Cellular Respiration

Glycolysis, Krebs cycle, and oxidative phosphorylation

🔋 Cellular Respiration

Overview

Cellular respiration: Process of breaking down glucose to produce ATP

Overall equation:

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + ~32 ATP

Three main stages:

  1. Glycolysis (cytoplasm)
  2. Krebs cycle (mitochondrial matrix)
  3. Oxidative phosphorylation (inner membrane)

Stage 1: Glycolysis

Location: Cytoplasm

Process:

  • Glucose (6C) → 2 Pyruvate (3C each)
  • Does NOT require oxygen (anaerobic)
  • "Glucose splitting"

Energy yield:

  • 2 ATP (net) - used 2, produced 4
  • 2 NADH

Steps:

  1. Energy investment phase (uses 2 ATP)
  2. Energy payoff phase (makes 4 ATP, 2 NADH)

Stage 2: Krebs Cycle (Citric Acid Cycle)

Location: Mitochondrial matrix

Before Krebs:

  • Pyruvate → Acetyl CoA (by pyruvate dehydrogenase)
  • Releases CO₂, makes NADH

Process:

  • Acetyl CoA (2C) enters cycle
  • Combines with oxaloacetate (4C) → citrate (6C)
  • Series of redox reactions
  • Regenerates oxaloacetate

Energy yield (per glucose = 2 turns):

  • 2 ATP (or GTP)
  • 6 NADH
  • 2 FADH₂
  • 4 CO₂ released

Stage 3: Oxidative Phosphorylation

Two parts:

Electron Transport Chain (ETC)

Location: Inner mitochondrial membrane (cristae)

Process:

  • NADH and FADH₂ donate electrons
  • Electrons pass through protein complexes
  • Energy used to pump H⁺ into intermembrane space
  • Creates electrochemical gradient (proton-motive force)

Protein complexes:

  1. Complex I: NADH → Q
  2. Complex II: FADH₂ → Q
  3. Complex III: Q → Cytochrome c
  4. Complex IV: Cytochrome c → O₂

Final electron acceptor: O₂ → H₂O

Chemiosmosis

Process:

  • H⁺ gradient created by ETC
  • H⁺ flows back through ATP synthase
  • Flow drives ATP synthesis
  • ~3 ATP per NADH
  • ~2 ATP per FADH₂

Total ATP Yield

From one glucose:

  • Glycolysis: 2 ATP + 2 NADH
  • Pyruvate → Acetyl CoA: 2 NADH
  • Krebs cycle: 2 ATP + 6 NADH + 2 FADH₂
  • Oxidative phosphorylation: ~28 ATP

Total: ~32 ATP (varies by cell type)

Anaerobic Respiration (Fermentation)

When O₂ unavailable:

Lactic acid fermentation:

  • Pyruvate → Lactate
  • Regenerates NAD⁺ for glycolysis
  • Occurs in muscles during intense exercise

Alcohol fermentation:

  • Pyruvate → Ethanol + CO₂
  • Regenerates NAD⁺
  • Used by yeast

Energy yield: Only 2 ATP (from glycolysis)

Key Concepts

  1. Glycolysis: glucose → 2 pyruvate (2 ATP, 2 NADH)
  2. Krebs cycle: completes glucose oxidation (2 ATP, 8 NADH, 2 FADH₂)
  3. ETC: electrons from NADH/FADH₂ pump H⁺
  4. Chemiosmosis: H⁺ gradient drives ATP synthesis
  5. O₂ is final electron acceptor in aerobic respiration
  6. Fermentation: anaerobic, regenerates NAD⁺, only 2 ATP

📚 Practice Problems

1Problem 1easy

Question:

Outline the four stages of cellular respiration: (a) name each stage, (b) state where each occurs in the cell, (c) identify the main products of each stage, and (d) calculate the total ATP yield from one glucose molecule.

