Step 1: Rewrite as an exponential equation: log₁₀ 1000 = x means 10ˣ = 1000

Step 2: Express 1000 as a power of 10: 1000 = 10³

Step 3: Therefore: log₁₀ 1000 = 3

Step 4: Note: log₁₀ is called the "common logarithm" Often written as just "log" without the base

Answer: 3

Use quotient, product, and power rules:

Step 1: Apply quotient rule $\log_5\left(\frac{x^3y}{z^2}\right) = \log_5(x^3y) - \log_5(z^2)$

Step 1: Recall the relationship: bˣ = y is equivalent to logᵦ y = x

Step 2: Identify the parts: Base (b) = 5 Exponent (x) = 3 Result (y) = 125

Step 3: Write in logarithmic form: log₅ 125 = 3

Step 4: Verify: "5 to what power equals 125?" 5³ = 125 ✓

Answer: log₅ 125 = 3

Step 1: Use the product rule: logᵦ m + logᵦ n = logᵦ(mn)

Step 2: Apply the rule: log₃ 27 + log₃ 9 = log₃(27 · 9) = log₃ 243

Step 3: Evaluate log₃ 243: What power of 3 equals 243? 3¹ = 3 3² = 9 3³ = 27 3⁴ = 81 3⁵ = 243

Step 4: Therefore: log₃ 243 = 5

Alternative - evaluate first: log₃ 27 = 3 (since 3³ = 27) log₃ 9 = 2 (since 3² = 9) 3 + 2 = 5 ✓

Answer: 5

Step 1: Use product rule (combine logs) $\log_2[(x + 3)(x - 3)] = 4$

Step 1: Apply the quotient rule: logᵦ(m/n) = logᵦ m - logᵦ n

log₂(8x³/y²) = log₂(8x³) - log₂(y²)

Step 2: Apply the product rule to first term: logᵦ(mn) = logᵦ m + logᵦ n

log₂(8x³) = log₂ 8 + log₂ x³

Step 3: Apply the power rule: logᵦ(mⁿ) = n logᵦ m

log₂ x³ = 3 log₂ x log₂ y² = 2 log₂ y

Step 4: Combine all parts: log₂(8x³/y²) = log₂ 8 + 3 log₂ x - 2 log₂ y

Step 5: Simplify log₂ 8: log₂ 8 = 3 (since 2³ = 8)

Step 6: Final answer: 3 + 3 log₂ x - 2 log₂ y

Answer: 3 + 3 log₂ x - 2 log₂ y