Complex Numbers and Operations
Understand complex numbers, perform operations with complex numbers, and solve equations involving complex solutions.
Complex Numbers and Operations
Introduction to Complex Numbers
A complex number has the form:
Where:
- is the real part:
- is the imaginary part:
- is the imaginary unit: , so
Key Properties of
- Pattern repeats: , , etc.
To find : divide by 4 and use the remainder.
Complex Number Operations
Addition and Subtraction
Combine like terms (real with real, imaginary with imaginary):
Multiplication
Use the distributive property and :
FOIL method works:
- First:
- Outer:
- Inner:
- Last:
Division
To divide complex numbers, multiply by the conjugate of the denominator:
The denominator becomes real:
Complex Conjugate
The conjugate of is:
Properties:
- (always real and non-negative)
Absolute Value (Modulus)
The absolute value or modulus of is:
This represents the distance from the origin in the complex plane.
Properties:
- if and only if
- (if )
Complex Plane (Argand Diagram)
Complex numbers can be plotted on a coordinate plane:
- Horizontal axis: Real part
- Vertical axis: Imaginary part
- corresponds to point
Polar Form
A complex number can also be written in polar form:
Or using Euler's formula:
Where:
- (modulus)
- (argument/angle, adjusted for quadrant)
Solving Equations with Complex Numbers
Quadratic Equations
For with discriminant :
Complex Conjugate Root Theorem: If is a root of a polynomial with real coefficients, then is also a root.
Higher Degree Equations
Complex solutions come in conjugate pairs for polynomials with real coefficients.
Key Theorems
-
Fundamental Theorem of Algebra: Every polynomial of degree has exactly complex roots (counting multiplicity).
-
Complex Conjugate Root Theorem: If a polynomial has real coefficients and is a root, then is also a root.
📚 Practice Problems
1Problem 1easy
❓ Question:
Simplify and .
💡 Show Solution
Solution:
Part 1: Addition
Combine real parts and imaginary parts separately:
- Real parts:
- Imaginary parts:
Answer:
Part 2: Subtraction
Distribute the negative sign and combine:
- Real parts:
- Imaginary parts:
Answer:
Verification:
- Addition: Real = 8, Imaginary = -2 ✓
- Subtraction: Real = -2, Imaginary = 6 ✓
2Problem 2medium
❓ Question:
Multiply and express in standard form .
💡 Show Solution
Solution:
Given:
Use FOIL method:
- First:
- Outer:
- Inner:
- Last:
Combine:
Answer:
Verification using the formula:
Where :
- Real part: ✓
- Imaginary part: ✓
3Problem 3hard
❓ Question:
Divide and express in standard form .
💡 Show Solution
Solution:
Given:
Step 1: Multiply by the conjugate of the denominator
The conjugate of is :
Step 2: Multiply the numerators
- F:
- O:
- I:
- L:
Step 3: Multiply the denominators
Step 4: Combine
Answer:
Verification: Check by multiplying: ✓
4Problem 4medium
❓ Question:
Multiply: (3 - 2i)(1 + 4i)
💡 Show Solution
Step 1: Use FOIL method: (3 - 2i)(1 + 4i)
First: 3 × 1 = 3 Outer: 3 × 4i = 12i Inner: -2i × 1 = -2i Last: -2i × 4i = -8i²
Step 2: Combine: 3 + 12i - 2i - 8i²
Step 3: Remember i² = -1: -8i² = -8(-1) = 8
Step 4: Simplify: 3 + 12i - 2i + 8 = (3 + 8) + (12i - 2i) = 11 + 10i
Answer: 11 + 10i
5Problem 5hard
❓ Question:
Divide and express in standard form: (2 + 3i)/(4 - i)
💡 Show Solution
Step 1: Multiply by conjugate of denominator: Conjugate of (4 - i) is (4 + i)
Step 2: Multiply numerator and denominator: (2 + 3i)/(4 - i) × (4 + i)/(4 + i)
Step 3: Expand numerator: (2 + 3i)(4 + i) = 8 + 2i + 12i + 3i² = 8 + 14i + 3(-1) = 8 + 14i - 3 = 5 + 14i
Step 4: Expand denominator: (4 - i)(4 + i) = 16 + 4i - 4i - i² = 16 - (-1) = 17
Step 5: Divide: (5 + 14i)/17 = 5/17 + (14/17)i
Answer: (5/17) + (14/17)i
Practice with Flashcards
Review key concepts with our flashcard system
Browse All Topics
Explore other calculus topics