zero (though it was moving the entire time!).
Expression for instantaneous rate of change at :
Step 1: Find :
Step 2: Find :
Step 3: Write the difference quotient:
Step 4: Simplify:
Exact answer (taking ):
Estimate with :
Answer: The instantaneous rate of change is (exact). The estimate with gives approximately , which is very close!