Proteins

Amino acids, protein structure, and functions of proteins

🧬 Proteins

Overview

Proteins are polymers of amino acids with diverse functions.

Functions:

  1. Enzymes (catalyze reactions)
  2. Structure (collagen, keratin)
  3. Transport (hemoglobin)
  4. Defense (antibodies)
  5. Movement (actin, myosin)
  6. Signaling (hormones like insulin)
  7. Storage (egg albumin)

Amino Acids

Structure:

  • Central carbon (α-carbon)
  • Amino group (-NH₂)
  • Carboxyl group (-COOH)
  • Hydrogen atom
  • R group (side chain) - determines properties

20 different amino acids with different R groups:

  • Nonpolar/hydrophobic
  • Polar/hydrophilic
  • Acidic (negatively charged)
  • Basic (positively charged)

Protein Structure Levels

Primary Structure (1°)

  • Sequence of amino acids
  • Linked by peptide bonds
  • Formed by dehydration synthesis
  • Determines all higher structure

Secondary Structure (2°)

Regular folding patterns due to hydrogen bonding:

  • α-helix: coiled spring shape
  • β-pleated sheet: accordion-like folds

Tertiary Structure (3°)

  • 3D shape of entire polypeptide
  • Interactions between R groups:
    • Hydrogen bonds
    • Ionic bonds
    • Hydrophobic interactions
    • Disulfide bridges (covalent S-S bonds)

Quaternary Structure (4°)

  • Multiple polypeptide subunits
  • Example: hemoglobin (4 subunits)

Protein Folding

Denaturation:

  • Loss of protein structure and function
  • Caused by:
    • High temperature
    • pH changes
    • Chemical denaturants
  • Usually irreversible

Chaperone proteins:

  • Help proteins fold correctly
  • Prevent misfolding

Key Concepts

  1. Amino acids are monomers; proteins are polymers
  2. Peptide bonds link amino acids (dehydration synthesis)
  3. R groups determine amino acid properties
  4. Primary structure (sequence) determines final 3D shape
  5. Function depends on shape ("structure determines function")
  6. Denaturation destroys protein function

📚 Practice Problems

1Problem 1medium

Question:

Describe the four levels of protein structure (primary, secondary, tertiary, quaternary). For each level, identify: (a) the type of bonds or interactions involved, and (b) give a specific example.

💡 Show Solution

Four Levels of Protein Structure:

1. Primary Structure

(a) Bonds: Peptide bonds (covalent) linking amino acids

  • Sequence of amino acids in polypeptide chain
  • Written N-terminus to C-terminus
  • Determined by DNA sequence (gene)

(b) Example: Insulin A-chain: 21 amino acids starting with Gly-Ile-Val-Glu...

2. Secondary Structure

(a) Bonds/Interactions: Hydrogen bonds between backbone atoms (C=O and N-H)

Two main types:

  • α-helix: Coiled structure, H-bonds between every 4th amino acid
  • β-pleated sheet: Extended strands, H-bonds between adjacent strands (parallel or antiparallel)

(b) Example:

  • α-helix: Keratin in hair, myoglobin
  • β-sheet: Silk fibroin (antiparallel)

3. Tertiary Structure

(a) Bonds/Interactions:

  • Hydrophobic interactions: Nonpolar R-groups cluster in interior
  • Hydrogen bonds: Between R-groups
  • Ionic bonds (salt bridges): Between charged R-groups (+ and -)
  • Disulfide bridges (S-S): Covalent bonds between cysteine residues
  • van der Waals forces: Weak attractions

Overall 3D shape of single polypeptide

(b) Example:

  • Lysozyme (enzyme): specific 3D shape creates active site
  • Myoglobin: globular protein with heme group

4. Quaternary Structure

(a) Bonds/Interactions: Same as tertiary (H-bonds, ionic, hydrophobic, van der Waals)

  • Multiple polypeptide subunits associate
  • Not all proteins have quaternary structure
  • Functional protein complex

(b) Example:

  • Hemoglobin: 4 subunits (2α, 2β chains), each with heme
  • Collagen: 3 polypeptide helices twisted together (triple helix)

Summary Table:

| Level | Bond/Interaction | Example | |-------|-----------------|---------| | 1° | Peptide bonds | Amino acid sequence | | 2° | H-bonds (backbone) | α-helix, β-sheet | | 3° | Multiple (R-groups) | Myoglobin (3D fold) | | 4° | Multiple (subunits) | Hemoglobin (4 subunits) |

1°: sequence, 2°: local folds, 3°: 3D shape, 4°: multiple chains\boxed{\text{1°: sequence, 2°: local folds, 3°: 3D shape, 4°: multiple chains}}

Key Concept: Structure determines function! Denaturation (loss of 3D structure) → loss of function.

