Power
Calculate power in mechanical systems
Power content
📚 Practice Problems
1Problem 1easy
❓ Question:
A crane lifts a 500 kg mass vertically upward 20 meters in 10 seconds at constant velocity. Calculate the power output of the crane.
💡 Show Solution
Step 1: Calculate work done Work = Force × distance Force = weight = mg = 500 kg × 10 m/s² = 5000 N Work = 5000 N × 20 m = 100,000 J
Step 2: Calculate power Power = Work / time P = 100,000 J / 10 s = 10,000 W = 10 kW
The crane outputs 10 kilowatts of power.
2Problem 2easy
❓ Question:
An electric motor has a power rating of 750 W. How much work can it do in 2 minutes?
💡 Show Solution
Given: Power = 750 W Time = 2 minutes = 120 s
Using: Power = Work / time Work = Power × time Work = 750 W × 120 s = 90,000 J = 90 kJ
The motor can do 90 kilojoules of work in 2 minutes.
3Problem 3medium
❓ Question:
A 60 kg student runs up a flight of stairs, rising 5 meters vertically in 4 seconds. What is the student's average power output?
💡 Show Solution
Step 1: Calculate work done against gravity W = mgh W = 60 kg × 10 m/s² × 5 m = 3000 J
Step 2: Calculate average power P = W / t P = 3000 J / 4 s = 750 W
The student's average power output is 750 watts.
Note: This is just the power used to overcome gravity. The actual metabolic power would be higher due to inefficiency.
4Problem 4medium
❓ Question:
A car engine produces 150 horsepower (1 hp = 746 W). If the car is traveling at a constant 30 m/s on a level road, what is the total resistive force (air resistance + friction) acting on the car?
💡 Show Solution
Step 1: Convert power to watts P = 150 hp × 746 W/hp = 111,900 W
Step 2: Use relationship between power, force, and velocity For constant velocity: P = F × v where F is the applied force, which equals resistive force at constant velocity
F = P / v F = 111,900 W / 30 m/s = 3730 N
The total resistive force is 3,730 N.
Physical insight: At constant velocity, the engine force equals resistive forces, and all engine power goes into overcoming resistance.
5Problem 5hard
❓ Question:
A pump is rated at 2.5 kW and has an efficiency of 70%. How long will it take to pump 1000 kg of water from a well that is 15 meters deep?
💡 Show Solution
Step 1: Calculate work needed W = mgh W = 1000 kg × 10 m/s² × 15 m = 150,000 J
Step 2: Account for efficiency Only 70% of input power does useful work Useful power = 0.70 × 2500 W = 1750 W
Step 3: Calculate time t = W / P_useful t = 150,000 J / 1750 W ≈ 85.7 s
It will take approximately 86 seconds (about 1.4 minutes) to pump the water.
Note: The remaining 30% of power is lost as heat, noise, etc.
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