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Understanding left-hand and right-hand limits and when they matter
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Sometimes a function behaves differently depending on which direction you approach a point. One-sided limits let us describe this precisely.
The left-hand limit examines the function as we approach from the left (smaller values):
Find and where
| Section | Format | Questions | Time | Weight | Calculator |
|---|---|---|---|---|---|
| Multiple Choice (No Calculator) | MCQ | 30 | 60 min | 33.3% | ๐ซ |
| Multiple Choice (Calculator) | MCQ | 15 | 45 min | 16.7% | โ |
| Free Response (Calculator) | FRQ | 2 | 30 min | 16.7% | โ |
| Free Response (No Calculator) | FRQ | 4 | 60 min | 33.3% | ๐ซ |
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See how this math is used in the real world
A stone is dropped into a still pond, creating a circular ripple. The radius of the ripple is increasing at a rate of cm/s. How fast is the area of the circle increasing when the radius is cm?
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Think of it as: "What happens as we walk toward a from the left side of the number line?"
Key Points:
The right-hand limit examines the function as we approach from the right (larger values):
Think of it as: "What happens as we walk toward a from the right side of the number line?"
Key Points:
For a two-sided limit to exist, both one-sided limits must exist AND be equal!
Consider a piecewise function:
From the left (using ):
From the right (using ):
Since , the two-sided limit does not exist!
One-sided limits are crucial for:
On a graph:
Left-hand limit (approaching from x < 3):
When x < 3, we use the formula
Right-hand limit (approaching from x โฅ 3):
When x โฅ 3, we use the formula
Conclusion:
Since and , and :
The function has a jump discontinuity at x = 3.
Given , find and
First, let's rewrite the absolute value as a piecewise function:
Find lim(xโ3โป) f(x) and lim(xโ3โบ) f(x) where f(x) = { x + 1, if x < 3; 2x - 3, if x โฅ 3 }
Step 1: Find left-hand limit lim(xโ3โป): Approaching 3 from left means x < 3 Use f(x) = x + 1 lim(xโ3โป) (x + 1) = 3 + 1 = 4
Step 2: Find right-hand limit lim(xโ3โบ): Approaching 3 from right means x โฅ 3 Use f(x) = 2x - 3 lim(xโ3โบ) (2x - 3) = 2(3) - 3 = 3
Step 3: Compare: lim(xโ3โป) f(x) = 4 lim(xโ3โบ) f(x) = 3 Since 4 โ 3, lim(xโ3) f(x) does not exist
Answer: lim(xโ3โป) f(x) = 4, lim(xโ3โบ) f(x) = 3, limit DNE
Evaluate lim(xโ0โป) (|x|/x)
Step 1: Understand the absolute value for x < 0: When x < 0, |x| = -x
Step 2: Substitute: |x|/x = (-x)/x = -1 for all x < 0
Step 3: Evaluate the limit: As xโ0 from the left, f(x) = -1 constantly lim(xโ0โป) (|x|/x) = -1
Step 4: Verify with values: x = -0.1: |-0.1|/(-0.1) = 0.1/(-0.1) = -1 โ x = -0.01: |-0.01|/(-0.01) = 0.01/(-0.01) = -1 โ
Answer: -1
For f(x) = 1/(x - 2), find lim(xโ2โป) f(x) and lim(xโ2โบ) f(x).
Step 1: Analyze left-hand limit (xโ2โป): As x approaches 2 from left (x < 2): โข x - 2 approaches 0 from the negative side โข x - 2 is small and negative โข 1/(negative small number) = large negative lim(xโ2โป) 1/(x - 2) = -โ
Step 2: Create table from left: x: 1.9 1.99 1.999 x-2: -0.1 -0.01 -0.001 1/(x-2): -10 -100 -1000 โ -โ
Step 3: Analyze right-hand limit (xโ2โบ): As x approaches 2 from right (x > 2): โข x - 2 approaches 0 from the positive side โข x - 2 is small and positive โข 1/(positive small number) = large positive lim(xโ2โบ) 1/(x - 2) = +โ
Step 4: Create table from right: x: 2.1 2.01 2.001 x-2: 0.1 0.01 0.001 1/(x-2): 10 100 1000 โ +โ
Answer: lim(xโ2โป) f(x) = -โ, lim(xโ2โบ) f(x) = +โ
Left-hand limit (x < 5):
Right-hand limit (x โฅ 5):
Result: