Newton's Third Law and Applications

Action-reaction pairs and force interactions

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Newton's Third Law and Applications

Newton's Third Law

Statement: For every action, there is an equal and opposite reaction.

More precisely: When object A exerts a force on object B, object B exerts an equal magnitude force on object A in the opposite direction.

FA on B=FB on A\vec{F}_{A \text{ on } B} = -\vec{F}_{B \text{ on } A}

Or more compactly: FAB=FBA\vec{F}_{AB} = -\vec{F}_{BA}

Key Characteristics of Action-Reaction Pairs

  1. Equal magnitude: FAB=FBA|F_{AB}| = |F_{BA}|
  2. Opposite directions: One points one way, the other points the opposite way
  3. Same type of force: If one is gravitational, both are gravitational
  4. Different objects: Each force acts on a different object
  5. Simultaneous: Both forces exist at the same time

Identifying Action-Reaction Pairs

Template

"Object A exerts force on object B" ⟺ "Object B exerts force on object A"

Examples

Example 1: Book on table

  • Action: Earth pulls down on book (weight)
  • Reaction: Book pulls up on Earth

NOT action-reaction:

  • Weight (Earth on book) and Normal force (table on book) - these act on the same object!

Example 2: Hammer hits nail

  • Action: Hammer exerts force on nail (to the right)
  • Reaction: Nail exerts force on hammer (to the left)

Example 3: Rocket propulsion

  • Action: Rocket pushes gas backward
  • Reaction: Gas pushes rocket forward

Common Mistakes

Wrong: Normal force and weight are action-reaction pairs ✓ Correct: They act on the same object, so they can't be action-reaction

Wrong: Action happens first, then reaction ✓ Correct: Both happen simultaneously

Wrong: The heavier object exerts more force ✓ Correct: Forces in a pair are always equal magnitude

Why Don't Action-Reaction Forces Cancel?

Action-reaction forces act on different objects, so they don't cancel!

Example: Push a wall

  • You push wall to the right with force FF
  • Wall pushes you to the left with force FF
  • Net force on you: FF to the left (you accelerate backward)
  • Net force on wall: FF to the right (but wall doesn't move—it's also attached to Earth!)

Forces only cancel if they act on the same object.

Applications of Newton's Third Law

Walking

  • Your foot pushes backward on ground
  • Ground pushes forward on your foot (you accelerate forward)
  • Without friction, you can't push on ground → can't walk (like ice skating!)

Swimming

  • You push water backward with your hands
  • Water pushes you forward
  • More water displaced → greater forward force

Rocket Propulsion

  • Engine expels gas backward (action)
  • Gas pushes rocket forward (reaction)
  • Works in space (doesn't need air to "push against")

Tension in Ropes

If rope has negligible mass:

  • Tension is the same throughout the rope
  • Forces at both ends of rope segment are equal and opposite (third law)

Normal Force

  • Object pushes down on surface
  • Surface pushes up on object (normal force)
  • Perpendicular to surface

Internal vs. External Forces

Internal Forces

  • Forces between objects within a system
  • Come in action-reaction pairs
  • Cancel out when considering the system as a whole
  • Example: Tension between two connected blocks

External Forces

  • Forces from outside the system
  • Don't have reaction partners within the system
  • Cause acceleration of the system
  • Example: Friction from ground on a car

For a system: Only external forces affect the motion of the center of mass.

Problem-Solving with Third Law

  1. Identify the two objects in the interaction
  2. Name both forces:
    • Force object A exerts on object B
    • Force object B exerts on object A
  3. Remember: Equal magnitude, opposite direction
  4. Draw separate FBDs for each object if needed
  5. Apply Second Law to each object separately

Connected Objects

When objects are connected (ropes, contact, etc.):

  1. Draw separate FBDs for each object
  2. Apply Newton's Second Law to each object
  3. Use Third Law to relate interaction forces
  4. Solve the system of equations

Example: Two blocks connected by rope

  • Tension force on block 1: TT (pulls block 1)
  • Tension force on block 2: TT (pulls block 2)
  • If rope is massless: same tension throughout

Misconceptions Clarified

Q: If forces are always equal and opposite, how does anything accelerate?

A: Action-reaction forces act on different objects! The net force on each object determines its acceleration.

Q: When a horse pulls a cart, doesn't the cart pull back equally hard on the horse? How does the cart move?

A: Yes, cart pulls on horse (backward) and horse pulls on cart (forward) with equal forces. But these act on different objects!