💡 Show Solution

Cellular Respiration Overview:

C6H12O6+6O26CO2+6H2O+ATP\text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{CO}_2 + 6\text{H}_2\text{O} + \text{ATP}

(a) Four stages:

  1. Glycolysis
  2. Pyruvate Oxidation (transition reaction)
  3. Krebs Cycle (Citric Acid Cycle)
  4. Electron Transport Chain + Oxidative Phosphorylation

(b) Locations:

1. Glycolysis:

  • Location: Cytoplasm (cytosol)
  • Anaerobic (doesn't require O₂)

2. Pyruvate Oxidation:

  • Location: Mitochondrial matrix
  • Entry into mitochondria

3. Krebs Cycle:

  • Location: Mitochondrial matrix
  • Aerobic (requires O₂ indirectly)

4. Electron Transport Chain:

  • Location: Inner mitochondrial membrane (cristae)
  • Requires O₂ as final electron acceptor

(c) Products of each stage:

1. Glycolysis (glucose → 2 pyruvate):

  • ATP: 2 net (4 produced - 2 invested)
  • NADH: 2
  • Pyruvate: 2

2. Pyruvate Oxidation (2 pyruvate → 2 acetyl-CoA):

  • NADH: 2
  • CO₂: 2
  • Acetyl-CoA: 2

3. Krebs Cycle (2 turns, one per acetyl-CoA):

  • ATP (GTP): 2
  • NADH: 6
  • FADH₂: 2
  • CO₂: 4

4. Electron Transport Chain:

  • ATP: ~34 (from NADH and FADH₂)
  • H₂O: 6 (O₂ reduced)

(d) Total ATP yield:

From NADH:

  • Glycolysis: 2 NADH × 2.5 ATP = 5 ATP
  • Pyruvate oxidation: 2 NADH × 2.5 ATP = 5 ATP
  • Krebs: 6 NADH × 2.5 ATP = 15 ATP
  • Subtotal: 25 ATP

(Note: Glycolysis NADH may yield only 1.5 ATP each if using glycerol phosphate shuttle = 3 ATP total)

From FADH₂:

  • Krebs: 2 FADH₂ × 1.5 ATP = 3 ATP

From substrate-level phosphorylation:

  • Glycolysis: 2 ATP
  • Krebs: 2 ATP (or GTP)
  • Subtotal: 4 ATP

Total (using malate-aspartate shuttle): Total=25+3+4=32 ATP\text{Total} = 25 + 3 + 4 = 32 \text{ ATP}

Total (using glycerol phosphate shuttle): Total=23+3+4=30 ATP\text{Total} = 23 + 3 + 4 = 30 \text{ ATP}

Total ATP: 30-32 per glucose (most commonly cited: 30-38)\boxed{\text{Total ATP: 30-32 per glucose (most commonly cited: 30-38)}}

Note: Older textbooks cite 36-38 ATP using 3 ATP/NADH and 2 ATP/FADH₂. Modern estimates (accounting for proton leak and ATP/ADP transport) are lower: ~30-32 ATP.

Summary Table:

| Stage | Location | ATP | NADH | FADH₂ | CO₂ | |-------|----------|-----|------|-------|-----| | Glycolysis | Cytoplasm | 2 | 2 | 0 | 0 | | Pyruvate ox. | Matrix | 0 | 2 | 0 | 2 | | Krebs | Matrix | 2 | 6 | 2 | 4 | | ETC | Inner membrane | ~26 | 0 | 0 | 0 | | TOTAL | | ~30 | | | 6 |

Efficiency:

  • Glucose: 686 kcal/mol
  • ATP: 7.3 kcal/mol
  • Efficiency: (30 × 7.3) / 686 = ~32%
  • Rest lost as heat (maintains body temperature)

2Problem 2easy

Question:

Outline the four stages of cellular respiration: (a) name each stage, (b) state where each occurs in the cell, (c) identify the main products of each stage, and (d) calculate the total ATP yield from one glucose molecule.

💡 Show Solution

Cellular Respiration Overview:

C6H12O6+6O26CO2+6H2O+ATP\text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{CO}_2 + 6\text{H}_2\text{O} + \text{ATP}

(a) Four stages:

  1. Glycolysis
  2. Pyruvate Oxidation (transition reaction)
  3. Krebs Cycle (Citric Acid Cycle)
  4. Electron Transport Chain + Oxidative Phosphorylation

(b) Locations:

1. Glycolysis:

  • Location: Cytoplasm (cytosol)
  • Anaerobic (doesn't require O₂)

2. Pyruvate Oxidation:

  • Location: Mitochondrial matrix
  • Entry into mitochondria

3. Krebs Cycle:

  • Location: Mitochondrial matrix
  • Aerobic (requires O₂ indirectly)

