In vacuum, taking curl of Faraday's law and using Ampere-Maxwell:
∇2E
📚 Practice Problems
1Problem 1medium
❓ Question:
A plane electromagnetic wave in vacuum has electric field amplitude E₀ = 600 V/m and frequency f = 5.0 × 10¹⁴ Hz. Find: (a) the magnetic field amplitude B₀, (b) the wavelength λ, and (c) the intensity I of the wave.
Wave equations from Maxwell's equations, properties of EM waves
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Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 3 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
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Electromagnetic Waves is part of the AP Physics C: Electricity & Magnetism course on Study Mondo, specifically in the Maxwell's Equations section. You can explore the full course for more related topics and practice resources.
Are there practice problems for Electromagnetic Waves?
=
μ0ϵ0∂t2∂2E
∇2B=μ0ϵ0∂t2∂2B
These are wave equations with speed:
c=μ0ϵ01=3.00×108 m/s
(Speed of light!)
Plane Wave Solution
Electric field:E=E0sin(kx−ωt)j^
Magnetic field:B=B0sin(kx−ωt)k^
where:
k=2π/λ (wave number)
ω=2πf (angular frequency)
ω=ck (dispersion relation)
Properties of EM Waves
Transverse:E and B perpendicular to propagation direction
Perpendicular to each other:E⊥B
In phase:E and B oscillate together
Right-hand rule:E×B points in propagation direction
Field magnitudes related:BE=c
Energy in EM Wave
Energy density:u=ϵ0E2=μ0B2
(Equal contributions from E and B)
Intensity (average power per area):I=⟨S⟩=21ϵ0cE02=2μ0cE02
A laser beam with intensity I = 1.0 × 10⁴ W/m² is incident normally on a perfectly reflecting mirror of area A = 2.0 cm². Find: (a) the radiation pressure on the mirror, (b) the force on the mirror, and (c) compare this to the force if the mirror were perfectly absorbing.
💡 Show Solution
Given:
I = 1.0 × 10⁴ W/m²
A = 2.0 cm² = 2.0 × 10⁻⁴ m²
c = 3.0 × 10⁸ m/s
Perfectly reflecting
(a) Radiation pressure (reflecting):
For perfect reflection:
P=c2I
P=3.0×1082(1.0×10
P=6.67×10−5 Pa
(b) Force on mirror:
F=PA=(6.67×10−5)(2.0×10
F=1.33×10−8 N=13.3 nN
Very small! But significant for:
Solar sails in space
Optical tweezers (manipulating particles)
Radiation pressure from Sun on comet tails
(c) Perfectly absorbing:
For perfect absorption:
Pabs=cI
Pabs=3.0×10
Fabs=(3.33×10−5)(2.0
Fabs=6.67×10
Reflection produces twice the force as absorption!
Why? Momentum change:
Absorption: Δp = p (from p to 0)
Reflection: Δp = 2p (from +p to -p)
Physics: EM waves carry momentum p=U/c where U is energy
3Problem 3hard
❓ Question:
A plane EM wave traveling in the +x direction has electric field E=E0sin(kx−ωt)j^ where E₀ = 300 V/m, k = 1.0 × 10⁷ m⁻¹, and ω = 3.0 × 10¹⁵ rad/s. Find: (a) the magnetic field vector, (b) verify these satisfy v = ω/k = c, and (c) the Poynting vector and its time-averaged value.
💡 Show Solution
Given:
E=E
▾
Yes, this page includes 3 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.
4
)
−4
)
8
1.0×104
=
3.33×
10−5 Pa
×
10−4)
−9
N
=
6.67
nN
0
sin
(
k
x
−
ωt)j^
E₀ = 300 V/m
k = 1.0 × 10⁷ m⁻¹
ω = 3.0 × 10¹⁵ rad/s
Direction: +x
c = 3.0 × 10⁸ m/s
μ₀ = 4π × 10⁻⁷ T·m/A
(a) Magnetic field:
For EM wave: E⊥B⊥ direction
E is in +y direction, wave travels in +x, so B must be in ±z direction.
Using right-hand rule (E×B points in propagation direction):
j^×k^=i^ ✓