Polynomial Division and Remainder Theorem
Understanding polynomial long division, synthetic division, and the Remainder and Factor Theorems
Polynomial Division and Remainder Theorem
Why Divide Polynomials?
Polynomial division helps us:
- Factor polynomials
- Find zeros of polynomials
- Simplify rational expressions
- Analyze polynomial behavior
Long Division of Polynomials
The process is similar to long division with numbers.
Steps for Polynomial Long Division
- Arrange both polynomials in descending order of powers
- Divide the leading term of the dividend by the leading term of the divisor
- Multiply the result by the divisor
- Subtract from the dividend
- Bring down the next term
- Repeat until the degree of the remainder is less than the degree of the divisor
Example Format
Synthetic Division
Synthetic division is a shortcut for dividing by linear factors of the form .
When to Use Synthetic Division
✓ Divisor is (linear with leading coefficient 1) ✗ Cannot use for divisors like or
Steps for Synthetic Division
- Write (from ) outside the box
- Write coefficients of the dividend inside
- Bring down the first coefficient
- Multiply by , add to next coefficient
- Repeat across all coefficients
- Last number is the remainder
Example Setup
Dividing by :
c & a_n & a_{n-1} & \cdots & a_0 \\ & & ca_n & \cdots & \\ \hline & a_n & b_{n-1} & \cdots & r \end{array}$$ The bottom row gives quotient coefficients and remainder $r$. ## The Remainder Theorem **Remainder Theorem**: When a polynomial $f(x)$ is divided by $(x - c)$, the remainder is $f(c)$. $$f(x) = (x - c) \cdot q(x) + r$$ where $r = f(c)$ ### Why It Matters - Quick way to find remainders without full division - Just evaluate $f(c)$! ## The Factor Theorem **Factor Theorem**: $(x - c)$ is a factor of $f(x)$ if and only if $f(c) = 0$. In other words: - If $f(c) = 0$, then $(x - c)$ divides evenly into $f(x)$ - If the remainder is 0, then $c$ is a zero of $f(x)$ ### Applications 1. **Testing for factors**: Check if $f(c) = 0$ 2. **Finding zeros**: If $(x - c)$ is a factor, then $c$ is a zero 3. **Factoring**: Use known zeros to write factored form ## Rational Zero Theorem If $f(x) = a_nx^n + ... + a_0$ has integer coefficients, then any rational zero $\frac{p}{q}$ must have: - $p$ divides the constant term $a_0$ - $q$ divides the leading coefficient $a_n$ This gives us a list of **possible** rational zeros to test. ## Complete Factorization Strategy 1. Use Rational Zero Theorem to list possible zeros 2. Test candidates using synthetic division or direct evaluation 3. Once you find a zero $c$, factor out $(x - c)$ 4. Repeat on the quotient polynomial 5. Factor completely over the real numbers📚 Practice Problems
1Problem 1medium
❓ Question:
Use synthetic division to divide by .
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Solution:
Step 1: Set up synthetic division with .
The coefficients of are:
2 & 2 & -5 & 1 & 2 \\ & & 4 & -2 & -2 \\ \hline & 2 & -1 & -1 & 0 \end{array}$$ Step 2: Perform the operations. - Bring down 2 - Multiply: $2 \times 2 = 4$, add: $-5 + 4 = -1$ - Multiply: $2 \times (-1) = -2$, add: $1 + (-2) = -1$ - Multiply: $2 \times (-1) = -2$, add: $2 + (-2) = 0$ Step 3: Interpret the result. The bottom row gives: quotient coefficients $2, -1, -1$ and remainder $0$. **Quotient**: $2x^2 - x - 1$ **Remainder**: $0$ Therefore: $$f(x) = (x - 2)(2x^2 - x - 1)$$ Since the remainder is 0, $(x - 2)$ is a factor and $x = 2$ is a zero of $f(x)$. **Answer:** Quotient: $2x^2 - x - 1$, Remainder: $0$2Problem 2easy
❓ Question:
Use the Remainder Theorem to find the remainder when is divided by .
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Solution:
The Remainder Theorem states that the remainder when dividing by is .
Step 1: Identify .
We're dividing by , so .
Step 2: Evaluate .
Answer: The remainder is .
Note: We found this without doing any division!
3Problem 3hard
❓ Question:
Find all rational zeros of and factor completely.
💡 Show Solution
Solution:
Step 1: List possible rational zeros using the Rational Zero Theorem.
Factors of constant term (-6): Factors of leading coefficient (2):
Possible rational zeros:
Step 2: Test candidates.
Try : ✗
Try : ✗
Try : ✓
Step 3: Use synthetic division with .
-2 & 2 & -1 & -13 & -6 \\ & & -4 & 10 & 6 \\ \hline & 2 & -5 & -3 & 0 \end{array}$$ Quotient: $2x^2 - 5x - 3$ Step 4: Factor the quotient. $$2x^2 - 5x - 3 = (2x + 1)(x - 3)$$ Step 5: Write complete factorization. $$f(x) = (x + 2)(2x + 1)(x - 3)$$ **Zeros**: $x = -2, x = -\frac{1}{2}, x = 3$ **Answer:** Zeros are $-2, -\frac{1}{2}, 3$; Factored form: $(x + 2)(2x + 1)(x - 3)$Practice with Flashcards
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