4. Electron Transport Chain:

  • Location: Inner mitochondrial membrane (cristae)
  • Requires O₂ as final electron acceptor

(c) Products of each stage:

1. Glycolysis (glucose → 2 pyruvate):

  • ATP: 2 net (4 produced - 2 invested)
  • NADH: 2
  • Pyruvate: 2

2. Pyruvate Oxidation (2 pyruvate → 2 acetyl-CoA):

  • NADH: 2
  • CO₂: 2
  • Acetyl-CoA: 2

3. Krebs Cycle (2 turns, one per acetyl-CoA):

  • ATP (GTP): 2
  • NADH: 6
  • FADH₂: 2
  • CO₂: 4

4. Electron Transport Chain:

  • ATP: ~34 (from NADH and FADH₂)
  • H₂O: 6 (O₂ reduced)

(d) Total ATP yield:

From NADH:

  • Glycolysis: 2 NADH × 2.5 ATP = 5 ATP
  • Pyruvate oxidation: 2 NADH × 2.5 ATP = 5 ATP
  • Krebs: 6 NADH × 2.5 ATP = 15 ATP
  • Subtotal: 25 ATP

(Note: Glycolysis NADH may yield only 1.5 ATP each if using glycerol phosphate shuttle = 3 ATP total)

From FADH₂:

  • Krebs: 2 FADH₂ × 1.5 ATP = 3 ATP

From substrate-level phosphorylation:

  • Glycolysis: 2 ATP
  • Krebs: 2 ATP (or GTP)
  • Subtotal: 4 ATP

Total (using malate-aspartate shuttle): Total=25+3+4=32 ATP\text{Total} = 25 + 3 + 4 = 32 \text{ ATP}

Total (using glycerol phosphate shuttle): Total=23+3+4=30 ATP\text{Total} = 23 + 3 + 4 = 30 \text{ ATP}

Total ATP: 30-32 per glucose (most commonly cited: 30-38)\boxed{\text{Total ATP: 30-32 per glucose (most commonly cited: 30-38)}}

Note: Older textbooks cite 36-38 ATP using 3 ATP/NADH and 2 ATP/FADH₂. Modern estimates (accounting for proton leak and ATP/ADP transport) are lower: ~30-32 ATP.

Summary Table:

| Stage | Location | ATP | NADH | FADH₂ | CO₂ | |-------|----------|-----|------|-------|-----| | Glycolysis | Cytoplasm | 2 | 2 | 0 | 0 | | Pyruvate ox. | Matrix | 0 | 2 | 0 | 2 | | Krebs | Matrix | 2 | 6 | 2 | 4 | | ETC | Inner membrane | ~26 | 0 | 0 | 0 | | TOTAL | | ~30 | | | 6 |

Efficiency:

  • Glucose: 686 kcal/mol
  • ATP: 7.3 kcal/mol
  • Efficiency: (30 × 7.3) / 686 = ~32%
  • Rest lost as heat (maintains body temperature)

3Problem 3easy

Question:

Outline the four stages of cellular respiration: (a) name each stage, (b) state where each occurs in the cell, (c) identify the main products of each stage, and (d) calculate the total ATP yield from one glucose molecule.

💡 Show Solution

Cellular Respiration Overview:

C6H12O6+6O26CO2+6H2O+ATP\text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{CO}_2 + 6\text{H}_2\text{O} + \text{ATP}

(a) Four stages:

  1. Glycolysis
  2. Pyruvate Oxidation (transition reaction)
  3. Krebs Cycle (Citric Acid Cycle)
  4. Electron Transport Chain + Oxidative Phosphorylation

(b) Locations:

1. Glycolysis:

  • Location: Cytoplasm (cytosol)
  • Anaerobic (doesn't require O₂)

2. Pyruvate Oxidation:

  • Location: Mitochondrial matrix
  • Entry into mitochondria

3. Krebs Cycle:

  • Location: Mitochondrial matrix
  • Aerobic (requires O₂ indirectly)

4. Electron Transport Chain:

  • Location: Inner mitochondrial membrane (cristae)
  • Requires O₂ as final electron acceptor

(c) Products of each stage:

