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Mean, median, mode, and range
Learn step-by-step with practice exercises built right in.
Measures of central tendency describe the "center" or "typical value" of a data set.
Three main measures:
Each tells us something different about the data!
The mean is the sum of all values divided by the number of values.
Formula: Mean = (sum of all values) / (number of values)
Or: x̄ = (x₁ + x₂ + x₃ + ... + xₙ) / n
Example 1: Find the mean of 5, 8, 12, 15, 20
Sum: 5 + 8 + 12 + 15 + 20 = 60 Count: 5 values Mean: 60 ÷ 5 = 12
Example 2: Find the mean of 3, 7, 9, 10, 11
Sum: 3 + 7 + 9 + 10 + 11 = 40 Count: 5 values Mean: 40 ÷ 5 = 8
Example 3: Test scores: 85, 90, 78, 92, 88, 95
Find the mean of: 8, 12, 15, 10, 5
Step 1: Understand that mean is the average. Formula: Mean = (sum of all values) / (number of values)
Step 2: Add all the values: 8 + 12 + 15 + 10 + 5 = 50
Step 3: Count how many values there are: There are 5 values
Step 4: Divide the sum by the count: Mean = 50 / 5 = 10
Answer: The mean is 10
Avoid these 3 frequent errors
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Sum: 528 Count: 6 Mean: 528 ÷ 6 = 88
The average test score is 88.
The mean:
Example with outlier: Data: 10, 12, 14, 15, 16, 100
Mean = 167 ÷ 6 = 27.83
The 100 pulls the mean up significantly!
The median is the middle value when data is arranged in order.
Steps to find median:
Example 1 (odd): Find median of 7, 3, 9, 5, 11
Step 1: Order: 3, 5, 7, 9, 11 Step 2: 5 values (odd), so middle is 3rd value Median: 7
Example 2 (even): Find median of 4, 8, 12, 15, 20, 25
Step 1: Already ordered Step 2: 6 values (even), so average 3rd and 4th values Middle values: 12 and 15 Median: (12 + 15) ÷ 2 = 13.5
Example 3: Data: 85, 90, 78, 92, 88, 95
Ordered: 78, 85, 88, 90, 92, 95 Middle values: 88 and 90 Median: (88 + 90) ÷ 2 = 89
The median:
Example with outlier: Data: 10, 12, 14, 15, 16, 100
Median: (14 + 15) ÷ 2 = 14.5
The outlier (100) doesn't affect the median!
The mode is the value that appears most frequently.
Example 1: Find mode of 3, 5, 7, 5, 9, 5, 11
5 appears three times (most frequent) Mode: 5
Example 2: Test scores: 85, 90, 85, 92, 88, 85, 95
85 appears three times Mode: 85
Example 3: 2, 4, 6, 8, 10
All values appear once No mode (or all values are modes)
Example 4: 1, 2, 2, 3, 3, 4
Both 2 and 3 appear twice Bimodal: modes are 2 and 3
The mode:
Terms:
Example: 2, 3, 4, 4, 5, 6, 7, 20
Mean: (2+3+4+4+5+6+7+20) ÷ 8 = 51 ÷ 8 = 6.375 Median: (4+5) ÷ 2 = 4.5 Mode: 4
Observations:
Use MEAN when:
Use MEDIAN when:
Use MODE when:
A weighted mean gives different values different importance.
Formula: Weighted mean = Σ(value × weight) / Σ(weights)
Example: Test scores with different weights
Homework (10%): 90 Quiz (20%): 85 Test (70%): 92
Weighted mean = (90×10 + 85×20 + 92×70) / (10+20+70) = (900 + 1700 + 6440) / 100 = 9040 / 100 = 90.4
Overall grade: 90.4%
Example 2: GPA calculation
Course A (3 credits): 4.0 Course B (3 credits): 3.5 Course C (4 credits): 3.0
GPA = (4.0×3 + 3.5×3 + 3.0×4) / (3+3+4) = (12 + 10.5 + 12) / 10 = 34.5 / 10 = 3.45
Example: Five test scores have mean 85. Four scores are 80, 85, 90, 88. Find the fifth score.
Let x = fifth score Mean = (80 + 85 + 90 + 88 + x) / 5 = 85
Solve: 343 + x = 425 x = 82
The fifth score is 82.
Example 2: Three numbers have mean 12 and median 10. Two numbers are 8 and 10. Find the third.
Since median is 10, and we have 8 and 10, the third number must be ≥ 10.
Order will be: 8, 10, x (where x ≥ 10)
Mean: (8 + 10 + x) / 3 = 12 18 + x = 36 x = 18
The range measures spread (not central tendency).
Formula: Range = maximum value - minimum value
Example: 3, 7, 12, 15, 20
Range = 20 - 3 = 17
The data spans 17 units.
Example: Compare with and without outlier
Original data: 5, 6, 7, 8, 9 Mean: 7 Median: 7 Mode: none
Add outlier: 5, 6, 7, 8, 9, 50 Mean: 85 ÷ 6 = 14.17 (changed significantly!) Median: (7 + 8) ÷ 2 = 7.5 (barely changed) Mode: none
Conclusion: Median is more resistant to outliers.
