Proteins
Amino acids, protein structure, and functions of proteins
🧬 Proteins
Overview
Proteins are polymers of amino acids with diverse functions.
Functions:
- Enzymes (catalyze reactions)
- Structure (collagen, keratin)
- Transport (hemoglobin)
- Defense (antibodies)
- Movement (actin, myosin)
- Signaling (hormones like insulin)
- Storage (egg albumin)
Amino Acids
Structure:
- Central carbon (α-carbon)
- Amino group (-NH₂)
- Carboxyl group (-COOH)
- Hydrogen atom
- R group (side chain) - determines properties
20 different amino acids with different R groups:
- Nonpolar/hydrophobic
- Polar/hydrophilic
- Acidic (negatively charged)
- Basic (positively charged)
Protein Structure Levels
Primary Structure (1°)
- Sequence of amino acids
- Linked by peptide bonds
- Formed by dehydration synthesis
- Determines all higher structure
Secondary Structure (2°)
Regular folding patterns due to hydrogen bonding:
- α-helix: coiled spring shape
- β-pleated sheet: accordion-like folds
Tertiary Structure (3°)
- 3D shape of entire polypeptide
- Interactions between R groups:
- Hydrogen bonds
- Ionic bonds
- Hydrophobic interactions
- Disulfide bridges (covalent S-S bonds)
Quaternary Structure (4°)
- Multiple polypeptide subunits
- Example: hemoglobin (4 subunits)
Protein Folding
Denaturation:
- Loss of protein structure and function
- Caused by:
- High temperature
- pH changes
- Chemical denaturants
- Usually irreversible
Chaperone proteins:
- Help proteins fold correctly
- Prevent misfolding
Key Concepts
- Amino acids are monomers; proteins are polymers
- Peptide bonds link amino acids (dehydration synthesis)
- R groups determine amino acid properties
- Primary structure (sequence) determines final 3D shape
- Function depends on shape ("structure determines function")
- Denaturation destroys protein function
📚 Practice Problems
1Problem 1medium
❓ Question:
Describe the four levels of protein structure (primary, secondary, tertiary, quaternary). For each level, identify: (a) the type of bonds or interactions involved, and (b) give a specific example.
💡 Show Solution
Four Levels of Protein Structure:
1. Primary Structure
(a) Bonds: Peptide bonds (covalent) linking amino acids
- Sequence of amino acids in polypeptide chain
- Written N-terminus to C-terminus
- Determined by DNA sequence (gene)
(b) Example: Insulin A-chain: 21 amino acids starting with Gly-Ile-Val-Glu...
2. Secondary Structure
(a) Bonds/Interactions: Hydrogen bonds between backbone atoms (C=O and N-H)
Two main types:
- α-helix: Coiled structure, H-bonds between every 4th amino acid
- β-pleated sheet: Extended strands, H-bonds between adjacent strands (parallel or antiparallel)
(b) Example:
- α-helix: Keratin in hair, myoglobin
- β-sheet: Silk fibroin (antiparallel)
3. Tertiary Structure
(a) Bonds/Interactions:
- Hydrophobic interactions: Nonpolar R-groups cluster in interior
- Hydrogen bonds: Between R-groups
- Ionic bonds (salt bridges): Between charged R-groups (+ and -)
- Disulfide bridges (S-S): Covalent bonds between cysteine residues
- van der Waals forces: Weak attractions
Overall 3D shape of single polypeptide
(b) Example:
- Lysozyme (enzyme): specific 3D shape creates active site
- Myoglobin: globular protein with heme group
4. Quaternary Structure
(a) Bonds/Interactions: Same as tertiary (H-bonds, ionic, hydrophobic, van der Waals)
- Multiple polypeptide subunits associate
- Not all proteins have quaternary structure
- Functional protein complex
(b) Example:
- Hemoglobin: 4 subunits (2α, 2β chains), each with heme
- Collagen: 3 polypeptide helices twisted together (triple helix)
Summary Table:
| Level | Bond/Interaction | Example | |-------|-----------------|---------| | 1° | Peptide bonds | Amino acid sequence | | 2° | H-bonds (backbone) | α-helix, β-sheet | | 3° | Multiple (R-groups) | Myoglobin (3D fold) | | 4° | Multiple (subunits) | Hemoglobin (4 subunits) |
Key Concept: Structure determines function! Denaturation (loss of 3D structure) → loss of function.
