Measures of Center
Mean, median, mode, and range
Mean, Median, and Mode
Measures of Central Tendency
Measures of central tendency describe the "center" or "typical value" of a data set.
Three main measures:
- Mean (average)
- Median (middle value)
- Mode (most frequent)
Each tells us something different about the data!
The Mean (Average)
The mean is the sum of all values divided by the number of values.
Formula: Mean = (sum of all values) / (number of values)
Or: xฬ = (xโ + xโ + xโ + ... + xโ) / n
Example 1: Find the mean of 5, 8, 12, 15, 20
Sum: 5 + 8 + 12 + 15 + 20 = 60 Count: 5 values Mean: 60 รท 5 = 12
Example 2: Find the mean of 3, 7, 9, 10, 11
Sum: 3 + 7 + 9 + 10 + 11 = 40 Count: 5 values Mean: 40 รท 5 = 8
Example 3: Test scores: 85, 90, 78, 92, 88, 95
Sum: 528 Count: 6 Mean: 528 รท 6 = 88
The average test score is 88.
Properties of the Mean
The mean:
- Uses ALL data values
- Can be affected by extreme values (outliers)
- May not be an actual data value
- Is used in further statistical calculations
- Represents "balance point" of data
Example with outlier: Data: 10, 12, 14, 15, 16, 100
Mean = 167 รท 6 = 27.83
The 100 pulls the mean up significantly!
The Median
The median is the middle value when data is arranged in order.
Steps to find median:
- Arrange data in order (least to greatest)
- If odd number of values: median is the middle value
- If even number of values: median is average of two middle values
Example 1 (odd): Find median of 7, 3, 9, 5, 11
Step 1: Order: 3, 5, 7, 9, 11 Step 2: 5 values (odd), so middle is 3rd value Median: 7
Example 2 (even): Find median of 4, 8, 12, 15, 20, 25
Step 1: Already ordered Step 2: 6 values (even), so average 3rd and 4th values Middle values: 12 and 15 Median: (12 + 15) รท 2 = 13.5
Example 3: Data: 85, 90, 78, 92, 88, 95
Ordered: 78, 85, 88, 90, 92, 95 Middle values: 88 and 90 Median: (88 + 90) รท 2 = 89
Properties of the Median
The median:
- Not affected by extreme values (resistant to outliers)
- Always a value that divides data in half
- May or may not be an actual data value
- Better than mean when data has outliers
- Represents the 50th percentile
Example with outlier: Data: 10, 12, 14, 15, 16, 100
Median: (14 + 15) รท 2 = 14.5
The outlier (100) doesn't affect the median!
The Mode
The mode is the value that appears most frequently.
Example 1: Find mode of 3, 5, 7, 5, 9, 5, 11
5 appears three times (most frequent) Mode: 5
Example 2: Test scores: 85, 90, 85, 92, 88, 85, 95
85 appears three times Mode: 85
Example 3: 2, 4, 6, 8, 10
All values appear once No mode (or all values are modes)
Example 4: 1, 2, 2, 3, 3, 4
Both 2 and 3 appear twice Bimodal: modes are 2 and 3
Properties of the Mode
The mode:
- Always an actual data value
- Can have no mode, one mode, or multiple modes
- Useful for categorical data (colors, types, etc.)
- Not affected by extreme values
- Easy to identify in small data sets
Terms:
- Unimodal: one mode
- Bimodal: two modes
- Multimodal: more than two modes
- No mode: all values appear same number of times
Comparing Mean, Median, and Mode
Example: 2, 3, 4, 4, 5, 6, 7, 20
Mean: (2+3+4+4+5+6+7+20) รท 8 = 51 รท 8 = 6.375 Median: (4+5) รท 2 = 4.5 Mode: 4
Observations:
- Mean is pulled up by outlier (20)
- Median better represents "typical" value here
- Mode is most frequent value
When to Use Each Measure
Use MEAN when:
- Data has no extreme outliers
- You want to use all data values
- Data is numerical and roughly symmetric
- You need it for further calculations
Use MEDIAN when:
- Data has outliers or is skewed
- You want the "middle" value
- Income, home prices (often skewed data)
- You want a resistant measure
Use MODE when:
- Data is categorical
- You want the most popular/common value
- Multiple modes are meaningful
- Shoe sizes, favorite colors, etc.
Weighted Mean
A weighted mean gives different values different importance.