1. Glycolysis (glucose → 2 pyruvate):

  • ATP: 2 net (4 produced - 2 invested)
  • NADH: 2
  • Pyruvate: 2

2. Pyruvate Oxidation (2 pyruvate → 2 acetyl-CoA):

  • NADH: 2
  • CO₂: 2
  • Acetyl-CoA: 2

3. Krebs Cycle (2 turns, one per acetyl-CoA):

  • ATP (GTP): 2
  • NADH: 6
  • FADH₂: 2
  • CO₂: 4

4. Electron Transport Chain:

  • ATP: ~34 (from NADH and FADH₂)
  • H₂O: 6 (O₂ reduced)

(d) Total ATP yield:

From NADH:

  • Glycolysis: 2 NADH × 2.5 ATP = 5 ATP
  • Pyruvate oxidation: 2 NADH × 2.5 ATP = 5 ATP
  • Krebs: 6 NADH × 2.5 ATP = 15 ATP
  • Subtotal: 25 ATP

(Note: Glycolysis NADH may yield only 1.5 ATP each if using glycerol phosphate shuttle = 3 ATP total)

From FADH₂:

  • Krebs: 2 FADH₂ × 1.5 ATP = 3 ATP

From substrate-level phosphorylation:

  • Glycolysis: 2 ATP
  • Krebs: 2 ATP (or GTP)
  • Subtotal: 4 ATP

Total (using malate-aspartate shuttle): Total=25+3+4=32 ATP\text{Total} = 25 + 3 + 4 = 32 \text{ ATP}

Total (using glycerol phosphate shuttle): Total=23+3+4=30 ATP\text{Total} = 23 + 3 + 4 = 30 \text{ ATP}

Total ATP: 30-32 per glucose (most commonly cited: 30-38)\boxed{\text{Total ATP: 30-32 per glucose (most commonly cited: 30-38)}}

Note: Older textbooks cite 36-38 ATP using 3 ATP/NADH and 2 ATP/FADH₂. Modern estimates (accounting for proton leak and ATP/ADP transport) are lower: ~30-32 ATP.

Summary Table:

| Stage | Location | ATP | NADH | FADH₂ | CO₂ | |-------|----------|-----|------|-------|-----| | Glycolysis | Cytoplasm | 2 | 2 | 0 | 0 | | Pyruvate ox. | Matrix | 0 | 2 | 0 | 2 | | Krebs | Matrix | 2 | 6 | 2 | 4 | | ETC | Inner membrane | ~26 | 0 | 0 | 0 | | TOTAL | | ~30 | | | 6 |

Efficiency:

  • Glucose: 686 kcal/mol
  • ATP: 7.3 kcal/mol
  • Efficiency: (30 × 7.3) / 686 = ~32%
  • Rest lost as heat (maintains body temperature)

4Problem 4hard

Question:

Explain the chemiosmotic theory of ATP synthesis: (a) describe how the electron transport chain creates a proton gradient, (b) explain how ATP synthase uses this gradient to make ATP, and (c) calculate how many H⁺ must flow through ATP synthase to make one ATP.

💡 Show Solution

Chemiosmotic Theory (Peter Mitchell, 1961):

(a) Electron Transport Chain - Creating the gradient:

Overview: ETC pumps H⁺ from matrix to intermembrane space, creating electrochemical gradient

Four protein complexes + 2 mobile carriers:

Complex I (NADH dehydrogenase):

  • Accepts: 2e⁻ from NADH
  • Passes to: Ubiquinone (CoQ)
  • Pumps: 4 H⁺ out
  • NADH → NAD⁺ + H⁺ + 2e⁻

Complex II (Succinate dehydrogenase):

  • Accepts: 2e⁻ from FADH₂ (from Krebs cycle)
  • Passes to: CoQ
  • Pumps: 0 H⁺ (no pumping!)
  • Lower entry point → less ATP

Ubiquinone (CoQ):

  • Mobile carrier in membrane
  • Carries electrons from Complex I/II to Complex III
  • Also picks up H⁺ from matrix

Complex III (Cytochrome bc₁ complex):

  • Accepts: 2e⁻ from CoQ
  • Passes to: Cytochrome c
  • Pumps: 4 H⁺ out
  • Q-cycle mechanism

Cytochrome c:

  • Mobile carrier (peripheral protein)
  • Carries electrons from Complex III to Complex IV

Complex IV (Cytochrome oxidase):

  • Accepts: 2e⁻ from cytochrome c
  • Passes to: O₂ (final electron acceptor)
  • Pumps: 2 H⁺ out
  • Reaction: ½O₂ + 2H⁺ + 2e⁻ → H₂O

