An ellipse is the set of all points where the sum of distances to two foci is constant.
Standard Form (Horizontal Major Axis)
a2
๐ Practice Problems
1Problem 1easy
โ Question:
Find the vertices, co-vertices, and foci of the ellipse 25.
Explain using:
โ ๏ธ Common Mistakes: Ellipses and Hyperbolas
Avoid these 4 frequent errors
๐ Real-World Applications: Ellipses and Hyperbolas
See how this math is used in the real world
๐ Worked Example: Related Rates โ Expanding Circle
Problem:
A stone is dropped into a still pond, creating a circular ripple. The radius of the ripple is increasing at a rate of 2 cm/s. How fast is the area of the circle increasing when the radius is 10 cm?
Standard forms and key features of ellipses and hyperbolas
How can I study Ellipses and Hyperbolas effectively?โพ
Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 5 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
Is this Ellipses and Hyperbolas study guide free?โพ
Yes โ all study notes, flashcards, and practice problems for Ellipses and Hyperbolas on Study Mondo are 100% free. No account is needed to access the content.
What course covers Ellipses and Hyperbolas?โพ
Ellipses and Hyperbolas is part of the AP Precalculus course on Study Mondo, specifically in the Function Fundamentals section. You can explore the full course for more related topics and practice resources.
Are there practice problems for Ellipses and Hyperbolas?
(xโh)2
โ
+
b2(yโk)2โ=
1,a>
b
Standard Form (Vertical Major Axis)
b2(xโh)2โ+a2(yโk)2โ=1,a>b
Where:
(h,k) = center
a = semi-major axis (larger value)
b = semi-minor axis (smaller value)
c = distance from center to focus
Key relationship:c2=a2โb2
Key Features of Ellipse
For horizontal major axisa2(xโh)2โ+b2(yโk)2โ=1:
Center: (h,k)
Vertices (endpoints of major axis): (hยฑa,k)
Co-vertices (endpoints of minor axis): (h,kยฑb)
Foci: (hยฑc,k) where c2=a2โ
Major axis length: 2a
Minor axis length: 2b
For vertical major axis: Swap the roles (vertices on vertical axis)
Eccentricity
e=acโ,0<e<1
e close to 0: nearly circular
e close to 1: very elongated
Hyperbolas
A hyperbola is the set of all points where the difference of distances to two foci is constant.
Standard Form (Horizontal Transverse Axis)
a2(xโh)2โโb2(yโk)2โ=1
Opens left and right.
Standard Form (Vertical Transverse Axis)
a2(yโk)2โโb2(xโh)2โ=1
Opens up and down.
Where:
(h,k) = center
a = distance from center to vertex
b = determines spread of branches
c = distance from center to focus
Key relationship:c2=a2+b2 (note: plus, not minus!)
Key Features of Hyperbola
For horizontal transverse axisa2(xโh)2โโb2(yโk)2โ=1:
Center: (h,k)
Vertices: (hยฑa,k)
Foci: (hยฑc,k) where c2=a2+b2
Asymptotes: yโk=ยฑabโ(xโh)
For vertical transverse axis: Vertices and foci on vertical axis, asymptotes: yโk=ยฑbaโ(xโh)
Asymptotes
The branches of a hyperbola approach (but never touch) the asymptotes.
Rectangle method:
Draw rectangle with vertices at (hยฑa,kยฑb)
Draw diagonals of rectangle
These diagonals are the asymptotes
Identifying Conic Sections
From the equation Ax2+Bxy+Cy2+Dx+Ey+F=0 (with B=0):
Circle: A=C (and same sign)
Ellipse: A๎ =C but same sign
Parabola: Either A=0 or C=0 (but not both)
Hyperbola: A and C have opposite signs
Summary Table
Conic
Standard Form
c relationship
Key feature
Circle
(xโh)2+(yโk)2=r2
N/A
All points distance r from center
Ellipse
a2(xโh)
Hyperbola
a2(xโh)
Parabola
(xโh)2=4p(yโk)
N/A
Distance to focus = distance to directrix
(
x
โ
2
)2
โ
+
9(y+1)2โ=
1
๐ก Show Solution
Identify the ellipse characteristics:
Step 1: Determine orientation:
Form: a2(xโh)2โ+b2(yโk)2โ=1
a2=25>b2=9 โ horizontal major axis
a=5, b=3
Center: (h,k)=(2,โ1)
Step 2: Find vertices (endpoints of major axis):
Vertices are a units left and right of center:
(2ยฑ5,โ1)=(7,โ1)ย andย (โ3,โ1)
Step 3: Find co-vertices (endpoints of minor axis):
Co-vertices are b units up and down from center:
(2,โ1ยฑ3)=(2,2)ย andย (2,โ4)
Step 4: Find foci using c2=a2โb2:
Foci are c units left and right of center:
(2ยฑ4,โ1)=(6,โ1)ย andย (โ2,โ1)
Answers:
Center: (2,โ1)
Vertices: (7,โ1) and (โ3,โ1)
Co-vertices: and
2Problem 2medium
โ Question:
Find the center, vertices, foci, and asymptotes of the hyperbola 16(y+3)2โโ9(xโ1)2โ=1.
๐ก Show Solution
Identify the hyperbola characteristics:
Step 1: Determine orientation:
y term is positive โ vertical transverse axis (opens up and down)
a2=16, so a
3Problem 3hard
โ Question:
Write the equation of an ellipse with center at the origin, a focus at (0,3), and a vertex at (0,5).
๐ก Show Solution
Determine ellipse characteristics:
Step 1: Analyze given information:
Center: (0,0)
Focus: (0,3) โ on y-axis โ vertical major axis
Vertex: (0,5) โ also on -axis โ
Step 2: Find a and c:
Distance from center to vertex: a=5
Distance from center to focus: c=3
Step 3: Use c2=a2โb2 to find b:
Step 4: Write equation (vertical major axis with center at origin):
b2x2โ+
Step 5: Verify:
Center: (0,0) โ
a=5, so vertices: (0,ยฑ5) โ
c, so foci: โ
Answer:16x2โ+25
4Problem 4medium
โ Question:
Find the center, vertices, and foci of the ellipse: (x - 1)ยฒ/25 + (y + 2)ยฒ/9 = 1
Yes, this page includes 5 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.
b2
2
โ
+
b2(yโk)2โ=
1
c2=a2โb2
Sum of distances to foci = 2a
2
โ
โ
b2(yโk)2โ=
1
c2=a2+b2
Difference of distances to foci = 2a
c2
=
25โ
9=
16
c=4
(2,2)
(2,โ4)
Foci: (6,โ1) and (โ2,โ1)
Major axis length: 2a=10
Minor axis length: 2b=6
=
4
b2=9, so b=3
Center: (h,k)=(1,โ3)
Step 2: Find vertices:
Vertices are a units above and below center:
(1,โ3ยฑ4)=(1,1)ย andย (1,โ7)
Step 3: Find foci using c2=a2+b2:
c2=16+9=25c=5
Foci are c units above and below center:
(1,โ3ยฑ5)=(1,2)ย andย (1,โ8)
Step 4: Find asymptotes:
For vertical hyperbola: yโk=ยฑbaโ(xโh)yโ(โ3)=ยฑ34โ(xโ1)y+3=ยฑ34โ(xโ1)
Two asymptotes:
y=34โ(xโ1)โ3=34โxโ313โy=โ34โ(xโ1)โ3=