Introduction to Simple Harmonic Motion
Restoring forces, period, frequency, and Hooke's Law
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๐ Introduction to Simple Harmonic Motion
What is Simple Harmonic Motion (SHM)?
Simple Harmonic Motion is periodic oscillatory motion where the restoring force is proportional to displacement:
where:
- = restoring force (N)
- = spring constant or force constant (N/m)
- = displacement from equilibrium (m)
- Negative sign: force always points toward equilibrium
๐ก Key Idea: SHM occurs when an object experiences a restoring force proportional to its displacement from equilibrium. The negative sign means the force always tries to bring the object back to equilibrium.
Examples of SHM
Mass-Spring System:
- Mass attached to spring
- Pull and release โ oscillates
- Spring force: (Hooke's Law)
Simple Pendulum:
- Mass on string
- Pull aside and release โ swings
- For small angles: acts like SHM
- Restoring force: component of gravity
Other Examples:
- Vibrating guitar string
- Atoms in a solid (vibrate about equilibrium)
- Molecular bonds
- Earthquake oscillations (seismograph)
Hooke's Law
For an ideal spring, the force is proportional to displacement:
Spring Constant :
- Measures spring "stiffness"
- Units: N/m
- Large : stiff spring (hard to stretch)
- Small : soft spring (easy to stretch)
Equilibrium Position:
- Where spring is unstretched ()
- No net force
- Object naturally returns here
Characteristics of SHM
Amplitude
Maximum displacement from equilibrium:
- If object goes from to , amplitude is
- Always positive
- Units: meters
- Independent of mass or spring constant
Period
Time for one complete oscillation:
- From max displacement, through equilibrium, to other max, and back
- Units: seconds (s)
- Does NOT depend on amplitude!
For mass-spring system:
For simple pendulum (small angles):
where is length, is gravitational acceleration.
Frequency
Number of oscillations per second:
Units: Hz (hertz) = 1/s = cycles/second
For mass-spring:
Angular Frequency
Units: rad/s
For mass-spring:
Position, Velocity, and Acceleration in SHM
Position
or
where:
- = amplitude
- = angular frequency
- = phase constant (depends on initial conditions)
- = time
Velocity
Maximum speed (at equilibrium, ):
Acceleration
Maximum acceleration (at amplitude, ):
Key relationship:
Acceleration is always proportional to (and opposite in direction to) displacement!
Mass-Spring System
For a mass attached to spring with constant :
Period:
Frequency:
Key Observations:
- Heavier mass โ longer period (slower oscillation)
- Stiffer spring (larger ) โ shorter period (faster oscillation)
- Independent of amplitude! (as long as spring obeys Hooke's Law)
Simple Pendulum
For a pendulum with length and small amplitude:
Period:
Key Observations:
- Longer pendulum โ longer period
- Independent of mass!
- Independent of amplitude! (for small angles < 15ยฐ)
- Only depends on length and gravity
Note: For large angles, period does depend on amplitude (not SHM anymore).
โ ๏ธ Common Mistakes
Mistake 1: Confusing Period and Frequency
- Period : time for ONE oscillation (seconds)
- Frequency : oscillations per second (Hz)
- They are reciprocals:
Mistake 2: Thinking Amplitude Affects Period
In ideal SHM, period is independent of amplitude!
- Large swing or small swing, same period
- As long as Hooke's Law holds
Mistake 3: Sign of Restoring Force
Force is ALWAYS opposite to displacement:
- If (stretched right), then (force left)
- If (compressed left), then (force right)
Mistake 4: Pendulum Period and Mass
Pendulum period does NOT depend on mass!
- Only length and gravity matter
- Heavy or light bob, same period (if same length)
Restoring Force
Definition: Force that always acts to return object to equilibrium
Characteristics:
- Always points toward equilibrium
- Proportional to displacement (for SHM)
- Creates oscillatory motion
For Spring:
For Pendulum (small angle ):
- Restoring force = component of weight tangent to arc
- (for small )
- For small angles:
- So: (proportional to !)