2Problem 2medium
❓ Question:
Describe the four levels of protein structure (primary, secondary, tertiary, quaternary). For each level, identify: (a) the type of bonds or interactions involved, and (b) give a specific example.
💡 Show Solution
Four Levels of Protein Structure:
1. Primary Structure
(a) Bonds: Peptide bonds (covalent) linking amino acids
- Sequence of amino acids in polypeptide chain
- Written N-terminus to C-terminus
- Determined by DNA sequence (gene)
(b) Example: Insulin A-chain: 21 amino acids starting with Gly-Ile-Val-Glu...
2. Secondary Structure
(a) Bonds/Interactions: Hydrogen bonds between backbone atoms (C=O and N-H)
Two main types:
- α-helix: Coiled structure, H-bonds between every 4th amino acid
- β-pleated sheet: Extended strands, H-bonds between adjacent strands (parallel or antiparallel)
(b) Example:
- α-helix: Keratin in hair, myoglobin
- β-sheet: Silk fibroin (antiparallel)
3. Tertiary Structure
(a) Bonds/Interactions:
- Hydrophobic interactions: Nonpolar R-groups cluster in interior
- Hydrogen bonds: Between R-groups
- Ionic bonds (salt bridges): Between charged R-groups (+ and -)
- Disulfide bridges (S-S): Covalent bonds between cysteine residues
- van der Waals forces: Weak attractions
Overall 3D shape of single polypeptide
(b) Example:
- Lysozyme (enzyme): specific 3D shape creates active site
- Myoglobin: globular protein with heme group
4. Quaternary Structure
(a) Bonds/Interactions: Same as tertiary (H-bonds, ionic, hydrophobic, van der Waals)
- Multiple polypeptide subunits associate
- Not all proteins have quaternary structure
- Functional protein complex
(b) Example:
- Hemoglobin: 4 subunits (2α, 2β chains), each with heme
- Collagen: 3 polypeptide helices twisted together (triple helix)
Summary Table:
| Level | Bond/Interaction | Example | |-------|-----------------|---------| | 1° | Peptide bonds | Amino acid sequence | | 2° | H-bonds (backbone) | α-helix, β-sheet | | 3° | Multiple (R-groups) | Myoglobin (3D fold) | | 4° | Multiple (subunits) | Hemoglobin (4 subunits) |
Key Concept: Structure determines function! Denaturation (loss of 3D structure) → loss of function.
3Problem 3medium
❓ Question:
Describe the four levels of protein structure (primary, secondary, tertiary, quaternary). For each level, identify: (a) the type of bonds or interactions involved, and (b) give a specific example.
💡 Show Solution
Four Levels of Protein Structure:
1. Primary Structure
(a) Bonds: Peptide bonds (covalent) linking amino acids
- Sequence of amino acids in polypeptide chain
- Written N-terminus to C-terminus
- Determined by DNA sequence (gene)
(b) Example: Insulin A-chain: 21 amino acids starting with Gly-Ile-Val-Glu...
