A student performs paper chromatography on a sample of black ink. After the solvent travels 10.0 cm up the paper, three colored spots are visible: a blue spot 8.0 cm from the origin, a red spot 5.0 cm from the origin, and a yellow spot 2.0 cm from the origin. (a) Calculate the Rf value for each pigment. (b) Which pigment is most polar? (c) If the student used a more polar solvent, how would the Rf values change?
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Solution:
Given:
Solvent front distance = 10.0 cm (distance solvent traveled)
Blue spot distance = 8.0 cm from origin
Red spot distance = 5.0 cm from origin
Yellow spot distance = 2.0 cm from origin
Find: (a) Rf values, (b) Most polar pigment, (c) Effect of more polar solvent
Note: Spots still in same order (blue > red > yellow), but all higher
Additional insights:
Why does order stay the same?
Blue always least polar ā always highest Rf
Yellow always most polar ā always lowest Rf
Changing solvent polarity shifts ALL Rf values but maintains order
Practical implications:
Too polar solvent:
All Rf values very high (0.8-1.0)
Poor separation
Spots close together near top
Too nonpolar solvent:
All Rf values very low (0.0-0.2)
Poor separation
Spots close together near bottom
Optimal solvent:
Rf values spread out (0.2-0.8)
Good separation
Easy to distinguish components
Summary of key concepts:
Rf = distance(component) / distance(solvent)
Always between 0 and 1
Characteristic for each compound (under same conditions)
Lower Rf = more polar (for polar stationary phase)
Polar compounds stick to polar paper
More polar solvent ā higher Rf values
Better dissolves polar compounds
Carries them farther
Chromatography separates by polarity
Different affinities for stationary vs mobile phases
2Problem 2medium
ā Question:
A mixture of ethanol (BP 78°C) and water (BP 100°C) is to be separated. (a) Which separation technique would be most appropriate and why? (b) During simple distillation, which component will distill over first? (c) Why can't pure ethanol (100%) be obtained by simple distillation of an ethanol-water mixture? (d) What additional technique could achieve better separation?
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Solution:
Given:
Mixture: Ethanol (CāHā OH) and water (HāO)
BP(ethanol) = 78°C
BP(water) = 100°C
Two miscible liquids (form homogeneous solution)
Find: (a) Best separation technique, (b) Which distills first, (c) Why not 100% pure, (d) Better technique
Part (a): Most appropriate separation technique
Analysis of mixture:
3Problem 3hard
ā Question:
A student needs to separate a mixture containing sand (SiOā), salt (NaCl), and naphthalene (CāāHā, a nonpolar organic solid, sublimes at 80°C). Design a complete separation scheme to isolate each component in pure form. For each step, identify: (i) the technique used, (ii) the property exploited, (iii) what is separated from what. Draw a flow chart of your procedure.
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Solution:
Given mixture components:
Sand (SiOā): Insoluble in water, nonpolar, high melting point, does not sublime
Salt (NaCl): Ionic, very soluble in water, high melting point
Naphthalene (CāāHā): Nonpolar organic solid, insoluble in water, sublimes at 80°C
Objective: Separate and isolate ALL THREE components in pure form
Understand types of mixtures, chromatography, distillation, and techniques for separating components based on physical properties.
How can I study Mixtures and Separation Techniques effectively?ā¾
Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 3 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
Is this Mixtures and Separation Techniques study guide free?ā¾
Yes ā all study notes, flashcards, and practice problems for Mixtures and Separation Techniques on Study Mondo are free to access. No account is needed.
What course covers Mixtures and Separation Techniques?ā¾
Mixtures and Separation Techniques is part of the AP Chemistry course on Study Mondo, specifically in the Intermolecular Forces and Properties section. You can explore the full course for more related topics and practice resources.
Are there practice problems for Mixtures and Separation Techniques?ā¾
Yes, this page includes 3 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.
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fā
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red
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Rfā
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yellow
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Type: Two miscible liquids (form solution)
Cannot use filtration (both dissolved)
Cannot use chromatography easily (not good for large amounts)
Cannot use crystallization (both liquids)
Key property difference:Boiling points
BP difference = 100°C - 78°C = 22°C
Moderate difference
Best technique:DISTILLATION
Why distillation?
Liquids have different BPs
Component with lower BP vaporizes first
Can be selectively evaporated and condensed
Components are miscible
Cannot separate by density/filtration
Need to use volatility difference
Want to purify/collect both components
Distillation allows collection of volatile component
Reason: Separates miscible liquids based on boiling point differences. Ethanol (lower BP) vaporizes first, travels to condenser, and is collected. Water (higher BP) remains in flask.
Part (b): Which component distills first?
