Logarithmic Functions

Understanding and evaluating logarithms

Logarithmic Functions

Definition

A logarithm is the inverse of an exponential function.

logb(x)=ymeansby=x\log_b(x) = y \quad \text{means} \quad b^y = x

Read as: "log base bb of xx equals yy"

Example: log2(8)=3\log_2(8) = 3 because 23=82^3 = 8

Common Logarithms

Common log: log(x)\log(x) means log10(x)\log_{10}(x)

Natural log: ln(x)\ln(x) means loge(x)\log_e(x) where e2.718e \approx 2.718

Properties of Logarithms

Product Rule: logb(MN)=logb(M)+logb(N)\log_b(MN) = \log_b(M) + \log_b(N)

Quotient Rule: logb(MN)=logb(M)logb(N)\log_b\left(\frac{M}{N}\right) = \log_b(M) - \log_b(N)

Power Rule: logb(Mp)=plogb(M)\log_b(M^p) = p \cdot \log_b(M)

Change of Base: logb(x)=log(x)log(b)\log_b(x) = \frac{\log(x)}{\log(b)}

Special Values

  • logb(1)=0\log_b(1) = 0 (because b0=1b^0 = 1)
  • logb(b)=1\log_b(b) = 1 (because b1=bb^1 = b)
  • logb(bx)=x\log_b(b^x) = x
  • blogb(x)=xb^{\log_b(x)} = x

📚 Practice Problems

1Problem 1easy

Question:

Evaluate: log3(81)\log_3(81)

💡 Show Solution

We need to find: log3(81)=?\log_3(81) = ?

This asks: "3 to what power equals 81?"

3?=813^? = 81

Since 34=813^4 = 81: log3(81)=4\log_3(81) = 4

Answer: 44

2Problem 2medium

Question:

Expand using log properties: log5(x3yz2)\log_5(\frac{x^3y}{z^2})

💡 Show Solution

Use quotient, product, and power rules:

Step 1: Apply quotient rule log5(x3yz2)=log5(x3y)log5(z2)\log_5\left(\frac{x^3y}{z^2}\right) = \log_5(x^3y) - \log_5(z^2)

Step 2: Apply product rule to first term =log5(x3)+log5(y)log5(z2)= \log_5(x^3) + \log_5(y) - \log_5(z^2)

Step 3: Apply power rule =3log5(x)+log5(y)2log5(z)= 3\log_5(x) + \log_5(y) - 2\log_5(z)

Answer: 3log5(x)+log5(y)2log5(z)3\log_5(x) + \log_5(y) - 2\log_5(z)

3Problem 3hard

Question:

Solve: log2(x+3)+log2(x3)=4\log_2(x + 3) + \log_2(x - 3) = 4

💡 Show Solution

Step 1: Use product rule (combine logs) log2[(x+3)(x3)]=4\log_2[(x + 3)(x - 3)] = 4

Step 2: Convert to exponential form (x+3)(x3)=24=16(x + 3)(x - 3) = 2^4 = 16

Step 3: Simplify left side (difference of squares) x29=16x^2 - 9 = 16

Step 4: Solve for x x2=25x^2 = 25 x=±5x = \pm 5

Step 5: Check both solutions

  • x=5x = 5: log2(8)+log2(2)=3+1=4\log_2(8) + \log_2(2) = 3 + 1 = 4
  • x=5x = -5: log2(2)+log2(8)\log_2(-2) + \log_2(-8) ✗ (negative logs undefined)

Answer: x=5x = 5