Formula: Weighted mean = ฮฃ(value ร weight) / ฮฃ(weights)
Example: Test scores with different weights
Homework (10%): 90 Quiz (20%): 85 Test (70%): 92
Weighted mean = (90ร10 + 85ร20 + 92ร70) / (10+20+70) = (900 + 1700 + 6440) / 100 = 9040 / 100 = 90.4
Overall grade: 90.4%
Example 2: GPA calculation
Course A (3 credits): 4.0 Course B (3 credits): 3.5 Course C (4 credits): 3.0
GPA = (4.0ร3 + 3.5ร3 + 3.0ร4) / (3+3+4) = (12 + 10.5 + 12) / 10 = 34.5 / 10 = 3.45
Finding a Missing Value
Example: Five test scores have mean 85. Four scores are 80, 85, 90, 88. Find the fifth score.
Let x = fifth score Mean = (80 + 85 + 90 + 88 + x) / 5 = 85
Solve: 343 + x = 425 x = 82
The fifth score is 82.
Example 2: Three numbers have mean 12 and median 10. Two numbers are 8 and 10. Find the third.
Since median is 10, and we have 8 and 10, the third number must be โฅ 10.
Order will be: 8, 10, x (where x โฅ 10)
Mean: (8 + 10 + x) / 3 = 12 18 + x = 36 x = 18
Range
The range measures spread (not central tendency).
Formula: Range = maximum value - minimum value
Example: 3, 7, 12, 15, 20
Range = 20 - 3 = 17
The data spans 17 units.
Effect of Outliers
Example: Compare with and without outlier
Original data: 5, 6, 7, 8, 9 Mean: 7 Median: 7 Mode: none
Add outlier: 5, 6, 7, 8, 9, 50 Mean: 85 รท 6 = 14.17 (changed significantly!) Median: (7 + 8) รท 2 = 7.5 (barely changed) Mode: none
Conclusion: Median is more resistant to outliers.
Symmetric vs. Skewed Data
Symmetric distribution: Mean โ Median โ Mode Example: 2, 4, 6, 8, 10 Mean = Median = 6
Right-skewed (positive skew): Mode < Median < Mean Few large values pull mean up Example: 1, 2, 3, 4, 20
Left-skewed (negative skew): Mean < Median < Mode Few small values pull mean down Example: 1, 17, 18, 19, 20
Real-World Applications
Example 1: Salaries Company salaries: 32k, 38k, 250k (CEO)
Mean: 36.5k (better represents typical salary)
Example 2: Test Scores Class scores: 65, 70, 75, 80, 85, 90, 95
Mean = 80 (class average) Median = 80 (middle score) No mode (good distribution)
Example 3: Shoe Sizes Sizes sold: 7, 8, 8, 9, 9, 9, 9, 10, 10, 11
Mode = 9 (stock more size 9s!) Mean = 9 (but can't have size 9.0 shoe)
Data with Frequency Tables
Example: Frequency table of quiz scores
| Score | Frequency | |-------|-----------| | 7 | 2 | | 8 | 5 | | 9 | 8 | | 10 | 3 |
Mean: Sum = (7ร2) + (8ร5) + (9ร8) + (10ร3) = 14 + 40 + 72 + 30 = 156 Count = 2 + 5 + 8 + 3 = 18 Mean = 156 รท 18 = 8.67
Median: 18 values, so median is average of 9th and 10th values Looking at cumulative: 2, 7, 15, 18 9th and 10th values are both 9 Median = 9
Mode: 9 appears 8 times (most frequent) Mode = 9
Quartiles (Preview)
Quartiles divide data into four parts:
- Q1: 25th percentile (lower quartile)
- Q2: 50th percentile (median)
- Q3: 75th percentile (upper quartile)
Example: 2, 4, 6, 8, 10, 12, 14, 16, 18
Median (Q2) = 10 Lower half: 2, 4, 6, 8 โ Q1 = 5 Upper half: 12, 14, 16, 18 โ Q3 = 15
Common Mistakes to Avoid
-
Forgetting to order data for median Always sort first!
-
Not averaging two middle values for even count With 6 values, median = average of 3rd and 4th
-
Confusing mean with median Mean = average, Median = middle
-
Saying "no mode" when values appear once Either say "no mode" or "all values are modes"
-
Not using all data values for mean Include every value in the sum
-
Arithmetic errors Double-check calculations!
Choosing the Best Measure
Scenario 1: Average income in a neighborhood with one billionaire โ Use MEDIAN (outliers present)
Scenario 2: Average test score for class โ Use MEAN (symmetric data, no outliers)
Scenario 3: Most popular ice cream flavor โ Use MODE (categorical data)
Scenario 4: Typical home price โ Use MEDIAN (often skewed data)
Effect of Transformations
Adding a constant to all values: Mean, median, and mode all increase by that constant
Example: 2, 4, 6, 8 (mean = 5) Add 3 to each: 5, 7, 9, 11 (mean = 8)
Multiplying all values by constant: Mean, median, and mode all multiply by that constant
Example: 2, 4, 6, 8 (mean = 5) Multiply by 2: 4, 8, 12, 16 (mean = 10)
Box Plots Connection
Box plot (box-and-whisker plot) shows:
- Minimum
- Q1 (lower quartile)
- Median (Q2)
- Q3 (upper quartile)
- Maximum
The median is the line inside the box!
