Exponential Functions

Properties and graphs of exponential functions

Exponential Functions

Definition

An exponential function has the form: f(x)=abxf(x) = a \cdot b^x

where:

  • aa = initial value (y-intercept when x=0x = 0)
  • bb = base (growth/decay factor)
  • xx = exponent (input variable)

Growth vs. Decay

Exponential Growth: b>1b > 1

  • Function increases
  • Example: f(x)=2xf(x) = 2^x

Exponential Decay: 0<b<10 < b < 1

  • Function decreases
  • Example: f(x)=(12)xf(x) = (\frac{1}{2})^x

Properties

  • Domain: All real numbers
  • Range: (0,)(0, \infty) if a>0a > 0
  • Y-intercept: (0,a)(0, a)
  • Horizontal asymptote: y=0y = 0
  • Never touches or crosses x-axis

Exponential Growth/Decay Formula

A=A0(1+r)tA = A_0(1 + r)^t

where:

  • AA = final amount
  • A0A_0 = initial amount
  • rr = rate (as decimal)
  • tt = time

Growth: r>0r > 0 (add) Decay: r<0r < 0 (subtract)

📚 Practice Problems

1Problem 1easy

Question:

Evaluate: f(x)=32xf(x) = 3 \cdot 2^x when x=4x = 4

💡 Show Solution

Substitute x=4x = 4 into the function:

f(4)=324f(4) = 3 \cdot 2^4 =316= 3 \cdot 16 =48= 48

Answer: f(4)=48f(4) = 48

2Problem 2medium

Question:

A population of bacteria doubles every 3 hours. If there are initially 500 bacteria, how many will there be after 12 hours?

💡 Show Solution

Step 1: Determine how many doubling periods 12 hours3 hours/doubling=4 doublings\frac{12 \text{ hours}}{3 \text{ hours/doubling}} = 4 \text{ doublings}

Step 2: Use the formula A=A02nA = A_0 \cdot 2^n A=50024A = 500 \cdot 2^4 =50016= 500 \cdot 16 =8000= 8000

Answer: 8,000 bacteria

3Problem 3hard

Question:

A car depreciates at 15% per year. If it costs $25,000 new, what will it be worth after 5 years?

💡 Show Solution

Use the decay formula: A=A0(1r)tA = A_0(1 - r)^t

Given:

  • A0=25000A_0 = 25000
  • r=0.15r = 0.15 (15% decay)
  • t=5t = 5 years

Substitute: A=25000(10.15)5A = 25000(1 - 0.15)^5 =25000(0.85)5= 25000(0.85)^5 =25000(0.4437...)= 25000(0.4437...) 11,093\approx 11,093

Answer: Approximately $11,093