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Understand the properties of solids, liquids, and gases, including phase changes, vapor pressure, and the relationship to intermolecular forces.
Learn step-by-step with practice exercises built right in.
The state of matter depends on balance between kinetic energy and intermolecular forces:
| State | Kinetic Energy | IMF Strength | Particle Arrangement |
|---|---|---|---|
| Solid | Low | Strong (KE < IMF) | Fixed, ordered positions |
| Liquid | Medium | Moderate (KE ≈ IMF) | Close but mobile |
| Gas | High |
Explain why ice floats on water, and why this property is unusual compared to most other substances.
Solution:
Given: Ice floats on liquid water Find: Explain why and why this is unusual
Step 1: Recall density principles
General rule: Objects float if less dense than the liquid
For ice to float on water:
| Section | Format | Questions | Time | Weight | Calculator |
|---|---|---|---|---|---|
| Multiple Choice | MCQ | 60 | 90 min | 50% | ✅ |
| Free Response (Long) | FRQ | 3 | 69 min | 30% | ✅ |
| Free Response (Short) | FRQ | 4 | 36 min | 20% | ✅ |
Avoid these 3 frequent errors
See how this math is used in the real world
mol of reacts with mol of . How many grams of water are produced? Which is the limiting reagent? ()
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| Weak (KE > IMF) |
| Far apart, random motion |
Definite shape and volume
High density
Incompressible
Very low compressibility
1. Crystalline Solids
Types of crystalline solids:
a) Ionic Solids
b) Molecular Solids
c) Covalent Network Solids
d) Metallic Solids
2. Amorphous Solids
Triple point: Temperature and pressure where all 3 phases coexist
Normal melting point: Temperature at 1 atm where solid ↔ liquid
Definite volume, no definite shape
High density (similar to solids)
Incompressible
Can flow
1. Viscosity
Definition: Resistance to flow
Factors affecting viscosity:
Examples:
2. Surface Tension
Definition: Energy required to increase surface area of liquid
Cause: Molecules at surface experience net inward force
Factors:
3. Capillary Action
Definition: Spontaneous rise of liquid in narrow tube
Two competing forces:
Adhesion: Attraction between liquid and tube surface
Cohesion: Attraction between liquid molecules (IMFs)
Result:
Meniscus:
4. Vapor Pressure
Definition: Pressure exerted by vapor in equilibrium with liquid
Dynamic equilibrium:
Rate of evaporation = Rate of condensation
Factors affecting vapor pressure:
a) Temperature:
b) IMF Strength:
Volatile liquids: High vapor pressure (weak IMFs)
Nonvolatile liquids: Low vapor pressure (strong IMFs)
Normal Boiling Point: Temperature where vapor pressure = 1 atm (760 mmHg)
No definite shape or volume
Very low density
Highly compressible
Complete mixing
Five postulates:
Gas particles are in constant, random motion
Negligible particle volume
No intermolecular forces
Elastic collisions
Average kinetic energy ∝ Temperature
Cause: Collisions of gas particles with container walls
Factors affecting pressure:
Temperature (↑T → ↑P at constant V, n)
Volume (↓V → ↑P at constant T, n)
Number of moles (↑n → ↑P at constant T, V)
Molar mass (indirect effect)
Endothermic (absorb energy):
Exothermic (release energy): 4. Freezing: Liquid → Solid 5. Condensation: Gas → Liquid 6. Deposition: Gas → Solid (direct)
Enthalpy of fusion (ΔHfus): Energy to melt 1 mole
Enthalpy of vaporization (ΔHvap): Energy to vaporize 1 mole
Key relationship:
Why: More IMFs to break going liquid → gas than solid → liquid
Temperature vs. Heat Added graph:
Features:
Solid heating: Temperature increases
Melting plateau: Temperature constant at melting point
Liquid heating: Temperature increases
Boiling plateau: Temperature constant at boiling point
Gas heating: Temperature increases
Calculation:
(during phase change)
(within one phase)
Relates vapor pressure to temperature:
Where:
Linear form:
Plot: ln P vs. 1/T gives straight line with slope =
Due to hydrogen bonding:
High boiling point (100°C)
High specific heat
High heat of vaporization
Ice less dense than water
High surface tension
| Property | Solid | Liquid | Gas |
|---|---|---|---|
| Shape | Definite | Indefinite | Indefinite |
| Volume | Definite | Definite | Indefinite |
| Density | High | High | Very low |
| Compressibility | Very low | Low | High |
| Particle motion | Vibration | Translation, rotation | Random, rapid |
| IMF importance | Very important | Important | Negligible |
| KE vs IMF | KE < IMF | KE ≈ IMF | KE >> IMF |
This means: Ice has larger volume than same mass of water
Step 2: Typical behavior of substances
Most substances:
Step 3: Explain water's unusual behavior
In liquid water:
In ice (solid water):
Step 4: Why the open structure?
Hydrogen bonding geometry:
In ice:
In liquid water:
Step 5: Quantitative comparison
Ice: 0.917 g/cm³ Water: 1.000 g/cm³
Ratio: Ice is about 8-9% less dense than water
Volume increase: When water freezes, it expands by ~9%
Step 6: Why is this unusual?