Total H⁺ pumped:

  • Per NADH: 4 + 4 + 2 = 10 H⁺
  • Per FADH₂: 0 + 4 + 2 = 6 H⁺

Electrochemical gradient created:

  • Chemical gradient (ΔpH): ~0.5-1 pH units
    • Matrix pH ~8, intermembrane space pH ~7
  • Electrical gradient (ΔΨ): ~180 mV (matrix negative)
  • Proton-motive force (PMF):

Δp=ΔΨ2.3RTFΔpH\Delta p = \Delta\Psi - \frac{2.3RT}{F}\Delta pH

At 37°C: Δp18060(1)=220 mV\Delta p \approx 180 - 60(1) = 220 \text{ mV}

(b) ATP Synthase - Using the gradient:

Structure:

F₀ portion (membrane-embedded):

  • c-ring: 8-15 subunits forming rotor
  • Proton channel through a-subunit
  • Anchored in membrane

F₁ portion (matrix-facing):

  • 3α and 3β subunits (catalytic)
  • γ-subunit (central stalk/rotor)
  • Extends into matrix

Mechanism (rotary catalysis):

Step 1: H⁺ enters channel in F₀

  • H⁺ binds to c-ring subunit
  • Neutralizes negative charge (Asp/Glu residue)

Step 2: Rotation

  • Binding of H⁺ causes c-ring to rotate
  • Each H⁺ binding causes ~30° rotation (for 12-subunit c-ring)

Step 3: H⁺ release

  • c-ring rotation brings H⁺ to exit channel
  • H⁺ released into matrix
  • c-ring subunit returns to start

Step 4: Mechanical energy → chemical energy

  • γ-subunit (connected to c-ring) rotates

  • Rotation changes conformation of β-subunits

  • 3 β-subunits cycle through 3 states:

    1. Open (O): ADP + Pi bind
    2. Loose (L): Binding stimulated
    3. Tight (T): ATP formed and released

Binding change mechanism:

  • All three β-subunits in different states simultaneously
  • 120° rotation changes: O → L → T → O
  • ATP formed spontaneously when in T state
  • Energy used to RELEASE ATP, not form it!

(c) H⁺ per ATP calculation:

Depends on c-ring size:

Most organisms: c-ring with 8-15 subunits

Complete rotation (360°):

  • c-ring: 10 subunits (common in mitochondria)
  • 1 full rotation = 10 H⁺ through F₀
  • 1 full rotation = 3 ATP made (3 β-subunits × 1 ATP each)

H+ATP=1033.3 H+/ATP\frac{\text{H}^+}{\text{ATP}} = \frac{10}{3} \approx 3.3 \text{ H}^+\text{/ATP}

For different c-ring sizes:

  • 8 subunits: 8/3 = 2.7 H⁺/ATP
  • 10 subunits: 10/3 = 3.3 H⁺/ATP
  • 12 subunits: 12/3 = 4.0 H⁺/ATP
  • 15 subunits: 15/3 = 5.0 H⁺/ATP

Approximately 3-4 H+ per ATP (depends on organism)\boxed{\text{Approximately 3-4 H}^+ \text{ per ATP (depends on organism)}}

ATP yield from NADH:

NADH → 10 H⁺ pumped

At 3.3 H⁺/ATP: ATP=103.33 ATP/NADH\text{ATP} = \frac{10}{3.3} \approx 3 \text{ ATP/NADH}

Modern estimates (accounting for ATP/ADP translocase): ATP2.5 ATP/NADH\text{ATP} \approx 2.5 \text{ ATP/NADH}

FADH₂: ATP=63.31.81.5 ATP/FADH2\text{ATP} = \frac{6}{3.3} \approx 1.8 \approx 1.5 \text{ ATP/FADH}_2

Energy coupling: ΔGpmf=nΔp=(3.3)(220 mV)=726 mV\Delta G_{pmf} = n\Delta p = (3.3)(220 \text{ mV}) = 726 \text{ mV}

Enough to drive ATP synthesis: ADP+PiATP+H2OΔG=+30.5 kJ/mol\text{ADP} + \text{P}_i \rightarrow \text{ATP} + \text{H}_2\text{O} \quad \Delta G = +30.5 \text{ kJ/mol}

Uncouplers:

  • DNP (2,4-dinitrophenol): carries H⁺ across membrane
  • Bypasses ATP synthase
  • Energy dissipated as heat (thermogenesis)
  • Brown fat uses UCP1 (uncoupling protein) naturally

5Problem 5hard

Question:

Explain the chemiosmotic theory of ATP synthesis: (a) describe how the electron transport chain creates a proton gradient, (b) explain how ATP synthase uses this gradient to make ATP, and (c) calculate how many H⁺ must flow through ATP synthase to make one ATP.