Problem-Solving Strategy
For Mass-Spring Problems:
- Identify: mass , spring constant
- Calculate period:
- Calculate frequency:
- Find amplitude: from initial conditions
- Maximum speed:
- Maximum acceleration:
For Pendulum Problems:
- Identify: length
- Check: small angle approximation valid? ()
- Calculate period:
- Note: independent of mass and (small) amplitude
Applications
Clocks and Timekeeping
- Pendulum clocks: invented by Christiaan Huygens (1656)
- Period independent of amplitude (for small swings)
- Reliable timekeeping
Seismographs
- Detect earthquake vibrations
- Record ground oscillations
- Mass-spring system measures ground motion
Musical Instruments
- Vibrating strings (guitars, violins)
- Vibrating air columns (flutes, organ pipes)
- Vibrating membranes (drums)
Molecular Vibrations
- Atoms in molecules vibrate about equilibrium
- Absorption spectra reveal molecular structure
- Chemical bond strength ~ spring constant
Key Formulas Summary
| Quantity | Symbol | Mass-Spring | Pendulum | |----------|--------|-------------|----------| | Restoring Force | | | | | Period | | | | | Frequency | | | | | Angular Frequency | | | | | Max Speed | | | | | Max Acceleration | | | |
Universal: , ,
๐ Practice Problems
1Problem 1easy
โ Question:
A 0.5 kg mass is attached to a spring with spring constant k = 200 N/m. The mass is pulled 0.1 m from equilibrium and released. Find: (a) the period of oscillation, (b) the frequency, and (c) the maximum speed.
๐ก Show Solution
Given Information:
- Mass: kg
- Spring constant: N/m
- Amplitude: m (pulled 0.1 m from equilibrium)
(a) Find period of oscillation
Step 1: Calculate period
Answer (a): Period = 0.314 s (about 0.31 seconds per oscillation)
(b) Find frequency
Step 2: Calculate frequency
Answer (b): Frequency = 3.18 Hz (about 3.2 oscillations per second)
(c) Find maximum speed
Step 3: Calculate angular frequency
Or directly:
Step 4: Calculate maximum speed
Maximum speed occurs at equilibrium position:
Answer (c): Maximum speed = 2.0 m/s
Summary: The mass oscillates with period 0.31 s, completing about 3.2 cycles per second, reaching a maximum speed of 2 m/s as it passes through equilibrium.
2Problem 2medium
โ Question:
A simple pendulum has a length of 2 m. (a) What is its period on Earth? (b) If the same pendulum were on the Moon (where g = 1.6 m/sยฒ), what would its period be?
๐ก Show Solution
Given Information:
- Length: m
- Earth: m/sยฒ
- Moon: m/sยฒ
(a) Find period on Earth
Step 1: Apply pendulum period formula
Answer (a): Period on Earth = 2.84 s
(b) Find period on Moon
Step 2: Apply formula with Moon's gravity
Step 3: Compare the periods
The Moon pendulum has a period about 2.5 times longer than on Earth!
Answer (b): Period on Moon = 7.02 s
Explanation: Lower gravity means weaker restoring force, so the pendulum oscillates more slowly.
Ratio check:
Note: This is why pendulum clocks would run slower on the Moon!
3Problem 3hard
โ Question:
A 2 kg mass on a spring oscillates with amplitude 0.15 m and period 1.5 s. Find: (a) the spring constant, (b) the maximum speed, (c) the maximum acceleration, and (d) the speed when the displacement is 0.1 m from equilibrium.
๐ก Show Solution
Given Information:
- Mass: kg
- Amplitude: m
- Period: s
(a) Find spring constant
Step 1: Use period formula and solve for k
Square both sides:
Solve for :
Answer (a): Spring constant = 35.1 N/m
(b) Find maximum speed
Step 2: Calculate angular frequency
Step 3: Calculate maximum speed
Answer (b): Maximum speed = 0.63 m/s
(c) Find maximum acceleration
Step 4: Calculate maximum acceleration
Answer (c): Maximum acceleration = 2.64 m/sยฒ
(d) Find speed at x = 0.1 m
Step 5: Use energy conservation
Total energy (constant):
At position :
Step 6: Set equations equal and solve for v
Multiply by 2 and cancel:
Note: radยฒ/sยฒ
Answer (d): Speed at m is 0.47 m/s
Check: At : m/s = โ
At m: m/s โ
Makes sense: speed is maximum at equilibrium, zero at amplitude!