Step 4: Simplify (standard form):
In polar coordinates, we typically use r = 3
(r = -3 represents the same circle)
Step 5: Interpretation:
This is a circle with radius 3 centered at the origin
Answer: r = 3
Explain using:
⚠️ Common Mistakes: Polar Coordinates and Graphs
Avoid these 4 frequent errors
🌍 Real-World Applications: Polar Coordinates and Graphs
See how this math is used in the real world
📝 Worked Example: Related Rates — Expanding Circle
Problem:
A stone is dropped into a still pond, creating a circular ripple. The radius of the ripple is increasing at a rate of 2 cm/s. How fast is the area of the circle increasing when the radius is 10 cm?
Convert between polar and rectangular coordinates, graph polar equations, and understand polar curves.
How can I study Polar Coordinates and Graphs effectively?▾
Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 5 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
Is this Polar Coordinates and Graphs study guide free?▾
Yes — all study notes, flashcards, and practice problems for Polar Coordinates and Graphs on Study Mondo are free to access. No account is needed.
What course covers Polar Coordinates and Graphs?▾
Polar Coordinates and Graphs is part of the AP Precalculus course on Study Mondo, specifically in the Functions Involving Parameters, Vectors, and Matrices section. You can explore the full course for more related topics and practice resources.
Are there practice problems for Polar Coordinates and Graphs?▾
Yes, this page includes 5 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.
Check angle: Point is in Quadrant II with correct ratio ✓
💡 Show Solution
Solution:
Given: x2+y2=4y
Use substitutions:
x=rcos(θ)
y=rsin(θ)
x2+y2=r2
Substitute:r2=4rsin(θ)
Simplify:r2−4rsin(θ)=0r(r
This gives r=0 or r=4sin(θ)
Since r=0 is included in r=4sin(θ) when θ=0 or , we can write:
Answer:r=4sin(θ)
Interpretation: This is a circle with diameter 4 on the line θ=2π (the y-axis).
Verification in rectangular:
r=4sin(θ) means r2=4rsin(θ)
Substituting back: ✓
r=2+2cos(θ)
Step 1: Identify the curve type
This is a limaçon of the form r=a+bcos(θ) where a=2 and b=2.
Since ba=22=1, this is a cardioid (heart-shaped).
Step 2: Check for symmetry
Test symmetry about the polar axis (x-axis):
Replace θ with −θ:
r=2+2cos(−θ)=2+2cos(θ)
Equation unchanged, so symmetric about the polar axis ✓
Step 3: Create table of values
θ
0
3π
2π
32π
π
34π
23π
35π
2π
cos(θ)
1
21
Step 4: Key features
Maximum r: r=4 when θ=0 (rightmost point)
Minimum r: r=0 when θ=π (cusp at origin)
Axis of symmetry: Polar axis (x-axis)
Shape: Heart-shaped curve pointing right
Key points in rectangular coordinates:
θ=0: (4,0)
θ=:
Sketch description:
The curve starts at (4,0), curves upward and left, passes through (0,2), continues to the origin at θ=π forming a cusp, then curves downward through (0,−2), and returns to (4,0). The overall shape resembles a heart lying on its side.
=
−
4sin(θ))=
0
π
x2+y2=4y
Completing the square: x2+(y−2)2=4, a circle centered at (0,2) with radius 2 ✓