💡 Show Solution

Chemiosmotic Theory (Peter Mitchell, 1961):

(a) Electron Transport Chain - Creating the gradient:

Overview: ETC pumps H⁺ from matrix to intermembrane space, creating electrochemical gradient

Four protein complexes + 2 mobile carriers:

Complex I (NADH dehydrogenase):

  • Accepts: 2e⁻ from NADH
  • Passes to: Ubiquinone (CoQ)
  • Pumps: 4 H⁺ out
  • NADH → NAD⁺ + H⁺ + 2e⁻

Complex II (Succinate dehydrogenase):

  • Accepts: 2e⁻ from FADH₂ (from Krebs cycle)
  • Passes to: CoQ
  • Pumps: 0 H⁺ (no pumping!)
  • Lower entry point → less ATP

Ubiquinone (CoQ):

  • Mobile carrier in membrane
  • Carries electrons from Complex I/II to Complex III
  • Also picks up H⁺ from matrix

Complex III (Cytochrome bc₁ complex):

  • Accepts: 2e⁻ from CoQ
  • Passes to: Cytochrome c
  • Pumps: 4 H⁺ out
  • Q-cycle mechanism

Cytochrome c:

  • Mobile carrier (peripheral protein)
  • Carries electrons from Complex III to Complex IV

Complex IV (Cytochrome oxidase):

  • Accepts: 2e⁻ from cytochrome c
  • Passes to: O₂ (final electron acceptor)
  • Pumps: 2 H⁺ out
  • Reaction: ½O₂ + 2H⁺ + 2e⁻ → H₂O

Total H⁺ pumped:

  • Per NADH: 4 + 4 + 2 = 10 H⁺
  • Per FADH₂: 0 + 4 + 2 = 6 H⁺

Electrochemical gradient created:

  • Chemical gradient (ΔpH): ~0.5-1 pH units
    • Matrix pH ~8, intermembrane space pH ~7
  • Electrical gradient (ΔΨ): ~180 mV (matrix negative)
  • Proton-motive force (PMF):

Δp=ΔΨ2.3RTFΔpH\Delta p = \Delta\Psi - \frac{2.3RT}{F}\Delta pH

At 37°C: Δp18060(1)=220 mV\Delta p \approx 180 - 60(1) = 220 \text{ mV}

(b) ATP Synthase - Using the gradient:

Structure:

F₀ portion (membrane-embedded):

  • c-ring: 8-15 subunits forming rotor
  • Proton channel through a-subunit
  • Anchored in membrane

F₁ portion (matrix-facing):

  • 3α and 3β subunits (catalytic)
  • γ-subunit (central stalk/rotor)
  • Extends into matrix

Mechanism (rotary catalysis):

Step 1: H⁺ enters channel in F₀

  • H⁺ binds to c-ring subunit
  • Neutralizes negative charge (Asp/Glu residue)

Step 2: Rotation

  • Binding of H⁺ causes c-ring to rotate
  • Each H⁺ binding causes ~30° rotation (for 12-subunit c-ring)

Step 3: H⁺ release

  • c-ring rotation brings H⁺ to exit channel
  • H⁺ released into matrix
  • c-ring subunit returns to start

Step 4: Mechanical energy → chemical energy

  • γ-subunit (connected to c-ring) rotates

  • Rotation changes conformation of β-subunits

  • 3 β-subunits cycle through 3 states:

    1. Open (O): ADP + Pi bind
    2. Loose (L): Binding stimulated
    3. Tight (T): ATP formed and released

Binding change mechanism:

  • All three β-subunits in different states simultaneously
  • 120° rotation changes: O → L → T → O
  • ATP formed spontaneously when in T state
  • Energy used to RELEASE ATP, not form it!

