Magnetic Fields and Forces
Magnetic fields, forces on moving charges, forces on current-carrying wires, torque on current loops
Try the Interactive Version!
Learn step-by-step with practice exercises built right in.
🧲 Magnetic Fields and Forces
Magnetic Field
Magnetic field is a vector field created by moving charges.
Unit: Tesla (T) = N/(A·m) = kg/(A·s²)
Also: Gauss (G) where 1 T = 10⁴ G
Earth's field: ~0.5 G = 5 × 10⁻⁵ T
Sources of Magnetic Fields
- Permanent magnets: Aligned atomic magnetic moments
- Moving charges: Create B field
- Current-carrying wires: Moving charges → B field
- Electromagnets: Coils of wire with current
Magnetic Poles:
- North and South (like charges, but no magnetic monopoles!)
- Like poles repel, opposite poles attract
- Field lines: N → S outside magnet
Force on Moving Charge
Magnitude:
where is angle between and .
Direction: Right-Hand Rule #1
- Point fingers along (velocity)
- Curl fingers toward (field)
- Thumb points along (force) for positive charge
For negative charge: Force is opposite!
Key Points:
- : Maximum force ()
- or : No force (parallel or anti-parallel)
- Force is perpendicular to both and
- No work done (F ⊥ v, so F·v = 0)
Circular Motion in B Field
If , charge moves in circle!
Magnetic force provides centripetal force:
Radius of orbit:
Period:
Frequency (cyclotron frequency):
💡 Note: Period and frequency are independent of v and r!
Applications: Mass Spectrometer
Separates ions by mass:
- Ions accelerated through V
- Enter perpendicular B field
- Radius depends on m/q ratio
- Heavier ions have larger radius
Force on Current-Carrying Wire
Current = moving charges, so wire in B field experiences force!
Magnitude:
where:
- I = current (A)
- L = length of wire in field (m)
- = angle between wire and B field
Direction: Right-Hand Rule #2
- Point fingers along current direction
- Curl toward
- Thumb = force direction
Maximum force: Wire perpendicular to B () No force: Wire parallel to B
Force Between Parallel Wires
Two parallel wires carrying currents:
where:
- T·m/A (permeability of free space)
- d = distance between wires
Same direction currents: Attract Opposite direction currents: Repel
💡 This defines the Ampere! 1 A = current that produces 2×10⁻⁷ N/m force between parallel wires 1 m apart.
Torque on Current Loop
Rectangular loop (sides a and b) in B field:
where:
- N = number of turns
- I = current
- A = area of loop
- = angle between normal to loop and B field
Magnetic dipole moment: (A·m²)
Maximum torque: Loop perpendicular to B () Equilibrium: Loop parallel to B ()
Applications: Electric Motor
- Current through loop in B field
- Torque rotates loop
- Commutator reverses current every half-turn
- Continuous rotation!
Magnetic Field of Long Straight Wire
Direction: Right-Hand Rule #3 (Grip Rule)
- Thumb along current
- Fingers curl around wire → B field direction
Field forms circles around wire.
Magnetic Field of Solenoid
Long coil of wire (N turns, length L):
Inside (uniform field):
where n = N/L = turns per unit length
Outside: B ≈ 0
Solenoid is like bar magnet with N and S poles!
Problem-Solving Strategy
- Identify: Charge or current in B field?
- Find angle between v (or I) and B
- Calculate magnitude: F = qvB sinθ or F = BIL sinθ
- Find direction: Right-hand rule
- For circular motion: Use r = mv/qB
Common Mistakes
❌ Forgetting sin θ term ❌ Wrong right-hand rule (for negative charges) ❌ Confusing E and B field formulas ❌ Saying magnetic force does work (it doesn't! F ⊥ v) ❌ Using v when parallel to B (F = 0) ❌ Wrong units (convert G to T, cm to m)
📚 Practice Problems
1Problem 1easy
❓ Question:
An electron (q = -1.6×10⁻¹⁹ C, m = 9.11×10⁻³¹ kg) moves at 2.0×10⁶ m/s perpendicular to a 0.50 T magnetic field. Find (a) the magnetic force, (b) the radius of its circular path.
💡 Show Solution
Given:
- Charge: C
- Mass: kg
- Velocity: m/s
- B field: T
- Angle: (perpendicular)
Part (a): Magnetic force
(Direction: Use right-hand rule, then reverse for negative charge)
Part (b): Radius of circular path
Very small radius!
Answer:
- (a) F = 1.6 × 10⁻¹³ N
- (b) r = 0.023 mm
2Problem 2medium
❓ Question:
A straight wire carries 10 A current. A 0.30 m section lies perpendicular to a 0.80 T magnetic field. What is the magnetic force on this section?
💡 Show Solution
Given:
- Current: A
- Length: m
- B field: T
- Angle: (perpendicular)
Solution:
Force on current-carrying wire:
Direction: Use right-hand rule #2
- Fingers along current
- Curl toward B field
- Thumb = force direction
Answer: F = 2.4 N
3Problem 3hard
❓ Question:
A rectangular loop (10 cm × 5 cm) with 20 turns carries 3.0 A current. It is placed in a 0.40 T field with its plane at 30° to the field. Find the torque on the loop.
💡 Show Solution
Given:
- Dimensions: 10 cm × 5 cm
- Number of turns:
- Current: A
- B field: T
- Angle: Plane at 30° to field
Solution:
Step 1: Find area.
Step 2: Find angle θ. If plane is at 30° to field, then normal to plane is at 60° to field!
Step 3: Calculate torque.
Answer: τ = 0.052 N·m = 52 mN·m
(Torque tends to align loop with field)