States of matter, phase transitions, and latent heat
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Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 3 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
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Phase Changes and Latent Heat is part of the AP Physics 2 course on Study Mondo, specifically in the Thermodynamics section. You can explore the full course for more related topics and practice resources.
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Condensation
Deposition
💡 Key Insight: During a phase change, temperature remains constant even as energy is added/removed!
Latent Heat
Latent heat is energy required to change phase without changing temperature.
Heat of Fusion (L_f)
Energy to melt (or freeze) 1 kg of substance:
Q=mLf
For water: Lf=334,000 J/kg = 334 kJ/kg
Heat of Vaporization (L_v)
Energy to vaporize (or condense) 1 kg of substance:
Q=mLv
For water: Lv=2,260,000 J/kg = 2260 kJ/kg
Note: Lv>Lf because you must completely overcome intermolecular forces for vaporization.
Potential energy increases, kinetic energy constant
Both phases coexist at transition temperature
Example: Ice-water mixture stays at 0°C until all ice melts.
Evaporation vs. Boiling
Evaporation
Occurs at surface
Happens at any temperature
Faster molecules escape
Causes cooling (loses high-energy molecules)
Boiling
Occurs throughout liquid
Happens at specific temperature (boiling point)
Vapor pressure equals atmospheric pressure
Bubbles form inside liquid
Important Values for Water
Property
Value
Melting point
0°C (273 K)
Boiling point
100°C (373 K) at 1 atm
L_f (fusion)
334 kJ/kg
L_v (vaporization)
2260 kJ/kg
c_ice
2090 J/kg·°C
c_water
4186 J/kg·°C
c_steam
2010 J/kg·°C
Pressure Dependence
Higher pressure → higher boiling point
Pressure cooker: cooks faster at higher T
Mountain top: water boils below 100°C
Lower pressure → lower boiling point
Vacuum chamber: water boils at room temp
Melting point is less affected by pressure (except for water/ice).
Problem-Solving Strategy
Identify all stages of heating/cooling
Separate into segments:
Temperature changes: Q=mcΔT
Phase changes: Q=mL
Add all energy contributions: Qtotal=∑Qi
Watch for mixed-phase problems (some melts, some doesn't)
Check if enough energy for complete phase change
Common Mistakes
❌ Forgetting temperature is constant during phase change
❌ Using wrong specific heat (ice vs. water vs. steam)
❌ Adding ΔT during phase change (it's zero!)
❌ Confusing L_f and L_v
❌ Not checking if phase change is complete
Lf=334
=334,000
Find: Energy required Q
Solution:
Since ice is already at melting point, only need energy for phase change:
Q=mLf=(2.0)(334,000)=668,000 J=668 kJ
Answer:668 kJ is required to melt the ice
Note: Temperature stays at 0°C during melting!
2Problem 2medium
❓ Question:
How much energy is needed to convert 0.50 kg of ice at -10°C to water at 20°C? (c_ice = 2090 J/kg·°C, L_f = 334 kJ/kg, c_water = 4186 J/kg·°C)
💡 Show Solution
Given:
Mass: m=0.50 kg
Initial: -10°C (ice)
Final: 20°C (water)
Find: Total energy Qtotal
Solution:
Stage 1: Heat ice from -10°C to 0°C
Q1=mciceΔT
Stage 2: Melt ice at 0°C
Q2=mLf=(0.50)(334
Stage 3: Heat water from 0°C to 20°C
Q3=mcwater
Total energy:Qtotal=Q1+Q
Answer:219 kJ is required
Note: Most energy goes to melting (76%), not warming!
3Problem 3hard
❓ Question:
A 0.10 kg piece of ice at 0°C is placed in 0.50 kg of water at 30°C in an insulated container. Does all the ice melt? If so, what is the final temperature? If not, how much ice melts? (L_f = 334 kJ/kg, c_water = 4186 J/kg·°C)
💡 Show Solution
Given:
Ice: mi=0.10 kg at 0°C
Water: mw=0.50 kg at 30°C
Lf=334,000 J/kg, cw=4186 J/kg·°C
Solution:
Step 1: Find maximum energy available from cooling water to 0°C.
Qavailable=m
Step 2: Find energy needed to melt all ice.
Qneeded=mi
Step 3: Compare.
Qavailable=62,790 J>
All ice melts! ✓ Excess energy warms the resulting water.
Step 4: Find final temperature.
Energy conservation:
Qice+Qwater=0
33,400+(0.10)(4186)Tf+(0.50)(4186)(
Answer: All ice melts, final temperature is 11.7°C
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Yes, this page includes 3 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.