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Properties of electric charge, conservation, and electrostatic forces
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Electric charge is a fundamental property of matter that causes electromagnetic interactions.
Two point charges, qโ = +3.0 ฮผC and qโ = -2.0 ฮผC, are separated by 0.50 m. What is the magnitude of the electrostatic force between them? (k = 9.0 ร 10โน Nยทmยฒ/Cยฒ)
Given:
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Coulomb (C): SI unit of electric charge
Elementary charge: C
Any charge: where is an integer
Coulomb's Law gives the electrostatic force between two point charges:
where:
Direction:
where Cยฒ/(Nยทmยฒ) is the permittivity of free space.
Often approximated as: Nยทmยฒ/Cยฒ
Similarities:
Differences:
| Property | Gravity | Electricity |
|---|---|---|
| Always | Attractive | Attractive OR repulsive |
| Constant | ||
| Relative strength | Very weak | Much stronger |
| Shielding | No | Yes (conductors) |
Electric force is ~10ยณโน times stronger than gravity!
For multiple charges, total force = vector sum of individual forces:
Each force calculated using Coulomb's Law independently.
โ Forgetting to square the distance in denominator โ Using wrong sign convention (use magnitude, then add direction) โ Not converting units (must use meters, coulombs) โ Adding forces as scalars instead of vectors โ Confusing force on A from B with force on B from A (equal magnitude, opposite direction)
Find: Force
Solution:
Apply Coulomb's Law:
Direction: Opposite signs โ attractive force
Answer: 0.22 N, attractive
Three charges are arranged in a line: qโ = +2.0 ฮผC at x = 0, qโ = -3.0 ฮผC at x = 0.30 m, and qโ = +1.0 ฮผC at x = 0.60 m. What is the net force on qโ?
Given:
Find: Net force on
Solution:
Force from qโ on qโ:
Distance: m
Direction: Opposite signs โ attractive โ toward qโ (left, negative)
Force from qโ on qโ:
Distance: m
Direction: Opposite signs โ attractive โ toward qโ (right, positive)
Net force (superposition):
Answer: 0.30 N to the left (toward qโ)
Four equal charges Q = +5.0 ฮผC are placed at the corners of a square with side length 0.20 m. What is the magnitude and direction of the net force on one of the charges?
Given:
Find: Net force on one corner charge
Solution:
Consider force on charge at origin (0,0). Other charges at:
Force from adjacent charges (two):
Each points along edge (90ยฐ angle between them).
Force from diagonal charge:
Points along diagonal toward corner.
Components:
From right: N From top: N From diagonal: At 45ยฐ, points toward (along diagonal from origin) $$\vec{F}_3 = (2.813\cos 45ยฐ, 2.813\sin 45ยฐ) = (1.99, 1.99)$ N
Total:
Answer: 10.8 N at 45ยฐ from the two adjacent sides (along diagonal outward)
By symmetry, this makes sense - force points directly away from center!