2Problem 2medium

Question:

Describe the four levels of protein structure (primary, secondary, tertiary, quaternary). For each level, identify: (a) the type of bonds or interactions involved, and (b) give a specific example.

💡 Show Solution

Four Levels of Protein Structure:

1. Primary Structure

(a) Bonds: Peptide bonds (covalent) linking amino acids

  • Sequence of amino acids in polypeptide chain
  • Written N-terminus to C-terminus
  • Determined by DNA sequence (gene)

(b) Example: Insulin A-chain: 21 amino acids starting with Gly-Ile-Val-Glu...

2. Secondary Structure

(a) Bonds/Interactions: Hydrogen bonds between backbone atoms (C=O and N-H)

Two main types:

  • α-helix: Coiled structure, H-bonds between every 4th amino acid
  • β-pleated sheet: Extended strands, H-bonds between adjacent strands (parallel or antiparallel)

(b) Example:

  • α-helix: Keratin in hair, myoglobin
  • β-sheet: Silk fibroin (antiparallel)

3. Tertiary Structure

(a) Bonds/Interactions:

  • Hydrophobic interactions: Nonpolar R-groups cluster in interior
  • Hydrogen bonds: Between R-groups
  • Ionic bonds (salt bridges): Between charged R-groups (+ and -)
  • Disulfide bridges (S-S): Covalent bonds between cysteine residues
  • van der Waals forces: Weak attractions

Overall 3D shape of single polypeptide

(b) Example:

  • Lysozyme (enzyme): specific 3D shape creates active site
  • Myoglobin: globular protein with heme group

4. Quaternary Structure

(a) Bonds/Interactions: Same as tertiary (H-bonds, ionic, hydrophobic, van der Waals)

  • Multiple polypeptide subunits associate
  • Not all proteins have quaternary structure
  • Functional protein complex

(b) Example:

  • Hemoglobin: 4 subunits (2α, 2β chains), each with heme
  • Collagen: 3 polypeptide helices twisted together (triple helix)

Summary Table:

| Level | Bond/Interaction | Example | |-------|-----------------|---------| | 1° | Peptide bonds | Amino acid sequence | | 2° | H-bonds (backbone) | α-helix, β-sheet | | 3° | Multiple (R-groups) | Myoglobin (3D fold) | | 4° | Multiple (subunits) | Hemoglobin (4 subunits) |

1°: sequence, 2°: local folds, 3°: 3D shape, 4°: multiple chains\boxed{\text{1°: sequence, 2°: local folds, 3°: 3D shape, 4°: multiple chains}}

Key Concept: Structure determines function! Denaturation (loss of 3D structure) → loss of function.

3Problem 3medium

Question:

Describe the four levels of protein structure (primary, secondary, tertiary, quaternary). For each level, identify: (a) the type of bonds or interactions involved, and (b) give a specific example.

💡 Show Solution

Four Levels of Protein Structure:

1. Primary Structure

(a) Bonds: Peptide bonds (covalent) linking amino acids

  • Sequence of amino acids in polypeptide chain
  • Written N-terminus to C-terminus
  • Determined by DNA sequence (gene)

(b) Example: Insulin A-chain: 21 amino acids starting with Gly-Ile-Val-Glu...

2. Secondary Structure

(a) Bonds/Interactions: Hydrogen bonds between backbone atoms (C=O and N-H)

Two main types:

  • α-helix: Coiled structure, H-bonds between every 4th amino acid
  • β-pleated sheet: Extended strands, H-bonds between adjacent strands (parallel or antiparallel)

(b) Example:

  • α-helix: Keratin in hair, myoglobin
  • β-sheet: Silk fibroin (antiparallel)

3. Tertiary Structure

(a) Bonds/Interactions:

  • Hydrophobic interactions: Nonpolar R-groups cluster in interior
  • Hydrogen bonds: Between R-groups
  • Ionic bonds (salt bridges): Between charged R-groups (+ and -)
  • Disulfide bridges (S-S): Covalent bonds between cysteine residues
  • van der Waals forces: Weak attractions

Overall 3D shape of single polypeptide

(b) Example:

  • Lysozyme (enzyme): specific 3D shape creates active site
  • Myoglobin: globular protein with heme group

