Arithmetic Sequences

Patterns and formulas for arithmetic sequences

Arithmetic Sequences

What is a Sequence?

A sequence is an ordered list of numbers.

Example: 2,5,8,11,14,...2, 5, 8, 11, 14, ...

Each number is called a term.

Arithmetic Sequence

An arithmetic sequence has a common difference (dd) between consecutive terms.

Example: 3,7,11,15,19,...3, 7, 11, 15, 19, ...

  • Common difference: d=4d = 4

Finding the Common Difference

d=a2a1=a3a2=...d = a_2 - a_1 = a_3 - a_2 = ...

Subtract any term from the next term.

Explicit Formula

To find the nnth term: an=a1+(n1)da_n = a_1 + (n - 1)d

where:

  • ana_n = nth term
  • a1a_1 = first term
  • dd = common difference
  • nn = term number

Recursive Formula

an=an1+da_n = a_{n-1} + d

Each term equals the previous term plus dd.

📚 Practice Problems

1Problem 1easy

Question:

Find the common difference: 5,9,13,17,...5, 9, 13, 17, ...

💡 Show Solution

Subtract consecutive terms:

d=95=4d = 9 - 5 = 4

Check: 139=413 - 9 = 4

Answer: Common difference = 44

2Problem 2medium

Question:

Find the 10th term of the sequence: 3,7,11,15,...3, 7, 11, 15, ...

💡 Show Solution

Step 1: Identify a1a_1 and dd a1=3,d=73=4a_1 = 3, \quad d = 7 - 3 = 4

Step 2: Use the explicit formula an=a1+(n1)da_n = a_1 + (n - 1)d

Step 3: Substitute n=10n = 10 a10=3+(101)(4)a_{10} = 3 + (10 - 1)(4) =3+9(4)= 3 + 9(4) =3+36= 3 + 36 =39= 39

Answer: a10=39a_{10} = 39

3Problem 3hard

Question:

The 5th term of an arithmetic sequence is 23 and the common difference is 4. Find the first term.

💡 Show Solution

Use the formula: an=a1+(n1)da_n = a_1 + (n - 1)d

Given: a5=23a_5 = 23, d=4d = 4, n=5n = 5

Substitute: 23=a1+(51)(4)23 = a_1 + (5 - 1)(4) 23=a1+1623 = a_1 + 16

Solve for a1a_1: a1=2316=7a_1 = 23 - 16 = 7

Check: If a1=7a_1 = 7 and d=4d = 4: 7,11,15,19,237, 11, 15, 19, 23

Answer: a1=7a_1 = 7