Photoelectric effect, photons, atomic models, energy levels, nuclear physics
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Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 3 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
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Photons and Atomic Physics is part of the AP Physics 2 course on Study Mondo, specifically in the Modern Physics section. You can explore the full course for more related topics and practice resources.
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E=hf=λhc
where:
h = Planck's constant = 6.626×10−34 J·s
f = frequency (Hz)
c = speed of light
λ = wavelength
Higher frequency → higher energy
Gamma rays: Very high E
Radio waves: Very low E
Photoelectric Effect
Light shining on metal can eject electrons!
Key Observations:
Threshold frequencyf0: Below this, NO electrons (even intense light!)
Instantaneous: Electrons ejected immediately
KE depends on f, not intensity
Intensity affects number of electrons, not their energy
Cannot be explained by classical wave theory!
Einstein's Photoelectric Equation
KEmax=hf−ϕ
where:
KEmax = maximum kinetic energy of ejected electron
hf = photon energy
ϕ = work function (minimum energy to eject electron)
At threshold: hf0=ϕ (just enough to eject, KE = 0)
Stopping potentialVs:
eVs=KEmax
Voltage needed to stop most energetic electrons.
💡 Won Nobel Prize 1921! Not for relativity, but photoelectric effect.
De Broglie Wavelength
Particles can behave like waves!
λ=ph=mvh
Matter waves confirmed by electron diffraction experiments!
Larger mass → smaller wavelength
Electron: λ ~ nm (measurable!)
Baseball: λ ~ 10⁻³⁴ m (unmeasurable)
Atomic Models
Rutherford Model (1911):
Nucleus: tiny, massive, positive
Electrons orbit (like planets)
Problem: Accelerating charges radiate → atom should collapse!
Bohr Model (1913):
Electrons in discrete energy levels (orbits)
Only certain radii allowed: rn=n2a0 where a0=0.529 Å
Quantized angular momentum: L=nℏ where ℏ=h/2π
Energy levels (hydrogen):
En=−n213.6 eV
where n = 1, 2, 3, ... (principal quantum number)
n = 1: Ground state, E = -13.6 eV
n = ∞: Ionization, E = 0
Negative energy means bound (need energy to remove electron).
Atomic Transitions
Electron jumps between levels → photon absorbed or emitted!
Energy of photon:Ephoton=∣Ef−Ei∣=hf
Emission (high → low): Photon out
Absorption (low → high): Photon in
Emission spectrum: Discrete lines (fingerprint of element!)
Hydrogen Series:
Lyman (UV): n → 1
Balmer (visible): n → 2
Paschen (IR): n → 3
Heisenberg Uncertainty Principle
Cannot know position and momentum simultaneously with perfect precision!
ΔxΔp≥2ℏ
Also for energy and time:
ΔEΔt≥2ℏ
Not limitation of measurement, but fundamental nature of reality!
💡 Key: More certain about position → less certain about momentum
Nuclear Physics
Nucleus Composition:
Protons: Z (atomic number), charge +e
Neutrons: N, charge 0
Mass number: A = Z + N
Isotopes: Same Z, different N (different A)
Example: 12C vs 14C
Mass-Energy Equivalence
Einstein's most famous equation:
E=mc2
Mass and energy are interchangeable!
Atomic mass unit: 1 u = 1.66×10−27 kg = 931.5 MeV/c²
Binding energy: Mass of separated nucleons > mass of nucleus
Δm=(mass of parts)−(mass of whole)BE=Δmc2
Fusion releases MORE energy per nucleon than fission!
Radioactive Decay
Unstable nuclei decay spontaneously:
Types:
Alpha (α): 4He nucleus, A↓4, Z↓2
Beta (β⁻): Electron, neutron→proton, A same, Z↑1
Gamma (γ): High-energy photon, A and Z same
Half-lifet1/2:
N(t)=N0(21)t/t1/2
After one half-life: 50% remain
After two: 25% remain
After three: 12.5% remain
Conservation Laws
All nuclear reactions must conserve:
Mass-energy: Total E (including mc²) conserved
Charge: Total Z conserved
Mass number: Total A conserved
Momentum: Total p conserved
Problem-Solving Strategy
Photoelectric:
Find photon energy: E=hf or E=hc/λ
Apply: KEmax=hf−ϕ
Check threshold: if f<f0, no electrons!
Atomic transitions:
Find energy levels: En=−13.6/n2 eV
Energy difference: ΔE=∣Ef−Ei∣
Photon: λ=hc/ΔE
Nuclear:
Check conservation (A and Z)
Calculate mass defect: Δm
Energy: E=Δmc2
Common Mistakes
❌ Using wavelength in meters with h in J·s (watch units!)
❌ Thinking intensity affects electron KE (only frequency does!)
❌ Forgetting negative sign in atomic energy levels
❌ Not converting eV to Joules (or vice versa): 1 eV = 1.60×10⁻¹⁹ J
❌ Confusing emission (high→low) with absorption (low→high)
❌ Using half-life formula incorrectly (power is t/t_1/2, not just t!)
Light with wavelength 400 nm strikes a metal surface with work function 2.0 eV. Find (a) maximum kinetic energy of ejected electrons, (b) stopping potential.
A hydrogen atom electron transitions from n=3 to n=2. Find (a) energy of emitted photon, (b) wavelength of light.
💡 Show Solution
Given:
Initial state: ni=3
Final state: nf=2
Hydrogen energy levels: En=−13.6/n2 eV
Part (a): Photon energy
Energy levels:
E3=−3213.6
Photon energy (emission, so high → low):
Ephoton=E3−
In Joules:
E=(1.89)(1.60×10−19)=3.02×10
Part (b): Wavelength
λ=Ehc=
Answer:
(a) E_photon = 1.89 eV
(b) λ = 656 nm (red light, Balmer series!)
This is the famous H-alpha line in hydrogen spectrum.
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Yes, this page includes 3 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.