Moment of Inertia
Calculating moment of inertia using integration, parallel axis theorem
Moment of Inertia
Definition
For discrete point masses:
where is perpendicular distance from rotation axis.
For continuous mass distribution:
where is perpendicular distance from axis.
Common Moments of Inertia
Thin rod about center:
Thin rod about end:
Solid cylinder/disk about axis:
Hollow cylinder about axis:
Solid sphere about diameter:
Hollow sphere about diameter:
Rectangular plate about center:
Calculating I by Integration
Example 1: Thin Rod About End
Rod of length , mass , uniform density.
Linear mass density:
Example 2: Solid Cylinder About Axis
Radius , mass , uniform density .
Use cylindrical shells:
Using :
Example 3: Solid Sphere About Diameter
Sphere of radius , mass .
Use disk method. At distance from center, disk has radius .
After integration:
Parallel Axis Theorem
where:
- = moment about new axis
- = moment about parallel axis through center of mass
- = distance between the two parallel axes
Example: Rod About End
(about center)
(distance from center to end)
Perpendicular Axis Theorem
For planar object in xy-plane:
where axes pass through same point.
Example: Thin Disk
About axis perpendicular to disk through center:
By symmetry:
(moment about diameter)
Composite Objects
For object composed of multiple parts:
Calculate moment of each part (using parallel axis if needed), then sum.
Example: T-Shape
Two identical rods (length , mass each) forming T-shape.
Vertical rod rotating about its end (where horizontal rod attaches):
Horizontal rod about its center (perpendicular to length):
Radius of Gyration
where is radius of gyration.
represents the distance from axis where all mass could be concentrated to give same .
📚 Practice Problems
1Problem 1medium
❓ Question:
Calculate the moment of inertia of a thin uniform rod (mass M = 3.0 kg, length L = 2.0 m) about an axis: (a) through the center perpendicular to the rod, (b) through one end perpendicular to the rod, and (c) verify the parallel axis theorem.
💡 Show Solution
Given:
- M = 3.0 kg
- L = 2.0 m
(a) Through center:
(b) Through one end:
(c) Parallel axis theorem verification:
Parallel axis theorem:
Distance from center to end: m
✓
Verified!
2Problem 2hard
❓ Question:
A thin spherical shell (mass M = 2.0 kg, radius R = 0.5 m) and a solid sphere (same M and R) roll down an incline (θ = 30°) without slipping. Find: (a) the acceleration of each object, (b) which reaches the bottom first, and (c) the ratio of their speeds at the bottom.
💡 Show Solution
Given:
- M = 2.0 kg, R = 0.5 m
- θ = 30°
- Rolling without slipping
(a) Acceleration of each:
For rolling without slipping:
Thin spherical shell:
Solid sphere:
(b) Which reaches bottom first?
Since :
(Less rotational inertia = faster)
(c) Ratio of speeds:
For same distance L down incline:
Sphere is 9% faster!
3Problem 3hard
❓ Question:
Using integration, derive the moment of inertia of a solid cylinder (mass M, radius R, height h) about its central axis. Then calculate for M = 4.0 kg, R = 0.2 m.
💡 Show Solution
Derivation:
Consider cylindrical shells of radius r, thickness dr.
Volume of shell:
Mass of shell:
where density
Moment of inertia contribution:
Total:
Substitute :
Numerical calculation:
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