4. Quaternary Structure

(a) Bonds/Interactions: Same as tertiary (H-bonds, ionic, hydrophobic, van der Waals)

  • Multiple polypeptide subunits associate
  • Not all proteins have quaternary structure
  • Functional protein complex

(b) Example:

  • Hemoglobin: 4 subunits (2α, 2β chains), each with heme
  • Collagen: 3 polypeptide helices twisted together (triple helix)

Summary Table:

| Level | Bond/Interaction | Example | |-------|-----------------|---------| | 1° | Peptide bonds | Amino acid sequence | | 2° | H-bonds (backbone) | α-helix, β-sheet | | 3° | Multiple (R-groups) | Myoglobin (3D fold) | | 4° | Multiple (subunits) | Hemoglobin (4 subunits) |

1°: sequence, 2°: local folds, 3°: 3D shape, 4°: multiple chains\boxed{\text{1°: sequence, 2°: local folds, 3°: 3D shape, 4°: multiple chains}}

Key Concept: Structure determines function! Denaturation (loss of 3D structure) → loss of function.

4Problem 4medium

Question:

Describe the four levels of protein structure (primary, secondary, tertiary, quaternary). For each level, identify: (a) the type of bonds or interactions involved, and (b) give a specific example.

💡 Show Solution

Four Levels of Protein Structure:

1. Primary Structure

(a) Bonds: Peptide bonds (covalent) linking amino acids

  • Sequence of amino acids in polypeptide chain
  • Written N-terminus to C-terminus
  • Determined by DNA sequence (gene)

(b) Example: Insulin A-chain: 21 amino acids starting with Gly-Ile-Val-Glu...

2. Secondary Structure

(a) Bonds/Interactions: Hydrogen bonds between backbone atoms (C=O and N-H)

Two main types:

  • α-helix: Coiled structure, H-bonds between every 4th amino acid
  • β-pleated sheet: Extended strands, H-bonds between adjacent strands (parallel or antiparallel)

(b) Example:

  • α-helix: Keratin in hair, myoglobin
  • β-sheet: Silk fibroin (antiparallel)

3. Tertiary Structure

(a) Bonds/Interactions:

  • Hydrophobic interactions: Nonpolar R-groups cluster in interior
  • Hydrogen bonds: Between R-groups
  • Ionic bonds (salt bridges): Between charged R-groups (+ and -)
  • Disulfide bridges (S-S): Covalent bonds between cysteine residues
  • van der Waals forces: Weak attractions

Overall 3D shape of single polypeptide

(b) Example:

  • Lysozyme (enzyme): specific 3D shape creates active site
  • Myoglobin: globular protein with heme group

4. Quaternary Structure

(a) Bonds/Interactions: Same as tertiary (H-bonds, ionic, hydrophobic, van der Waals)

  • Multiple polypeptide subunits associate
  • Not all proteins have quaternary structure
  • Functional protein complex

(b) Example:

  • Hemoglobin: 4 subunits (2α, 2β chains), each with heme
  • Collagen: 3 polypeptide helices twisted together (triple helix)

Summary Table:

| Level | Bond/Interaction | Example | |-------|-----------------|---------| | 1° | Peptide bonds | Amino acid sequence | | 2° | H-bonds (backbone) | α-helix, β-sheet | | 3° | Multiple (R-groups) | Myoglobin (3D fold) | | 4° | Multiple (subunits) | Hemoglobin (4 subunits) |

1°: sequence, 2°: local folds, 3°: 3D shape, 4°: multiple chains\boxed{\text{1°: sequence, 2°: local folds, 3°: 3D shape, 4°: multiple chains}}

Key Concept: Structure determines function! Denaturation (loss of 3D structure) → loss of function.

5Problem 5hard

Question:

An enzyme has optimal activity at pH 7.0 and temperature 37°C. Predict and explain what happens to enzyme activity when: (a) pH is changed to 3.0, (b) temperature is increased to 80°C, and (c) a competitive inhibitor is added. Include discussion of protein structure changes.

