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Understand reversible reactions, dynamic equilibrium, and equilibrium constant expressions (K_c and K_p).
Learn step-by-step with practice exercises built right in.
Equilibrium: State where forward and reverse reaction rates are equal
Dynamic equilibrium:
Example:
Write the equilibrium constant expression (K_c) for: 2SO₂(g) + O₂(g) ⇌ 2SO₃(g)
Reaction: 2SO₂(g) + O₂(g) ⇌ 2SO₃(g)
Identify components:
K_c expression:
| Section | Format | Questions | Time | Weight | Calculator |
|---|---|---|---|---|---|
| Multiple Choice | MCQ | 60 | 90 min | 50% | ✅ |
| Free Response (Long) | FRQ | 3 | 69 min | 30% | ✅ |
| Free Response (Short) | FRQ | 4 | 36 min | 20% | ✅ |
Avoid these 3 frequent errors
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mol of reacts with mol of . How many grams of water are produced? Which is the limiting reagent? ()
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At equilibrium: [N₂], [H₂], [NH₃] constant (but reactions ongoing)
Notation:
Characteristics:
For general reaction:
Equilibrium expression:
Key points:
Include: Gases and aqueous solutions
Exclude:
Examples:
(Solids omitted)
(Water omitted - solvent)
For gas-phase reactions:
Use partial pressures (atm) instead of concentrations
Where:
If Δn = 0: K_p = K_c
Interpretation:
| K value | Meaning |
|---|---|
| K >> 1 (>10³) | Products favored, equilibrium far right |
| K ≈ 1 (10⁻³ to 10³) | Significant amounts of both |
| K << 1 (<10⁻³) | Reactants favored, equilibrium far left |
Examples:
If K_forward = x, then K_reverse = 1/x
Example: If K = 100 for A ⇌ B, then K = 0.01 for B ⇌ A
If multiply by n, then K_new = (K_original)^n
Example: If K = 10 for A ⇌ B, then K = 100 for 2A ⇌ 2B
If add reactions, multiply K values
K_overall = K₁ × K₂ × K₃...
Homogeneous: All species in same phase
Heterogeneous: Multiple phases present
General strategy:
Apply coefficients as exponents:
Answer:
Key points:
For the reaction: N₂(g) + 3H₂(g) ⇌ 2NH₃(g), K_c = 0.500 at 400°C. Calculate K_p at the same temperature.
Given:
Relationship:
Calculate Δn:
Δn = moles gas products - moles gas reactants
Products: 2 mol NH₃ Reactants: 1 mol N₂ + 3 mol H₂ = 4 mol
Δn = 2 - 4 = -2
Calculate RT:
RT = (0.08206)(673) = 55.2 L·atm/mol
Calculate K_p:
Answer: K_p = 1.64 × 10⁻⁴
Interpretation:
K_p < K_c because Δn < 0
At equilibrium at 500 K: H₂(g) + I₂(g) ⇌ 2HI(g), [H₂] = 0.20 M, [I₂] = 0.20 M, [HI] = 1.60 M. (a) Calculate K_c. (b) If this reaction is reversed, what is the new K_c?
Given:
(a) Calculate K_c
K_c expression:
Substitute values:
Answer (a): K_c = 64
(b) Reversed reaction K_c
Reversed reaction: 2HI(g) ⇌ H₂(g) + I₂(g)
Rule: K_reverse = 1/K_forward
Answer (b): K_c = 0.0156 or 1.56 × 10⁻²
Interpretation:
Forward reaction (K = 64):
Reverse reaction (K = 0.0156):
Note: K_forward × K_reverse = 64 × 0.0156 = 1 ✓