2. Secondary Structure
(a) Bonds/Interactions: Hydrogen bonds between backbone atoms (C=O and N-H)
Two main types:
- α-helix: Coiled structure, H-bonds between every 4th amino acid
- β-pleated sheet: Extended strands, H-bonds between adjacent strands (parallel or antiparallel)
(b) Example:
- α-helix: Keratin in hair, myoglobin
- β-sheet: Silk fibroin (antiparallel)
3. Tertiary Structure
(a) Bonds/Interactions:
- Hydrophobic interactions: Nonpolar R-groups cluster in interior
- Hydrogen bonds: Between R-groups
- Ionic bonds (salt bridges): Between charged R-groups (+ and -)
- Disulfide bridges (S-S): Covalent bonds between cysteine residues
- van der Waals forces: Weak attractions
Overall 3D shape of single polypeptide
(b) Example:
- Lysozyme (enzyme): specific 3D shape creates active site
- Myoglobin: globular protein with heme group
4. Quaternary Structure
(a) Bonds/Interactions: Same as tertiary (H-bonds, ionic, hydrophobic, van der Waals)
- Multiple polypeptide subunits associate
- Not all proteins have quaternary structure
- Functional protein complex
(b) Example:
- Hemoglobin: 4 subunits (2α, 2β chains), each with heme
- Collagen: 3 polypeptide helices twisted together (triple helix)
Summary Table:
| Level | Bond/Interaction | Example | |-------|-----------------|---------| | 1° | Peptide bonds | Amino acid sequence | | 2° | H-bonds (backbone) | α-helix, β-sheet | | 3° | Multiple (R-groups) | Myoglobin (3D fold) | | 4° | Multiple (subunits) | Hemoglobin (4 subunits) |
Key Concept: Structure determines function! Denaturation (loss of 3D structure) → loss of function.
4Problem 4medium
❓ Question:
Describe the four levels of protein structure (primary, secondary, tertiary, quaternary). For each level, identify: (a) the type of bonds or interactions involved, and (b) give a specific example.
💡 Show Solution
Four Levels of Protein Structure:
1. Primary Structure
(a) Bonds: Peptide bonds (covalent) linking amino acids
- Sequence of amino acids in polypeptide chain
- Written N-terminus to C-terminus
- Determined by DNA sequence (gene)
(b) Example: Insulin A-chain: 21 amino acids starting with Gly-Ile-Val-Glu...
2. Secondary Structure
(a) Bonds/Interactions: Hydrogen bonds between backbone atoms (C=O and N-H)
Two main types:
- α-helix: Coiled structure, H-bonds between every 4th amino acid
- β-pleated sheet: Extended strands, H-bonds between adjacent strands (parallel or antiparallel)
(b) Example:
- α-helix: Keratin in hair, myoglobin
- β-sheet: Silk fibroin (antiparallel)
3. Tertiary Structure
(a) Bonds/Interactions:
- Hydrophobic interactions: Nonpolar R-groups cluster in interior
- Hydrogen bonds: Between R-groups
- Ionic bonds (salt bridges): Between charged R-groups (+ and -)
- Disulfide bridges (S-S): Covalent bonds between cysteine residues
- van der Waals forces: Weak attractions
Overall 3D shape of single polypeptide
(b) Example:
- Lysozyme (enzyme): specific 3D shape creates active site
- Myoglobin: globular protein with heme group
4. Quaternary Structure
(a) Bonds/Interactions: Same as tertiary (H-bonds, ionic, hydrophobic, van der Waals)
- Multiple polypeptide subunits associate
- Not all proteins have quaternary structure
- Functional protein complex
(b) Example:
- Hemoglobin: 4 subunits (2α, 2β chains), each with heme
- Collagen: 3 polypeptide helices twisted together (triple helix)
Summary Table:
| Level | Bond/Interaction | Example | |-------|-----------------|---------| | 1° | Peptide bonds | Amino acid sequence | | 2° | H-bonds (backbone) | α-helix, β-sheet | | 3° | Multiple (R-groups) | Myoglobin (3D fold) | | 4° | Multiple (subunits) | Hemoglobin (4 subunits) |
Key Concept: Structure determines function! Denaturation (loss of 3D structure) → loss of function.
5Problem 5hard
❓ Question:
An enzyme has optimal activity at pH 7.0 and temperature 37°C. Predict and explain what happens to enzyme activity when: (a) pH is changed to 3.0, (b) temperature is increased to 80°C, and (c) a competitive inhibitor is added. Include discussion of protein structure changes.