💡 Show Solution

Enzyme Conditions: Optimal at pH 7.0 and 37°C

(a) pH changed to 3.0 (strongly acidic):

Prediction: ⚠️ Enzyme activity greatly reduced or eliminated

Explanation:

  1. Protonation of amino acids:

    • Acidic pH adds excess H⁺ ions
    • Amino acid R-groups become protonated
    • Charged residues (Asp⁻, Glu⁻) become neutral (AspH, GluH)
    • Basic residues (His, Lys, Arg) become more positive
  2. Disruption of ionic bonds:

    • Salt bridges (electrostatic interactions) break
    • Changes in charge distribution
  3. Tertiary structure denaturation:

    • 3D shape distorts
    • Active site changes shape
    • Substrate can no longer bind properly
  4. Result: Loss of catalytic activity (may be reversible if pH restored quickly)

(b) Temperature increased to 80°C (far above optimum):

Prediction: ⚠️ Enzyme denatured, activity lost permanently

Explanation:

  1. Increased kinetic energy:

    • Molecules vibrate more vigorously
    • Weak bonds break (H-bonds, ionic, hydrophobic)
  2. Progressive unfolding:

    • Secondary structure disrupted (α-helices, β-sheets unfold)
    • Tertiary structure lost
    • Protein unfolds into random coil
  3. Permanent denaturation:

    • Polypeptide chains may aggregate
    • Disulfide bonds may scramble
    • Irreversible damage
  4. Activity-Temperature Relationship:

    Activity
      ^
      |     /\
      |    /  \
      |   /    \_____ (denaturation)
      |  /
      |_/________________> Temperature
          37°C  80°C
    

Why irreversible: Unlike pH change, heat breaks so many bonds simultaneously that protein cannot refold to native state.

(c) Competitive inhibitor added:

Prediction: 🔽 Enzyme activity reduced but NOT eliminated

Explanation:

  1. Competitive inhibition mechanism:

    • Inhibitor structurally similar to substrate
    • Competes for same active site
    • Reversibly binds to enzyme
  2. Effect on protein structure:

    • No structural change to enzyme!
    • Enzyme remains properly folded
    • Active site unchanged
  3. Kinetic effects:

    • ↑ K_m (apparent affinity for substrate decreases)
    • V_max unchanged (can be overcome with excess substrate)
  4. Equation:

    v=Vmax[S]Km(1+[I]/Ki)+[S]v = \frac{V_{max}[S]}{K_m(1 + [I]/K_i) + [S]}

    where [I] = inhibitor concentration, K_i = inhibitor constant

  5. Key difference:

    • Can be overcome by increasing substrate concentration
    • At high [S], substrate outcompetes inhibitor
    • Eventually reaches V_max

Comparison:

| Condition | Structure Change | Activity | Reversible? | |-----------|-----------------|----------|-------------| | Low pH | Tertiary disrupted | Very low | Yes (if quick) | | High temp | Complete denaturation | Zero | No | | Competitive inh. | None | Reduced | Yes (↑ substrate) |

(a) Denatures (reversible), (b) Denatures (irreversible), (c) Active site blocked (reversible)\boxed{\text{(a) Denatures (reversible), (b) Denatures (irreversible), (c) Active site blocked (reversible)}}

6Problem 6hard

Question:

An enzyme has optimal activity at pH 7.0 and temperature 37°C. Predict and explain what happens to enzyme activity when: (a) pH is changed to 3.0, (b) temperature is increased to 80°C, and (c) a competitive inhibitor is added. Include discussion of protein structure changes.

💡 Show Solution

Enzyme Conditions: Optimal at pH 7.0 and 37°C

(a) pH changed to 3.0 (strongly acidic):

Prediction: ⚠️ Enzyme activity greatly reduced or eliminated

Explanation:

  1. Protonation of amino acids:

    • Acidic pH adds excess H⁺ ions
    • Amino acid R-groups become protonated
    • Charged residues (Asp⁻, Glu⁻) become neutral (AspH, GluH)
    • Basic residues (His, Lys, Arg) become more positive
  2. Disruption of ionic bonds:

    • Salt bridges (electrostatic interactions) break
    • Changes in charge distribution
  3. Tertiary structure denaturation:

    • 3D shape distorts
    • Active site changes shape
    • Substrate can no longer bind properly
  4. Result: Loss of catalytic activity (may be reversible if pH restored quickly)

(b) Temperature increased to 80°C (far above optimum):

Prediction: ⚠️ Enzyme denatured, activity lost permanently

Explanation:

  1. Increased kinetic energy:

    • Molecules vibrate more vigorously
    • Weak bonds break (H-bonds, ionic, hydrophobic)
  2. Progressive unfolding:

    • Secondary structure disrupted (α-helices, β-sheets unfold)
    • Tertiary structure lost
    • Protein unfolds into random coil
  3. Permanent denaturation:

    • Polypeptide chains may aggregate
    • Disulfide bonds may scramble
    • Irreversible damage
  4. Activity-Temperature Relationship:

    Activity
      ^
      |     /\
      |    /  \
      |   /    \_____ (denaturation)
      |  /
      |_/________________> Temperature
          37°C  80°C
    

Why irreversible: Unlike pH change, heat breaks so many bonds simultaneously that protein cannot refold to native state.

