Static and kinetic friction, motion on inclines with calculus analysis
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fk=μkN
where N is the normal force and typically μs>μk.
Motion with Friction
For an object sliding with kinetic friction:
ma=Fapplied−fk=Fapplied−μkmg
dtdv=mFapplied−μkg
Stopping Distance
Object sliding on horizontal surface with initial velocity v0:
a=−μkg
vdxdv=−μkg
∫v00vdv=−μkg∫0ddx
−21v02=−μkgd
d=2μkgv02
Inclined Planes
For angle θ from horizontal:
Coordinate system: x-axis along incline (positive down), y-axis perpendicular
Weight components:
Parallel to incline: F∥=mgsinθ
Perpendicular: F⊥=mgcosθ
Normal force:N=mgcosθ (when no vertical acceleration)
Sliding Down Incline
With kinetic friction:
ma=mgsinθ−μkmgcosθ
a=g(sinθ−μkcosθ)
Condition for sliding:sinθ>μkcosθ, or tanθ>μk
Velocity after distance d:v2=v02+2ad=v02+2gd(sinθ−μkcosθ)
Critical Angle for Static Friction
Object on the verge of sliding:
fs=μsN
mgsinθc=μsmgcosθc
tanθc=μs
Motion with Time-Dependent Force
Force F(t) applied up an incline:
mdtdv=F(t)−mgsinθ−μkmgcosθ
v(t)=v0+∫0tmF(t′)dt′−gt(sinθ+μkcosθ)
Example: Exponential Force
If F(t)=F0e−t/τ:
v(t)=v0+mF0τ(1−e−t/τ)−gt(sinθ+μkcosθ)
Blocks Connected on Incline
Two blocks (masses m1, m2) connected by rope over pulley:
Block 1 on incline at angle θ, block 2 hanging vertically.