Write the full electron configuration for sulfur (S, atomic number 16).
💡 Show Solution
Solution:
Given: Sulfur (S), Z=16Find: Full electron configuration
Step 1: Determine number of electrons
Neutral sulfur has 16 electrons (same as protons).
Step 2: Fill orbitals in order
Order: 1s, 2s, 2p, 3s, 3p
1s: 2 electrons → 1s2 (total: 2)
2s: 2 electrons → 2s2 (total: 4)
2p: 6 electrons → 2p (total: 10)
Answer:1s22s22p63s23p
Noble gas notation:[Ne]3s23p4
Verification:
Total electrons: 2+2+6+2+4=16 ✓
Valence electrons: 6 (matches Group 16) ✓
2Problem 2medium
❓ Question:
(a) Write the complete electron configuration for iron (Fe, atomic number 26). (b) Write the noble gas notation for Fe. (c) How many unpaired electrons does Fe have in its ground state? (d) Which orbital subshell is being filled in the transition metals?
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Solution:
(a) Complete configuration:
Fe (Z=26): 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶
(b) Noble gas notation:
Previous noble gas is Ar (Z=18)
Fe: [Ar] 4s² 3d⁶
(c) Unpaired electrons:
4s²: 2 paired electrons
3d⁶: ↑↓ ↑ ↑ ↑ ↑ (following Hund's rule)
in the 3d subshell
3Problem 3medium
❓ Question:
Draw the orbital diagram for carbon (C) and identify any unpaired electrons.
💡 Show Solution
Solution:
Given: Carbon (C), Z=6Find: Orbital diagram and unpaired electrons
Step 1: Write electron configuration
Carbon:
4Problem 4hard
❓ Question:
(a) Write the electron configuration for Cu²⁺ (copper ion). (b) Explain why copper's electron configuration is [Ar] 4s¹ 3d¹⁰ rather than the expected [Ar] 4s² 3d⁹. (c) Which electrons are removed first when forming the Cu²⁺ ion?
💡 Show Solution
Solution:
(a) Cu²⁺ configuration:
Cu is [Ar] 4s¹ 3d¹⁰
Remove 2 electrons from highest energy levels
Cu²⁺: [Ar] 3d⁹
(b) Copper's anomalous configuration:
Expected: [Ar] 4s² 3d⁹
Actual: [Ar] 4s¹ 3d¹⁰
Explanation: A completely filled d¹⁰ subshell is more stable than d⁹ due to exchange energy. The extra stability from having a filled d subshell outweighs the energy cost of promoting an electron from 4s to 3d.
(c)
5Problem 5hard
❓ Question:
Write the electron configuration for Fe²⁺ and explain how it differs from neutral Fe.
💡 Show Solution
Solution:
Given: Fe (iron, Z=26) and Fe²⁺
Find: Electron configurations and explanation
Step 1: Write configuration for neutral Fe
Iron has 26 electrons.
Following the filling order through 4s and 3d:
Explain using:
📋 AP Chemistry — Exam Format Guide
⏱ 3 hours 15 minutes📝 67 questions📊 3 sections
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💡 Key Test-Day Tips
✓Memorize common polyatomic ions
✓Practice dimensional analysis
✓Know your gas laws
⚠️ Common Mistakes: Atomic Structure and Electron Configuration
Avoid these 3 frequent errors
🌍 Real-World Applications: Atomic Structure and Electron Configuration
See how this math is used in the real world
📝 Worked Example: Stoichiometry — Limiting Reagent
Problem:
2 mol of H2 reacts with 1 mol of O2. How many grams of water are produced? Which is the limiting reagent? (2H2+O2→2H2O)
What is Atomic Structure and Electron Configuration?▾
Learn about subatomic particles, energy levels, orbitals, and how to write electron configurations for atoms and ions.
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Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 5 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
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Yes, this page includes 5 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.
6
3s: 2 electrons → 3s2 (total: 12)
3p: 4 electrons → 3p4 (total: 16) ✓
4
4 unpaired electrons
(d) Subshell being filled:
Transition metals fill the d subshell (specifically the (n-1)d subshell)
1s22s22p2
Step 2: Draw orbital diagram
1s: ↑↓
2s: ↑↓
2p: ↑ ↑ _ (three orbitals: px, py, pz)
Step 3: Apply Hund's Rule
For the 2 electrons in 2p:
Place one electron in first orbital (↑)
Place one electron in second orbital (↑)
Leave third orbital empty
Complete diagram:
↑↓ ↑↓ ↑ ↑ _
1s 2s 2p
Answer:
Orbital diagram shown above
Unpaired electrons: 2 (both in 2p sublevel)
Explanation:
Hund's rule requires maximizing unpaired electrons in degenerate orbitals
Carbon's 2 unpaired electrons make it chemically reactive
These unpaired electrons form bonds in compounds like CO₂, CH₄
Verification:
Total electrons: 2 + 2 + 2 = 6 ✓
Hund's rule followed ✓
Electron removal:
When forming ions, electrons are removed from the highest n value first (4s before 3d)
Even though Cu fills 3d last, the 4s¹ electron is removed first, then one 3d electron
This is why Cu²⁺ is [Ar] 3d⁹, not [Ar] 4s¹ 3d⁸
Fe: [Ar]4s23d6
Expanded: [Ar]=1s22s22p63s23p6
Step 2: Form Fe²⁺ (remove 2 electrons)
Key concept: When forming cations, remove electrons from the highest n value first.
For Fe: Remove from 4s before 3d
Fe2+:[Ar]3d6
NOT[Ar]4s23d4 (incorrect!)
Step 3: Explain the difference
Neutral Fe:[Ar]4s23d6 (26 electrons)
4s sublevel: 2 electrons
3d sublevel: 6 electrons
Fe²⁺:[Ar]3d6 (24 electrons)
4s sublevel: 0 electrons (both removed)
3d sublevel: 6 electrons (unchanged)
Why remove 4s first?
Even though 4s fills before 3d, once the 3d sublevel begins filling, it becomes lower in energy than 4s. When ionizing, electrons are removed from the highest energy orbital, which is 4s.