Momentum and Collisions
Linear Momentum
p=mv
Newton's second law:
F=dtdp
For constant mass:
F=mdtdv=ma
Conservation of Momentum
When Fext=0:
dtdptotal=0
ptotal=constant
For a system of particles:
ptotal=∑imivi=constant
Impulse
J=∫t1t2Fdt=Δp
Variable Force Example
If F(t)=F0sin(ωt) from t=0 to t=π/ω:
J=∫0π/ωF0sin(ωt)dt=ωF0[−cos(ωt)]0π/ω
J=ωF0(1−(−1))=ω2F0
Elastic Collisions (1D)
Conservation of momentum:
m1v1i+m2v2i=m1v1f+m2v2f
Conservation of kinetic energy:
21m1v1i2+21m2v2i2=21m1v1f2+21m2v2f2
Solutions:
v1f=m1+m2(m1−m2)v1i+2m2v2i
v2f=m1+m2(m2−m1)v2i+2m1v1i
Special Cases
Equal masses (m1=m2):
v1f=v2i,v2f=v1i
(velocities exchange)
Target at rest (v2i=0):
v1f=m1+m2m1−m2v1i,v2f=m1+m22m1v1i
Massive target (m2≫m1, v2i=0):
v1f≈−v1i,v2f≈0
(light object bounces back)
Inelastic Collisions
Momentum conserved, but kinetic energy not conserved.
Perfectly inelastic (objects stick together):
m1v1i+m2v2i=(m1+m2)vf
vf=m1+m2m1v1i+m2v2i
Energy lost:
ΔKE=KEf−KEi=21m1+m2m1m2(v1i−v2i)2
(This energy is converted to heat, deformation, sound, etc.)
Coefficient of Restitution
For partially elastic collisions:
e=∣v1i−v2i∣∣v2f−v1f∣
- e=1: perfectly elastic
- e=0: perfectly inelastic
- 0<e<1: partially elastic
Relative velocity after collision:
v2f−v1f=−e(v2i−v1i)
2D Collisions
Momentum conserved in each direction:
x-component:
m1v1ix+m2v2ix=m1v1fx+m2v2fx
y-component:
m1v1iy+m2v2iy=m1v1fy+m2v2fy
For elastic collisions, also conserve kinetic energy.
Rocket Motion
Variable mass: m(t) decreases as fuel burns.
mdtdv=−vreldtdm+Fext
where vrel is exhaust speed relative to rocket.
In space (Fext=0):
mdv=−vreldm
∫v0vdv′=−vrel∫m0mm′dm′
Δv=vrellnmm0
Tsiolkovsky equation