💡 Show Solution
Enzyme Conditions: Optimal at pH 7.0 and 37°C
(a) pH changed to 3.0 (strongly acidic):
Prediction: ⚠️ Enzyme activity greatly reduced or eliminated
Explanation:
-
Protonation of amino acids:
- Acidic pH adds excess H⁺ ions
- Amino acid R-groups become protonated
- Charged residues (Asp⁻, Glu⁻) become neutral (AspH, GluH)
- Basic residues (His, Lys, Arg) become more positive
-
Disruption of ionic bonds:
- Salt bridges (electrostatic interactions) break
- Changes in charge distribution
-
Tertiary structure denaturation:
- 3D shape distorts
- Active site changes shape
- Substrate can no longer bind properly
-
Result: Loss of catalytic activity (may be reversible if pH restored quickly)
(b) Temperature increased to 80°C (far above optimum):
Prediction: ⚠️ Enzyme denatured, activity lost permanently
Explanation:
-
Increased kinetic energy:
- Molecules vibrate more vigorously
- Weak bonds break (H-bonds, ionic, hydrophobic)
-
Progressive unfolding:
- Secondary structure disrupted (α-helices, β-sheets unfold)
- Tertiary structure lost
- Protein unfolds into random coil
-
Permanent denaturation:
- Polypeptide chains may aggregate
- Disulfide bonds may scramble
- Irreversible damage
-
Activity-Temperature Relationship:
Activity ^ | /\ | / \ | / \_____ (denaturation) | / |_/________________> Temperature 37°C 80°C
Why irreversible: Unlike pH change, heat breaks so many bonds simultaneously that protein cannot refold to native state.
(c) Competitive inhibitor added:
Prediction: 🔽 Enzyme activity reduced but NOT eliminated
Explanation:
-
Competitive inhibition mechanism:
- Inhibitor structurally similar to substrate
- Competes for same active site
- Reversibly binds to enzyme
-
Effect on protein structure:
- No structural change to enzyme!
- Enzyme remains properly folded
- Active site unchanged
-
Kinetic effects:
- ↑ K_m (apparent affinity for substrate decreases)
- V_max unchanged (can be overcome with excess substrate)
-
Equation:
where [I] = inhibitor concentration, K_i = inhibitor constant
-
Key difference:
- Can be overcome by increasing substrate concentration
- At high [S], substrate outcompetes inhibitor
- Eventually reaches V_max
Comparison:
| Condition | Structure Change | Activity | Reversible? | |-----------|-----------------|----------|-------------| | Low pH | Tertiary disrupted | Very low | Yes (if quick) | | High temp | Complete denaturation | Zero | No | | Competitive inh. | None | Reduced | Yes (↑ substrate) |
6Problem 6hard
❓ Question:
An enzyme has optimal activity at pH 7.0 and temperature 37°C. Predict and explain what happens to enzyme activity when: (a) pH is changed to 3.0, (b) temperature is increased to 80°C, and (c) a competitive inhibitor is added. Include discussion of protein structure changes.
💡 Show Solution
Enzyme Conditions: Optimal at pH 7.0 and 37°C
(a) pH changed to 3.0 (strongly acidic):
Prediction: ⚠️ Enzyme activity greatly reduced or eliminated
Explanation:
-
Protonation of amino acids:
- Acidic pH adds excess H⁺ ions
- Amino acid R-groups become protonated
- Charged residues (Asp⁻, Glu⁻) become neutral (AspH, GluH)
- Basic residues (His, Lys, Arg) become more positive
-
Disruption of ionic bonds:
- Salt bridges (electrostatic interactions) break
- Changes in charge distribution
-
Tertiary structure denaturation:
- 3D shape distorts
- Active site changes shape
- Substrate can no longer bind properly
-
Result: Loss of catalytic activity (may be reversible if pH restored quickly)
(b) Temperature increased to 80°C (far above optimum):
Prediction: ⚠️ Enzyme denatured, activity lost permanently
Explanation:
-
Increased kinetic energy:
- Molecules vibrate more vigorously
- Weak bonds break (H-bonds, ionic, hydrophobic)
-
Progressive unfolding:
- Secondary structure disrupted (α-helices, β-sheets unfold)
- Tertiary structure lost
- Protein unfolds into random coil
-
Permanent denaturation:
- Polypeptide chains may aggregate
- Disulfide bonds may scramble
- Irreversible damage
-
Activity-Temperature Relationship:
Activity ^ | /\ | / \ | / \_____ (denaturation) | / |_/________________> Temperature 37°C 80°C
Why irreversible: Unlike pH change, heat breaks so many bonds simultaneously that protein cannot refold to native state.
