Area of Triangles and Quadrilaterals

Formulas for calculating area

Area of Triangles and Quadrilaterals

Triangle

Basic formula: A=12bhA = \frac{1}{2}bh where bb = base, hh = height (perpendicular to base)

Heron's Formula (when you know all three sides): A=s(sa)(sb)(sc)A = \sqrt{s(s-a)(s-b)(s-c)} where s=a+b+c2s = \frac{a+b+c}{2} (semi-perimeter)

Rectangle

A=lwA = lw where ll = length, ww = width

Parallelogram

A=bhA = bh where bb = base, hh = height (perpendicular distance between parallel sides)

Trapezoid

A=12(b1+b2)hA = \frac{1}{2}(b_1 + b_2)h where b1b_1 and b2b_2 are the parallel bases, hh = height

Can also write as: A=12h(b1+b2)A = \frac{1}{2}h(b_1 + b_2) or A=mhA = mh where mm is the midsegment

Rhombus

Method 1: A=bhA = bh (like parallelogram)

Method 2: A=12d1d2A = \frac{1}{2}d_1 d_2 (using diagonals)

Square

A=s2A = s^2 where ss = side length

Key Strategy

Always identify the base and perpendicular height!

📚 Practice Problems

1Problem 1easy

Question:

Find the area of a triangle with base 10 and height 6.

💡 Show Solution

Use the formula: A=12bhA = \frac{1}{2}bh

A=12(10)(6)A = \frac{1}{2}(10)(6)

A=602=30A = \frac{60}{2} = 30

Answer: 30 square units

2Problem 2medium

Question:

A trapezoid has bases of 8 and 12, and a height of 5. Find the area.

💡 Show Solution

Use the trapezoid formula: A=12(b1+b2)hA = \frac{1}{2}(b_1 + b_2)h

A=12(8+12)(5)A = \frac{1}{2}(8 + 12)(5)

A=12(20)(5)A = \frac{1}{2}(20)(5)

A=50A = 50

Answer: 50 square units

3Problem 3hard

Question:

A rhombus has diagonals of length 10 and 24. Find its area.

💡 Show Solution

For a rhombus, use the diagonal formula: A=12d1d2A = \frac{1}{2}d_1 d_2

A=12(10)(24)A = \frac{1}{2}(10)(24)

A=2402A = \frac{240}{2}

A=120A = 120

Answer: 120 square units