  • For the cart to accelerate: Forward force from horse > Backward friction on cart
  • The horse accelerates forward because: Ground pushes horse forward > Cart pulls horse backward

Q: If I push a wall and it pushes back equally hard, why do I move but the wall doesn't?

A: The wall is attached to the Earth (huge mass!). The force accelerates you: a=F/ma = F/m. Same force on Earth: a=F/MEarth0a = F/M_{Earth} \approx 0 (negligible).

📚 Practice Problems

1Problem 1easy

Question:

You push on a wall with a force of 5050 N. What is the force the wall exerts on you?

💡 Show Solution

Given:

  • Force you exert on wall: Fyou on wall=50F_{you \text{ on wall}} = 50 N

Find: Force wall exerts on you

Apply Newton's Third Law:

Every action has an equal and opposite reaction. When you push on the wall, the wall pushes back on you.

Fwall on you=Fyou on wallF_{wall \text{ on you}} = -F_{you \text{ on wall}}

Magnitude: Fwall on you=50|F_{wall \text{ on you}}| = 50 N

Direction: Opposite to the force you exerted

Answer: The wall exerts a force of 50 N on you, directed away from the wall (pushing you backward).

Key point: The forces are equal in magnitude but opposite in direction. They act on different objects (you vs. wall), so they don't cancel.

2Problem 2medium

Question:

A 6060 kg astronaut floating in space pushes a 120120 kg satellite with a force of 240240 N. What is the acceleration of: (a) the satellite, (b) the astronaut?

💡 Show Solution

Given:

  • Astronaut mass: mA=60m_A = 60 kg
  • Satellite mass: mS=120m_S = 120 kg
  • Force astronaut exerts on satellite: FA on S=240F_{A \text{ on } S} = 240 N

Part (a): Acceleration of satellite

Apply Newton's Second Law to the satellite: aS=FA on SmS=240120=2 m/s2a_S = \frac{F_{A \text{ on } S}}{m_S} = \frac{240}{120} = 2 \text{ m/s}^2

Direction: In the direction the astronaut pushed

Part (b): Acceleration of astronaut

By Newton's Third Law: FS on A=FA on SF_{S \text{ on } A} = -F_{A \text{ on } S}

Magnitude: FS on A=240|F_{S \text{ on } A}| = 240 N

Direction: Opposite (satellite pushes back on astronaut)

Apply Newton's Second Law to the astronaut: aA=FS on AmA=24060=4 m/s2a_A = \frac{F_{S \text{ on } A}}{m_A} = \frac{240}{60} = 4 \text{ m/s}^2

Direction: Opposite to the satellite's acceleration (astronaut moves backward)

Answers:

  • (a) Satellite acceleration: 2 m/s² (forward)
  • (b) Astronaut acceleration: 4 m/s² (backward)

Key insight: Even though the forces are equal, the accelerations are different because the masses are different! The less massive astronaut accelerates more (a1/ma \propto 1/m).

3Problem 3hard

Question:

A 55 kg book rests on a table. Identify all the forces on the book and state whether any pairs are action-reaction pairs according to Newton's Third Law.

💡 Show Solution

Forces acting on the book:

  1. Weight (W\vec{W} or Fg\vec{F}_g): Earth pulls down on book

    • Magnitude: W=mg=(5)(9.8)=49W = mg = (5)(9.8) = 49 N
    • Direction: Downward
  2. Normal force (N\vec{N} or FN\vec{F}_N): Table pushes up on book

    • Magnitude: N=49N = 49 N (since book is at rest)
    • Direction: Upward

Are weight and normal force action-reaction pairs?

NO! They are not action-reaction pairs because:

  • Both forces act on the same object (the book)
  • Action-reaction pairs must act on different objects
  • They are different types of forces (gravitational vs. contact)

What ARE the action-reaction pairs?

Pair 1: Gravitational forces

  • Action: Earth pulls down on book (weight) = 49 N downward
  • Reaction: Book pulls up on Earth = 49 N upward

Pair 2: Contact forces

  • Action: Book pushes down on table = 49 N downward
  • Reaction: Table pushes up on book (normal force) = 49 N upward

Summary:

  • Weight and normal force act on the book → they balance (net force = 0, so a=0a = 0)
  • The reaction to weight acts on Earth
  • The reaction to normal force acts on the table

Key insight: Just because two forces are equal and opposite doesn't make them an action-reaction pair! They must act on different objects and be the same type of force.