(c) H⁺ per ATP calculation:

Depends on c-ring size:

Most organisms: c-ring with 8-15 subunits

Complete rotation (360°):

  • c-ring: 10 subunits (common in mitochondria)
  • 1 full rotation = 10 H⁺ through F₀
  • 1 full rotation = 3 ATP made (3 β-subunits × 1 ATP each)

H+ATP=1033.3 H+/ATP\frac{\text{H}^+}{\text{ATP}} = \frac{10}{3} \approx 3.3 \text{ H}^+\text{/ATP}

For different c-ring sizes:

  • 8 subunits: 8/3 = 2.7 H⁺/ATP
  • 10 subunits: 10/3 = 3.3 H⁺/ATP
  • 12 subunits: 12/3 = 4.0 H⁺/ATP
  • 15 subunits: 15/3 = 5.0 H⁺/ATP

Approximately 3-4 H+ per ATP (depends on organism)\boxed{\text{Approximately 3-4 H}^+ \text{ per ATP (depends on organism)}}

ATP yield from NADH:

NADH → 10 H⁺ pumped

At 3.3 H⁺/ATP: ATP=103.33 ATP/NADH\text{ATP} = \frac{10}{3.3} \approx 3 \text{ ATP/NADH}

Modern estimates (accounting for ATP/ADP translocase): ATP2.5 ATP/NADH\text{ATP} \approx 2.5 \text{ ATP/NADH}

FADH₂: ATP=63.31.81.5 ATP/FADH2\text{ATP} = \frac{6}{3.3} \approx 1.8 \approx 1.5 \text{ ATP/FADH}_2

Energy coupling: ΔGpmf=nΔp=(3.3)(220 mV)=726 mV\Delta G_{pmf} = n\Delta p = (3.3)(220 \text{ mV}) = 726 \text{ mV}

Enough to drive ATP synthesis: ADP+PiATP+H2OΔG=+30.5 kJ/mol\text{ADP} + \text{P}_i \rightarrow \text{ATP} + \text{H}_2\text{O} \quad \Delta G = +30.5 \text{ kJ/mol}

Uncouplers:

  • DNP (2,4-dinitrophenol): carries H⁺ across membrane
  • Bypasses ATP synthase
  • Energy dissipated as heat (thermogenesis)
  • Brown fat uses UCP1 (uncoupling protein) naturally

6Problem 6hard

Question:

Explain the chemiosmotic theory of ATP synthesis: (a) describe how the electron transport chain creates a proton gradient, (b) explain how ATP synthase uses this gradient to make ATP, and (c) calculate how many H⁺ must flow through ATP synthase to make one ATP.

💡 Show Solution

Chemiosmotic Theory (Peter Mitchell, 1961):

(a) Electron Transport Chain - Creating the gradient:

Overview: ETC pumps H⁺ from matrix to intermembrane space, creating electrochemical gradient

Four protein complexes + 2 mobile carriers:

Complex I (NADH dehydrogenase):

  • Accepts: 2e⁻ from NADH
  • Passes to: Ubiquinone (CoQ)
  • Pumps: 4 H⁺ out
  • NADH → NAD⁺ + H⁺ + 2e⁻

Complex II (Succinate dehydrogenase):

  • Accepts: 2e⁻ from FADH₂ (from Krebs cycle)
  • Passes to: CoQ
  • Pumps: 0 H⁺ (no pumping!)
  • Lower entry point → less ATP

Ubiquinone (CoQ):

  • Mobile carrier in membrane
  • Carries electrons from Complex I/II to Complex III
  • Also picks up H⁺ from matrix

Complex III (Cytochrome bc₁ complex):

  • Accepts: 2e⁻ from CoQ
  • Passes to: Cytochrome c
  • Pumps: 4 H⁺ out
  • Q-cycle mechanism

Cytochrome c:

  • Mobile carrier (peripheral protein)
  • Carries electrons from Complex III to Complex IV

Complex IV (Cytochrome oxidase):

  • Accepts: 2e⁻ from cytochrome c
  • Passes to: O₂ (final electron acceptor)
  • Pumps: 2 H⁺ out
  • Reaction: ½O₂ + 2H⁺ + 2e⁻ → H₂O

Total H⁺ pumped:

  • Per NADH: 4 + 4 + 2 = 10 H⁺
  • Per FADH₂: 0 + 4 + 2 = 6 H⁺

Electrochemical gradient created:

  • Chemical gradient (ΔpH): ~0.5-1 pH units
    • Matrix pH ~8, intermembrane space pH ~7
  • Electrical gradient (ΔΨ): ~180 mV (matrix negative)
  • Proton-motive force (PMF):

Δp=ΔΨ2.3RTFΔpH\Delta p = \Delta\Psi - \frac{2.3RT}{F}\Delta pH

At 37°C: Δp18060(1)=220 mV\Delta p \approx 180 - 60(1) = 220 \text{ mV}

(b) ATP Synthase - Using the gradient:

Structure:

F₀ portion (membrane-embedded):

  • c-ring: 8-15 subunits forming rotor
  • Proton channel through a-subunit
  • Anchored in membrane

F₁ portion (matrix-facing):

  • 3α and 3β subunits (catalytic)
  • γ-subunit (central stalk/rotor)
  • Extends into matrix

Mechanism (rotary catalysis):

Step 1: H⁺ enters channel in F₀

  • H⁺ binds to c-ring subunit
  • Neutralizes negative charge (Asp/Glu residue)

Step 2: Rotation

  • Binding of H⁺ causes c-ring to rotate
  • Each H⁺ binding causes ~30° rotation (for 12-subunit c-ring)

Step 3: H⁺ release

  • c-ring rotation brings H⁺ to exit channel
  • H⁺ released into matrix
  • c-ring subunit returns to start

Step 4: Mechanical energy → chemical energy

  • γ-subunit (connected to c-ring) rotates

  • Rotation changes conformation of β-subunits

  • 3 β-subunits cycle through 3 states:

    1. Open (O): ADP + Pi bind
    2. Loose (L): Binding stimulated
    3. Tight (T): ATP formed and released

Binding change mechanism:

  • All three β-subunits in different states simultaneously
  • 120° rotation changes: O → L → T → O
  • ATP formed spontaneously when in T state
  • Energy used to RELEASE ATP, not form it!

(c) H⁺ per ATP calculation:

Depends on c-ring size:

Most organisms: c-ring with 8-15 subunits

Complete rotation (360°):

  • c-ring: 10 subunits (common in mitochondria)
  • 1 full rotation = 10 H⁺ through F₀
  • 1 full rotation = 3 ATP made (3 β-subunits × 1 ATP each)

H+ATP=1033.3 H+/ATP\frac{\text{H}^+}{\text{ATP}} = \frac{10}{3} \approx 3.3 \text{ H}^+\text{/ATP}

For different c-ring sizes:

  • 8 subunits: 8/3 = 2.7 H⁺/ATP
  • 10 subunits: 10/3 = 3.3 H⁺/ATP
  • 12 subunits: 12/3 = 4.0 H⁺/ATP
  • 15 subunits: 15/3 = 5.0 H⁺/ATP

Approximately 3-4 H+ per ATP (depends on organism)\boxed{\text{Approximately 3-4 H}^+ \text{ per ATP (depends on organism)}}

ATP yield from NADH:

NADH → 10 H⁺ pumped

At 3.3 H⁺/ATP: ATP=103.33 ATP/NADH\text{ATP} = \frac{10}{3.3} \approx 3 \text{ ATP/NADH}

Modern estimates (accounting for ATP/ADP translocase): ATP2.5 ATP/NADH\text{ATP} \approx 2.5 \text{ ATP/NADH}

FADH₂: ATP=63.31.81.5 ATP/FADH2\text{ATP} = \frac{6}{3.3} \approx 1.8 \approx 1.5 \text{ ATP/FADH}_2

Energy coupling: ΔGpmf=nΔp=(3.3)(220 mV)=726 mV\Delta G_{pmf} = n\Delta p = (3.3)(220 \text{ mV}) = 726 \text{ mV}

Enough to drive ATP synthesis: ADP+PiATP+H2OΔG=+30.5 kJ/mol\text{ADP} + \text{P}_i \rightarrow \text{ATP} + \text{H}_2\text{O} \quad \Delta G = +30.5 \text{ kJ/mol}

Uncouplers:

  • DNP (2,4-dinitrophenol): carries H⁺ across membrane
  • Bypasses ATP synthase
  • Energy dissipated as heat (thermogenesis)
  • Brown fat uses UCP1 (uncoupling protein) naturally