Principle: Component with lower boiling point vaporizes first
Comparison:
Ethanol BP: 78°C (lower)
Water BP: 100°C (higher)
During distillation:
Step 1: Heat mixture
Temperature rises toward lowest BP
At ~78°C, ethanol begins to boil
Step 2: Vaporization
Ethanol vaporizes preferentially
Vapor is enriched in ethanol (more ethanol than water in vapor)
Step 3: Condensation
Ethanol vapor enters condenser
Cools back to liquid
Collected as distillate
Answer (b):
EthanolĀ distillsĀ overĀ firstā
Reason: Lower boiling point (78°C < 100°C). Component with lower BP is more volatile and evaporates first.
Part (c): Why can't 100% pure ethanol be obtained?
Key concept: Ethanol-water forms an AZEOTROPE
Azeotrope: Mixture that boils at constant temperature with constant composition
Vapor has same composition as liquid
Cannot be separated further by simple distillation
Ethanol-water azeotrope:
Composition: 95.6% ethanol, 4.4% water (by volume)
Boiling point: 78.1°C
This is as pure as you can get by normal distillation
Why azeotrope forms:
Intermolecular forces:
Ethanol and water form hydrogen bonds with each other
Ethanol: O-H can H-bond
Water: O-H can H-bond
H-bonding between ethanol and water:
C2H5OHā ā ā HāOāH
These interactions:
Stabilize the mixture
Change vapor pressure behavior
Create composition where liquid and vapor have same ratio
Distillation behavior:
Starting with dilute ethanol (e.g., 10% ethanol):
Heat to ~78°C
Vapor enriched in ethanol (more volatile)
Collect distillate (higher % ethanol)
Repeat: gradually increase ethanol concentration
But at 95.6% ethanol:
Reach azeotrope
Vapor composition = liquid composition
Cannot increase ethanol % further
No matter how many times you distill!
Answer (c):
\boxed{\text{Ethanol-water forms an azeotrope at 95.6% ethanol}}
Explanation: At this composition, liquid and vapor have identical composition. Further distillation cannot increase purity beyond 95.6%. Strong hydrogen bonding between ethanol and water creates this constant-boiling mixture.
Part (d): Techniques for better separation
To get > 95.6% ethanol (absolute ethanol), use:
Method 1: Add drying agent
Add anhydrous calcium oxide (CaO) or molecular sieves
Drying agent chemically reacts with or absorbs water
Removes water from azeotrope
Then distill to get pure ethanol
Chemical reaction:
CaO+H2OāCa(OH)2
Method 2: Azeotropic distillation
Add third component (e.g., benzene, cyclohexane)
Forms new azeotrope with water
This azeotrope boils at different temperature
Can distill off water with third component
Leaves pure ethanol
Method 3: Fractional distillation
Won't break azeotrope, but...
Better separation before reaching azeotrope
Uses fractionating column
Multiple vaporization-condensation cycles
Gets to 95.6% more efficiently than simple distillation
For initial question (a) - should specify:
If BP difference is moderate (20-25°C):
Fractional distillation preferred over simple distillation
Better separation
Higher purity
Answer (d):
FractionalĀ distillationĀ (forĀ betterĀ separationĀ toĀ azeotrope)ā\boxed{\text{+ Drying agent (to break azeotrope and get 100% ethanol)}}
Output: SAND (wet, on filter) + Salt solution (filtrate)
Step 4: DRY SAND
Input: Wet sand
Property: Water evaporates
Output: SAND (pure, dry)
Step 5: EVAPORATION
Input: Salt solution
Property: Water evaporates
Output: SALT (pure, dry)
ALTERNATIVE SCHEME (Different order):
Could also start with dissolution:
MIXTURE + ADD WATER
FILTRATION gives: Salt solution + (Sand + Naphthalene)
EVAPORATE salt solution ā SALT
SUBLIMATION of (Sand + Naphthalene) ā NAPHTHALENE
But first scheme is better because:
Sublimation first removes naphthalene without solvents
Cleaner separation
Less contamination risk
DETAILED SUMMARY TABLE:
Step
Technique
Property Used
Separated
Result
1
Sublimation
Sublimes at 80°C
Naphthalene from (sand + salt)
Pure CāāHā
2
Dissolution
Water solubility
Salt dissolves, sand doesn't
Solution + solid
3
Filtration
Particle size
Sand from salt solution
Sand (wet) + filtrate
4
Drying
Volatility
Water from sand
Pure SiOā
5
Evaporation
Volatility
Water from salt
Pure NaCl
KEY CONSIDERATIONS:
Order matters:
Must do sublimation before adding water
If you add water first, naphthalene might stick to sand (harder to separate)
Sublimation is cleanest first step
Temperature control:
Sublimation: ~80°C (not too high or salt might decompose)
Drying sand: 100-110°C (above water BP)
Evaporating salt solution: Can heat to boiling
Purity checks:
Naphthalene: Check melting point (should be 80°C)
Sand: Rinse with water again to ensure no salt
Salt: Could recrystallize for higher purity
Common mistakes to avoid:
ā Filtering before dissolving salt (would trap salt + sand together)
ā Adding water before sublimation (naphthalene hard to remove when wet)
ā Not drying sand properly (would have salt contamination from residual water)