Introduction to Complex Numbers

Imaginary unit and complex number operations

Introduction to Complex Numbers

The Imaginary Unit

The imaginary unit ii is defined as: i=1i = \sqrt{-1}

Therefore: i2=1i^2 = -1

Complex Numbers

A complex number has the form: a+bia + bi

where:

  • aa = real part
  • bb = imaginary part
  • ii = imaginary unit

Example: 3+4i3 + 4i

Powers of ii

Pattern repeats every 4:

  • i1=ii^1 = i
  • i2=1i^2 = -1
  • i3=i2i=ii^3 = i^2 \cdot i = -i
  • i4=i2i2=1i^4 = i^2 \cdot i^2 = 1
  • i5=ii^5 = i (pattern repeats)

Adding and Subtracting

Combine like terms (real with real, imaginary with imaginary):

(3+4i)+(2i)=(3+2)+(4ii)=5+3i(3 + 4i) + (2 - i) = (3 + 2) + (4i - i) = 5 + 3i

Multiplying

Use FOIL and remember i2=1i^2 = -1:

(2+3i)(1+4i)(2 + 3i)(1 + 4i) =2+8i+3i+12i2= 2 + 8i + 3i + 12i^2 =2+11i+12(1)= 2 + 11i + 12(-1) =2+11i12= 2 + 11i - 12 =10+11i= -10 + 11i

Complex Conjugates

The conjugate of a+bia + bi is abia - bi.

Property: (a+bi)(abi)=a2+b2(a + bi)(a - bi) = a^2 + b^2 (always real!)

📚 Practice Problems

1Problem 1easy

Question:

Simplify: 16\sqrt{-16}

💡 Show Solution

Factor out 1-1: 16=116\sqrt{-16} = \sqrt{-1 \cdot 16}

=116= \sqrt{-1} \cdot \sqrt{16}

=i4= i \cdot 4

=4i= 4i

Answer: 4i4i

2Problem 2medium

Question:

Add: (52i)+(3+7i)(5 - 2i) + (-3 + 7i)

💡 Show Solution

Combine real parts and imaginary parts separately:

Real parts: 5+(3)=25 + (-3) = 2 Imaginary parts: 2i+7i=5i-2i + 7i = 5i

Answer: 2+5i2 + 5i

3Problem 3hard

Question:

Multiply: (32i)(3+2i)(3 - 2i)(3 + 2i)

💡 Show Solution

Notice these are conjugates! Use the formula (a+bi)(abi)=a2+b2(a + bi)(a - bi) = a^2 + b^2

Or use FOIL: (32i)(3+2i)(3 - 2i)(3 + 2i) =9+6i6i4i2= 9 + 6i - 6i - 4i^2 =94(1)= 9 - 4(-1) =9+4= 9 + 4 =13= 13

Answer: 1313 (a real number!)