(c) Competitive inhibitor added:

Prediction: 🔽 Enzyme activity reduced but NOT eliminated

Explanation:

  1. Competitive inhibition mechanism:

    • Inhibitor structurally similar to substrate
    • Competes for same active site
    • Reversibly binds to enzyme
  2. Effect on protein structure:

    • No structural change to enzyme!
    • Enzyme remains properly folded
    • Active site unchanged
  3. Kinetic effects:

    • ↑ K_m (apparent affinity for substrate decreases)
    • V_max unchanged (can be overcome with excess substrate)
  4. Equation:

    v=Vmax[S]Km(1+[I]/Ki)+[S]v = \frac{V_{max}[S]}{K_m(1 + [I]/K_i) + [S]}

    where [I] = inhibitor concentration, K_i = inhibitor constant

  5. Key difference:

    • Can be overcome by increasing substrate concentration
    • At high [S], substrate outcompetes inhibitor
    • Eventually reaches V_max

Comparison:

| Condition | Structure Change | Activity | Reversible? | |-----------|-----------------|----------|-------------| | Low pH | Tertiary disrupted | Very low | Yes (if quick) | | High temp | Complete denaturation | Zero | No | | Competitive inh. | None | Reduced | Yes (↑ substrate) |

(a) Denatures (reversible), (b) Denatures (irreversible), (c) Active site blocked (reversible)\boxed{\text{(a) Denatures (reversible), (b) Denatures (irreversible), (c) Active site blocked (reversible)}}

7Problem 7hard

Question:

An enzyme has optimal activity at pH 7.0 and temperature 37°C. Predict and explain what happens to enzyme activity when: (a) pH is changed to 3.0, (b) temperature is increased to 80°C, and (c) a competitive inhibitor is added. Include discussion of protein structure changes.

💡 Show Solution

Enzyme Conditions: Optimal at pH 7.0 and 37°C

(a) pH changed to 3.0 (strongly acidic):

Prediction: ⚠️ Enzyme activity greatly reduced or eliminated

Explanation:

  1. Protonation of amino acids:

    • Acidic pH adds excess H⁺ ions
    • Amino acid R-groups become protonated
    • Charged residues (Asp⁻, Glu⁻) become neutral (AspH, GluH)
    • Basic residues (His, Lys, Arg) become more positive
  2. Disruption of ionic bonds:

    • Salt bridges (electrostatic interactions) break
    • Changes in charge distribution
  3. Tertiary structure denaturation:

    • 3D shape distorts
    • Active site changes shape
    • Substrate can no longer bind properly
  4. Result: Loss of catalytic activity (may be reversible if pH restored quickly)

(b) Temperature increased to 80°C (far above optimum):

Prediction: ⚠️ Enzyme denatured, activity lost permanently

Explanation:

  1. Increased kinetic energy:

    • Molecules vibrate more vigorously
    • Weak bonds break (H-bonds, ionic, hydrophobic)
  2. Progressive unfolding:

    • Secondary structure disrupted (α-helices, β-sheets unfold)
    • Tertiary structure lost
    • Protein unfolds into random coil
  3. Permanent denaturation:

    • Polypeptide chains may aggregate
    • Disulfide bonds may scramble
    • Irreversible damage
  4. Activity-Temperature Relationship:

    Activity
      ^
      |     /\
      |    /  \
      |   /    \_____ (denaturation)
      |  /
      |_/________________> Temperature
          37°C  80°C
    

Why irreversible: Unlike pH change, heat breaks so many bonds simultaneously that protein cannot refold to native state.

