Skip to content

Geometric Sequences

Patterns with common ratios

Written and reviewed by the Study Mondo Education TeamLast updated
🎯⭐ INTERACTIVE LESSON

Try the Interactive Version!

Learn step-by-step with practice exercises built right in.

Start Interactive Lesson →

Geometric Sequences

Definition

A geometric sequence has a constant ratio between consecutive terms.

Example: 3,6,12,24,48,...3, 6, 12, 24, 48, ...

  • Common ratio: r=2r = 2

Finding the Common Ratio

r=a2a1=a3a2=...r = \frac{a_2}{a_1} = \frac{a_3}{a_2} = ...

Divide any term by the previous term.

Explicit Formula

To find the nnth term: an=a1⋅rn−1a_n = a_1 \cdot r^{n-1}

where:

  • ana_n = nth term
  • a1a_1 = first term
  • rr = common ratio
  • nn = term number

Recursive Formula

an=an−1⋅ra_n = a_{n-1} \cdot r

Each term equals the previous term times rr.

Growth vs. Decay

Growth: ∣r∣>1|r| > 1

  • Terms get larger in magnitude

Decay: 0<∣r∣<10 < |r| < 1

  • Terms get smaller

Real-World Applications

  • Compound interest
  • Population growth
  • Radioactive decay

📚 Practice Problems

1Problem 1easy

❓ Question:

Find the common ratio: 5,15,45,135,...5, 15, 45, 135, ...

💡 Show Solution

Divide consecutive terms:

r=155=3r = \frac{15}{5} = 3

Check: 4515=3\frac{45}{15} = 3 ✓

Answer: Common ratio = 33

2Problem 2medium

❓ Question:

Find the 8th term of the sequence: 2,6,18,54,...2, 6, 18, 54, ...

💡 Show Solution

Step 1: Identify a1a_1 and rr a1=2,r=62=3a_1 = 2, \quad r = \frac{6}{2} = 3

Step 2: Use the explicit formula an=a1⋅rn−1a_n = a_1 \cdot r^{n-1}

Step 3: Substitute n=8n = 8 a8=2⋅38−1a_8 = 2 \cdot 3^{8-1} =2⋅37= 2 \cdot 3^7 =2⋅2187= 2 \cdot 2187 =4374= 4374

Answer: a8=4374a_8 = 4374

3Problem 3hard

❓ Question:

The 3rd term of a geometric sequence is 12 and the 6th term is 96. Find the first term and common ratio.

💡 Show Solution

Given: a3=12a_3 = 12 and a6=96a_6 = 96

Step 1: Write equations using an=a1⋅rn−1a_n = a_1 \cdot r^{n-1} a3:12=a1⋅r2a_3: \quad 12 = a_1 \cdot r^2 a6:96=a1⋅r5a_6: \quad 96 = a_1 \cdot r^5

Step 2: Divide the second by the first 9612=a1⋅r5a1⋅r2\frac{96}{12} = \frac{a_1 \cdot r^5}{a_1 \cdot r^2} 8=r38 = r^3 r=2r = 2

Step 3: Find a1a_1 using a3=12a_3 = 12 12=a1⋅2212 = a_1 \cdot 2^2 12=4a112 = 4a_1 a1=3a_1 = 3

Check: Sequence is 3,6,12,24,48,96,...3, 6, 12, 24, 48, 96, ... ✓

Answer: a1=3a_1 = 3, r=2r = 2

Explain using:

⚠️ Common Mistakes: Geometric Sequences

Avoid these 3 frequent errors

🌍 Real-World Applications: Geometric Sequences

See how this math is used in the real world

📝 Worked Example: Solving a Quadratic by Factoring

Problem:

Solve x2−5x+6=0x^2 - 5x + 6 = 0.

2Factor the quadratic
3Set each factor equal to zero

📌 Related Topics in Sequences and Series

❓ Frequently Asked Questions

What is Geometric Sequences?▾
Patterns with common ratios
How can I study Geometric Sequences effectively?▾
Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 3 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
Is this Geometric Sequences study guide free?▾
Yes — all study notes, flashcards, and practice problems for Geometric Sequences on Study Mondo are free to access. No account is needed.
What course covers Geometric Sequences?▾
Geometric Sequences is part of the Algebra 2 course on Study Mondo, specifically in the Sequences and Series section. You can explore the full course for more related topics and practice resources.
Are there practice problems for Geometric Sequences?▾
Yes, this page includes 3 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.