Symmetric distribution: Mean ≈ Median ≈ Mode Example: 2, 4, 6, 8, 10 Mean = Median = 6
Right-skewed (positive skew): Mode < Median < Mean Few large values pull mean up Example: 1, 2, 3, 4, 20
Left-skewed (negative skew): Mean < Median < Mode Few small values pull mean down Example: 1, 17, 18, 19, 20
Example 1: Salaries Company salaries: 32k, 38k, 250k (CEO)
Mean: 36.5k (better represents typical salary)
Example 2: Test Scores Class scores: 65, 70, 75, 80, 85, 90, 95
Mean = 80 (class average) Median = 80 (middle score) No mode (good distribution)
Example 3: Shoe Sizes Sizes sold: 7, 8, 8, 9, 9, 9, 9, 10, 10, 11
Mode = 9 (stock more size 9s!) Mean = 9 (but can't have size 9.0 shoe)
Example: Frequency table of quiz scores
| Score | Frequency |
|---|---|
| 7 | 2 |
| 8 | 5 |
| 9 | 8 |
| 10 | 3 |
Mean: Sum = (7×2) + (8×5) + (9×8) + (10×3) = 14 + 40 + 72 + 30 = 156 Count = 2 + 5 + 8 + 3 = 18 Mean = 156 ÷ 18 = 8.67
Median: 18 values, so median is average of 9th and 10th values Looking at cumulative: 2, 7, 15, 18 9th and 10th values are both 9 Median = 9
Mode: 9 appears 8 times (most frequent) Mode = 9
Quartiles divide data into four parts:
Example: 2, 4, 6, 8, 10, 12, 14, 16, 18
Median (Q2) = 10 Lower half: 2, 4, 6, 8 → Q1 = 5 Upper half: 12, 14, 16, 18 → Q3 = 15
Forgetting to order data for median Always sort first!
Not averaging two middle values for even count With 6 values, median = average of 3rd and 4th
Confusing mean with median Mean = average, Median = middle
Saying "no mode" when values appear once Either say "no mode" or "all values are modes"
Not using all data values for mean Include every value in the sum
Arithmetic errors Double-check calculations!
Scenario 1: Average income in a neighborhood with one billionaire → Use MEDIAN (outliers present)
Scenario 2: Average test score for class → Use MEAN (symmetric data, no outliers)
Scenario 3: Most popular ice cream flavor → Use MODE (categorical data)
Scenario 4: Typical home price → Use MEDIAN (often skewed data)
Adding a constant to all values: Mean, median, and mode all increase by that constant
Example: 2, 4, 6, 8 (mean = 5) Add 3 to each: 5, 7, 9, 11 (mean = 8)
Multiplying all values by constant: Mean, median, and mode all multiply by that constant
Example: 2, 4, 6, 8 (mean = 5) Multiply by 2: 4, 8, 12, 16 (mean = 10)
Box plot (box-and-whisker plot) shows:
The median is the line inside the box!
Most calculators have statistical functions:
Verify by hand for small datasets!
Mean: Sum ÷ Count
Median: Middle value (ordered data)
Mode: Most frequent value
Best measure:
Level 1: Small datasets (5-7 values) Find mean, median, mode
Level 2: Even vs. odd counts Practice both median cases
Level 3: Data with outliers Compare mean and median
Level 4: Find missing values Given mean or median, find unknown
Level 5: Real-world applications Decide which measure to use
Find the mean of:
Add all values and divide by the count:
Answer: Mean = 6
Find the median of: 3, 7, 2, 9, 5, 8, 6
Step 1: Put the numbers in order from least to greatest: 2, 3, 5, 6, 7, 8, 9
Step 2: Find the middle number: Since there are 7 numbers (odd), the middle one is the 4th number
Step 3: Identify the median: 2, 3, 5, [6], 7, 8, 9 ↑ middle
Answer: The median is 6
Find the median of:
Step 1: Order the data
Step 2: Find the middle There are 6 values (even), so the median is the average of the 3rd and 4th values:
Answer: Median = 10
Find the median of: 12, 18, 15, 20, 14, 16
Step 1: Put the numbers in order from least to greatest: 12, 14, 15, 16, 18, 20
Step 2: Since there are 6 numbers (even), find the two middle numbers: 12, 14, [15, 16], 18, 20 ↑ ↑ middle two
Step 3: Average the two middle numbers: Median = (15 + 16) / 2 = 31 / 2 = 15.5
Answer: The median is 15.5
Find the mode(s) of: 5, 8, 3, 8, 2, 9, 8, 5, 3
Step 1: Count how many times each number appears: 2: appears 1 time 3: appears 2 times 5: appears 2 times 8: appears 3 times ← most frequent 9: appears 1 time
Step 2: Identify the number(s) that appear most often: 8 appears 3 times, which is more than any other number
Answer: The mode is 8
Find the mean, median, mode, and range of:
Mean:
Median: Order: Middle value (4th): 7
Mode: 7 appears 3 times (most frequent): 7
Range:
Answer: Mean = 6, Median = 7, Mode = 7, Range = 8
The mean of five test scores is 84. Four of the scores are 78, 85, 90, and 82. What is the fifth score?
Step 1: Write what we know: Mean = 84 Number of scores = 5 Four scores: 78, 85, 90, 82 Fifth score = ?
Step 2: Use the mean formula: Mean = (sum of all scores) / (number of scores) 84 = (sum of all 5 scores) / 5
Step 3: Multiply both sides by 5: 84 × 5 = sum of all 5 scores 420 = sum of all 5 scores
Step 4: Add the four known scores: 78 + 85 + 90 + 82 = 335
Step 5: Subtract from the total to find the fifth score: 420 - 335 = 85
Step 6: Check: (78 + 85 + 90 + 82 + 85) / 5 = 420 / 5 = 84 ✓
Answer: The fifth score is 85