(c) Competitive inhibitor added:
Prediction: 🔽 Enzyme activity reduced but NOT eliminated
Explanation:
-
Competitive inhibition mechanism:
- Inhibitor structurally similar to substrate
- Competes for same active site
- Reversibly binds to enzyme
-
Effect on protein structure:
- No structural change to enzyme!
- Enzyme remains properly folded
- Active site unchanged
-
Kinetic effects:
- ↑ K_m (apparent affinity for substrate decreases)
- V_max unchanged (can be overcome with excess substrate)
-
Equation:
where [I] = inhibitor concentration, K_i = inhibitor constant
-
Key difference:
- Can be overcome by increasing substrate concentration
- At high [S], substrate outcompetes inhibitor
- Eventually reaches V_max
Comparison:
| Condition | Structure Change | Activity | Reversible? | |-----------|-----------------|----------|-------------| | Low pH | Tertiary disrupted | Very low | Yes (if quick) | | High temp | Complete denaturation | Zero | No | | Competitive inh. | None | Reduced | Yes (↑ substrate) |
7Problem 7hard
❓ Question:
An enzyme has optimal activity at pH 7.0 and temperature 37°C. Predict and explain what happens to enzyme activity when: (a) pH is changed to 3.0, (b) temperature is increased to 80°C, and (c) a competitive inhibitor is added. Include discussion of protein structure changes.
💡 Show Solution
Enzyme Conditions: Optimal at pH 7.0 and 37°C
(a) pH changed to 3.0 (strongly acidic):
Prediction: ⚠️ Enzyme activity greatly reduced or eliminated
Explanation:
-
Protonation of amino acids:
- Acidic pH adds excess H⁺ ions
- Amino acid R-groups become protonated
- Charged residues (Asp⁻, Glu⁻) become neutral (AspH, GluH)
- Basic residues (His, Lys, Arg) become more positive
-
Disruption of ionic bonds:
- Salt bridges (electrostatic interactions) break
- Changes in charge distribution
-
Tertiary structure denaturation:
- 3D shape distorts
- Active site changes shape
- Substrate can no longer bind properly
-
Result: Loss of catalytic activity (may be reversible if pH restored quickly)
(b) Temperature increased to 80°C (far above optimum):
Prediction: ⚠️ Enzyme denatured, activity lost permanently
Explanation:
-
Increased kinetic energy:
- Molecules vibrate more vigorously
- Weak bonds break (H-bonds, ionic, hydrophobic)
-
Progressive unfolding:
- Secondary structure disrupted (α-helices, β-sheets unfold)
- Tertiary structure lost
- Protein unfolds into random coil
-
Permanent denaturation:
- Polypeptide chains may aggregate
- Disulfide bonds may scramble
- Irreversible damage
-
Activity-Temperature Relationship:
Activity ^ | /\ | / \ | / \_____ (denaturation) | / |_/________________> Temperature 37°C 80°C
Why irreversible: Unlike pH change, heat breaks so many bonds simultaneously that protein cannot refold to native state.