Calculator Tips
Most calculators have statistical functions:
- Enter data into lists
- Calculate 1-variable statistics
- Get mean (xฬ), median (Med), etc.
Verify by hand for small datasets!
Quick Reference
Mean: Sum รท Count
Median: Middle value (ordered data)
- Odd count: middle value
- Even count: average of two middle values
Mode: Most frequent value
Best measure:
- Symmetric data โ Mean
- Skewed/outliers โ Median
- Categorical โ Mode
Practice Strategy
Level 1: Small datasets (5-7 values) Find mean, median, mode
Level 2: Even vs. odd counts Practice both median cases
Level 3: Data with outliers Compare mean and median
Level 4: Find missing values Given mean or median, find unknown
Level 5: Real-world applications Decide which measure to use
Tips for Success
- Always organize data first
- Check if count is odd or even for median
- Remember mean uses ALL values
- Median is resistant to outliers
- Mode can be "none" or multiple values
- Double-check arithmetic
- Think about which measure makes sense for the context
- Practice with real-world examples
- Understand when each measure is most useful
- Use estimation to check if answers are reasonable
๐ Practice Problems
1Problem 1easy
โ Question:
Find the mean of: 8, 12, 15, 10, 5
๐ก Show Solution
Step 1: Understand that mean is the average. Formula: Mean = (sum of all values) / (number of values)
Step 2: Add all the values: 8 + 12 + 15 + 10 + 5 = 50
Step 3: Count how many values there are: There are 5 values
Step 4: Divide the sum by the count: Mean = 50 / 5 = 10
Answer: The mean is 10
2Problem 2easy
โ Question:
Find the median of: 3, 7, 2, 9, 5, 8, 6
๐ก Show Solution
Step 1: Put the numbers in order from least to greatest: 2, 3, 5, 6, 7, 8, 9
Step 2: Find the middle number: Since there are 7 numbers (odd), the middle one is the 4th number
Step 3: Identify the median: 2, 3, 5, [6], 7, 8, 9 โ middle
Answer: The median is 6
3Problem 3easy
โ Question:
Find the mean of:
๐ก Show Solution
Add all values and divide by the count:
Answer: Mean = 6
4Problem 4medium
โ Question:
Find the median of:
๐ก Show Solution
Step 1: Order the data
Step 2: Find the middle There are 6 values (even), so the median is the average of the 3rd and 4th values:
Answer: Median = 10
5Problem 5medium
โ Question:
Find the median of: 12, 18, 15, 20, 14, 16
๐ก Show Solution
Step 1: Put the numbers in order from least to greatest: 12, 14, 15, 16, 18, 20
Step 2: Since there are 6 numbers (even), find the two middle numbers: 12, 14, [15, 16], 18, 20 โ โ middle two
Step 3: Average the two middle numbers: Median = (15 + 16) / 2 = 31 / 2 = 15.5
Answer: The median is 15.5
6Problem 6medium
โ Question:
Find the mode(s) of: 5, 8, 3, 8, 2, 9, 8, 5, 3
๐ก Show Solution
Step 1: Count how many times each number appears: 2: appears 1 time 3: appears 2 times 5: appears 2 times 8: appears 3 times โ most frequent 9: appears 1 time
Step 2: Identify the number(s) that appear most often: 8 appears 3 times, which is more than any other number
Answer: The mode is 8
7Problem 7medium
โ Question:
Find the mean, median, mode, and range of:
๐ก Show Solution
Mean:
Median: Order: Middle value (4th): 7
Mode: 7 appears 3 times (most frequent): 7
Range:
Answer: Mean = 6, Median = 7, Mode = 7, Range = 8
8Problem 8hard
โ Question:
The mean of five test scores is 84. Four of the scores are 78, 85, 90, and 82. What is the fifth score?
๐ก Show Solution
Step 1: Write what we know: Mean = 84 Number of scores = 5 Four scores: 78, 85, 90, 82 Fifth score = ?
Step 2: Use the mean formula: Mean = (sum of all scores) / (number of scores) 84 = (sum of all 5 scores) / 5
Step 3: Multiply both sides by 5: 84 ร 5 = sum of all 5 scores 420 = sum of all 5 scores
Step 4: Add the four known scores: 78 + 85 + 90 + 82 = 335
Step 5: Subtract from the total to find the fifth score: 420 - 335 = 85
Step 6: Check: (78 + 85 + 90 + 82 + 85) / 5 = 420 / 5 = 84 โ
Answer: The fifth score is 85
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