For most substances:
For water:
Only a few substances behave this way:
Answer:
Ice floats because it is less dense than liquid water (0.917 g/cm³ vs. 1.000 g/cm³).
Explanation:
In ice, water molecules form a hexagonal crystalline structure where each H₂O molecule forms 4 hydrogen bonds in a tetrahedral arrangement. This creates an open, cage-like structure with large empty spaces between molecules.
In liquid water, H-bonds are constantly breaking and reforming, so molecules are not locked into this rigid structure and can pack more closely together, resulting in higher density.
Why unusual:
For most substances, the solid phase is MORE dense than the liquid because particles pack closer in the ordered solid structure. Water is unusual because the specific geometry required by hydrogen bonding (tetrahedral, 4 H-bonds per molecule) forces molecules APART, creating an open structure that is less dense than the liquid.
Importance:
Without this property, bodies of water would freeze from bottom up, potentially killing aquatic ecosystems.
Two liquids, hexane (C₆H₁₄) and water (H₂O), have similar molar masses (86 g/mol vs. 18 g/mol). However, hexane boils at 69°C while water boils at 100°C. Additionally, hexane has lower viscosity and surface tension than water. Explain these differences in terms of intermolecular forces.
Solution:
Given:
Find: Explain property differences using IMF concepts
Step 1: Identify intermolecular forces in each liquid
Hexane (C₆H₁₄):
Structure: CH₃-CH₂-CH₂-CH₂-CH₂-CH₃ (saturated hydrocarbon)
Lewis structure analysis:
IMFs present:
Water (H₂O):
Lewis structure analysis:
IMFs present:
Step 2: Explain boiling point difference
Expected based on molar mass:
Actual result: Water has higher BP (100°C vs. 69°C)
Explanation:
Type of IMF matters more than size!
Water:
Hexane:
Result: Water boils at higher temperature
Step 3: Explain viscosity difference
Viscosity = resistance to flow
Factors:
Water:
Hexane:
However, note: Water actually has relatively LOW viscosity for a H-bonding liquid because it's so small. Glycerol (3 OH groups) has much higher viscosity.
Step 4: Explain surface tension difference
Surface tension = energy to increase surface area
Cause: Molecules at surface experience net inward pull
Water:
Hexane:
Ratio: Water has ~4× higher surface tension than hexane
Step 5: Summary of IMF effects
Property relationships:
All these properties depend on IMF strength:
\text{Higher boiling point} \\ \text{Higher viscosity} \\ \text{Higher surface tension} \\ \text{Lower vapor pressure} \end{cases}$$ **Answer:** **Boiling Point:** Water (100°C) > Hexane (69°C) because **hydrogen bonding in water is much stronger than London dispersion forces in hexane**, despite hexane having higher molar mass. H-bonding requires more energy to overcome than LDF. **Viscosity:** Water has higher viscosity than hexane because **strong H-bonds resist molecular flow** more than weak LDF, even though hexane is a larger molecule. **Surface tension:** Water has higher surface tension (~73 mN/m) than hexane (~18 mN/m) because **H-bonding creates strong cohesive forces** that pull surface molecules inward, while hexane's weak LDF provide less cohesion. **General principle:** The **type of intermolecular force matters more than molecular size** for determining physical properties. Hydrogen bonding (10-40 kJ/mol) is significantly stronger than London dispersion forces in nonpolar molecules, even large ones. **Summary table:** | Property | Water | Hexane | Reason | |----------|-------|--------|--------| | Molar Mass | 18 g/mol | 86 g/mol | Hexane larger | | IMF Type | H-bonding | LDF only | H-bonding stronger | | BP | 100°C | 69°C | H-bonding > LDF | | Viscosity | Higher | Lower | H-bonding resists flow | | Surface Tension | 73 mN/m | 18 mN/m | H-bonding cohesion |The vapor pressure of water at 25°C is 23.8 mmHg, and at 50°C it is 92.5 mmHg. Use the Clausius-Clapeyron equation to calculate the enthalpy of vaporization (ΔHvap) for water. R = 8.314 J/(mol·K).
Solution:
Given:
Find: ΔHvap for water
Step 1: Write Clausius-Clapeyron equation
Step 2: Identify known and unknown values
Known:
Unknown:
Step 3: Calculate pressure ratio
Step 4: Calculate temperature term
Or more precisely:
Step 5: Substitute into Clausius-Clapeyron equation
Step 6: Solve for ΔHvap
Step 7: Check reasonableness
Literature value: ΔHvap for water ≈ 40.7 kJ/mol at 100°C
Our calculated value: 43.4 kJ/mol
Why slightly higher?
Step 8: Verify with unit analysis
Units:
✓
Answer:
Step-by-step summary:
Physical interpretation:
43.4 kJ/mol is the energy required to convert 1 mole of liquid water to water vapor at constant temperature (around 25-50°C).
This energy is needed to:
Comparison:
Ratio: ΔHvap/ΔHfus ≈ 7.2
Much more energy required for vaporization than melting because:
Alternative approach - Linear form:
Could also use: ln P = -ΔHvap/R × (1/T) + C
Plot ln P vs. 1/T → slope = -ΔHvap/R
This problem uses the two-point form, which is more common for single calculations.