(c) Competitive inhibitor added:

Prediction: 🔽 Enzyme activity reduced but NOT eliminated

Explanation:

  1. Competitive inhibition mechanism:

    • Inhibitor structurally similar to substrate
    • Competes for same active site
    • Reversibly binds to enzyme
  2. Effect on protein structure:

    • No structural change to enzyme!
    • Enzyme remains properly folded
    • Active site unchanged
  3. Kinetic effects:

    • ↑ K_m (apparent affinity for substrate decreases)
    • V_max unchanged (can be overcome with excess substrate)
  4. Equation:

    v=Vmax[S]Km(1+[I]/Ki)+[S]v = \frac{V_{max}[S]}{K_m(1 + [I]/K_i) + [S]}

    where [I] = inhibitor concentration, K_i = inhibitor constant

  5. Key difference:

    • Can be overcome by increasing substrate concentration
    • At high [S], substrate outcompetes inhibitor
    • Eventually reaches V_max

Comparison:

| Condition | Structure Change | Activity | Reversible? | |-----------|-----------------|----------|-------------| | Low pH | Tertiary disrupted | Very low | Yes (if quick) | | High temp | Complete denaturation | Zero | No | | Competitive inh. | None | Reduced | Yes (↑ substrate) |

(a) Denatures (reversible), (b) Denatures (irreversible), (c) Active site blocked (reversible)\boxed{\text{(a) Denatures (reversible), (b) Denatures (irreversible), (c) Active site blocked (reversible)}}

8Problem 8hard

Question:

An enzyme has optimal activity at pH 7.0 and temperature 37°C. Predict and explain what happens to enzyme activity when: (a) pH is changed to 3.0, (b) temperature is increased to 80°C, and (c) a competitive inhibitor is added. Include discussion of protein structure changes.

💡 Show Solution

Enzyme Conditions: Optimal at pH 7.0 and 37°C

(a) pH changed to 3.0 (strongly acidic):

Prediction: ⚠️ Enzyme activity greatly reduced or eliminated

Explanation:

  1. Protonation of amino acids:

    • Acidic pH adds excess H⁺ ions
    • Amino acid R-groups become protonated
    • Charged residues (Asp⁻, Glu⁻) become neutral (AspH, GluH)
    • Basic residues (His, Lys, Arg) become more positive
  2. Disruption of ionic bonds:

    • Salt bridges (electrostatic interactions) break
    • Changes in charge distribution
  3. Tertiary structure denaturation:

    • 3D shape distorts
    • Active site changes shape
    • Substrate can no longer bind properly
  4. Result: Loss of catalytic activity (may be reversible if pH restored quickly)

(b) Temperature increased to 80°C (far above optimum):

Prediction: ⚠️ Enzyme denatured, activity lost permanently

Explanation:

  1. Increased kinetic energy:

    • Molecules vibrate more vigorously
    • Weak bonds break (H-bonds, ionic, hydrophobic)
  2. Progressive unfolding:

    • Secondary structure disrupted (α-helices, β-sheets unfold)
    • Tertiary structure lost
    • Protein unfolds into random coil
  3. Permanent denaturation:

    • Polypeptide chains may aggregate
    • Disulfide bonds may scramble
    • Irreversible damage
  4. Activity-Temperature Relationship:

    Activity
      ^
      |     /\
      |    /  \
      |   /    \_____ (denaturation)
      |  /
      |_/________________> Temperature
          37°C  80°C
    

Why irreversible: Unlike pH change, heat breaks so many bonds simultaneously that protein cannot refold to native state.

(c) Competitive inhibitor added:

Prediction: 🔽 Enzyme activity reduced but NOT eliminated

Explanation:

  1. Competitive inhibition mechanism:

    • Inhibitor structurally similar to substrate
    • Competes for same active site
    • Reversibly binds to enzyme
  2. Effect on protein structure:

    • No structural change to enzyme!
    • Enzyme remains properly folded
    • Active site unchanged
  3. Kinetic effects:

    • ↑ K_m (apparent affinity for substrate decreases)
    • V_max unchanged (can be overcome with excess substrate)
  4. Equation:

    v=Vmax[S]Km(1+[I]/Ki)+[S]v = \frac{V_{max}[S]}{K_m(1 + [I]/K_i) + [S]}

    where [I] = inhibitor concentration, K_i = inhibitor constant

  5. Key difference:

    • Can be overcome by increasing substrate concentration
    • At high [S], substrate outcompetes inhibitor
    • Eventually reaches V_max

Comparison:

| Condition | Structure Change | Activity | Reversible? | |-----------|-----------------|----------|-------------| | Low pH | Tertiary disrupted | Very low | Yes (if quick) | | High temp | Complete denaturation | Zero | No | | Competitive inh. | None | Reduced | Yes (↑ substrate) |

(a) Denatures (reversible), (b) Denatures (irreversible), (c) Active site blocked (reversible)\boxed{\text{(a) Denatures (reversible), (b) Denatures (irreversible), (c) Active site blocked (reversible)}}