(c) Competitive inhibitor added:
Prediction: 🔽 Enzyme activity reduced but NOT eliminated
Explanation:
-
Competitive inhibition mechanism:
- Inhibitor structurally similar to substrate
- Competes for same active site
- Reversibly binds to enzyme
-
Effect on protein structure:
- No structural change to enzyme!
- Enzyme remains properly folded
- Active site unchanged
-
Kinetic effects:
- ↑ K_m (apparent affinity for substrate decreases)
- V_max unchanged (can be overcome with excess substrate)
-
Equation:
where [I] = inhibitor concentration, K_i = inhibitor constant
-
Key difference:
- Can be overcome by increasing substrate concentration
- At high [S], substrate outcompetes inhibitor
- Eventually reaches V_max
Comparison:
| Condition | Structure Change | Activity | Reversible? | |-----------|-----------------|----------|-------------| | Low pH | Tertiary disrupted | Very low | Yes (if quick) | | High temp | Complete denaturation | Zero | No | | Competitive inh. | None | Reduced | Yes (↑ substrate) |
8Problem 8hard
❓ Question:
An enzyme has optimal activity at pH 7.0 and temperature 37°C. Predict and explain what happens to enzyme activity when: (a) pH is changed to 3.0, (b) temperature is increased to 80°C, and (c) a competitive inhibitor is added. Include discussion of protein structure changes.
💡 Show Solution
Enzyme Conditions: Optimal at pH 7.0 and 37°C
(a) pH changed to 3.0 (strongly acidic):
Prediction: ⚠️ Enzyme activity greatly reduced or eliminated
Explanation:
-
Protonation of amino acids:
- Acidic pH adds excess H⁺ ions
- Amino acid R-groups become protonated
- Charged residues (Asp⁻, Glu⁻) become neutral (AspH, GluH)
- Basic residues (His, Lys, Arg) become more positive
-
Disruption of ionic bonds:
- Salt bridges (electrostatic interactions) break
- Changes in charge distribution
-
Tertiary structure denaturation:
- 3D shape distorts
- Active site changes shape
- Substrate can no longer bind properly
-
Result: Loss of catalytic activity (may be reversible if pH restored quickly)
(b) Temperature increased to 80°C (far above optimum):
Prediction: ⚠️ Enzyme denatured, activity lost permanently
Explanation:
-
Increased kinetic energy:
- Molecules vibrate more vigorously
- Weak bonds break (H-bonds, ionic, hydrophobic)
-
Progressive unfolding:
- Secondary structure disrupted (α-helices, β-sheets unfold)
- Tertiary structure lost
- Protein unfolds into random coil
-
Permanent denaturation:
- Polypeptide chains may aggregate
- Disulfide bonds may scramble
- Irreversible damage
-
Activity-Temperature Relationship:
Activity ^ | /\ | / \ | / \_____ (denaturation) | / |_/________________> Temperature 37°C 80°C
Why irreversible: Unlike pH change, heat breaks so many bonds simultaneously that protein cannot refold to native state.
(c) Competitive inhibitor added:
Prediction: 🔽 Enzyme activity reduced but NOT eliminated
Explanation:
-
Competitive inhibition mechanism:
- Inhibitor structurally similar to substrate
- Competes for same active site
- Reversibly binds to enzyme
-
Effect on protein structure:
- No structural change to enzyme!
- Enzyme remains properly folded
- Active site unchanged
-
Kinetic effects:
- ↑ K_m (apparent affinity for substrate decreases)
- V_max unchanged (can be overcome with excess substrate)
-
Equation:
where [I] = inhibitor concentration, K_i = inhibitor constant
-
Key difference:
- Can be overcome by increasing substrate concentration
- At high [S], substrate outcompetes inhibitor
- Eventually reaches V_max
Comparison:
| Condition | Structure Change | Activity | Reversible? | |-----------|-----------------|----------|-------------| | Low pH | Tertiary disrupted | Very low | Yes (if quick) | | High temp | Complete denaturation | Zero | No | | Competitive inh. | None | Reduced | Yes (↑ substrate) |
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