Statistics and Probability

Data interpretation, probability calculations

Statistics and Probability (ACT Math)

Statistics on the ACT

Measures of Central Tendency

Mean (Average):

Mean=Sum of all valuesNumber of values\text{Mean} = \frac{\text{Sum of all values}}{\text{Number of values}}

Example: Find the mean of 3, 7, 9, 12, 14

Mean=3+7+9+12+145=455=9\text{Mean} = \frac{3 + 7 + 9 + 12 + 14}{5} = \frac{45}{5} = 9

Median (Middle Value):

Steps:

  1. Order the data from least to greatest
  2. If odd number of values: middle value
  3. If even number of values: average of two middle values

Example 1 (odd): 3, 5, 7, 9, 11 → Median = 7

Example 2 (even): 2, 5, 8, 10 → Median = 5+82=6.5\frac{5 + 8}{2} = 6.5

Mode:

The value that appears most frequently

Example: 2, 3, 3, 5, 7, 7, 7, 9 → Mode = 7

Note: Can have multiple modes or no mode

Measures of Spread

Range:

Range=MaximumMinimum\text{Range} = \text{Maximum} - \text{Minimum}

Example: For data 3, 7, 12, 15, 20

Range=203=17\text{Range} = 20 - 3 = 17

Standard Deviation:

Measures how spread out the data is from the mean

  • Small standard deviation: Data clustered near mean
  • Large standard deviation: Data spread out

ACT Tip: You won't calculate standard deviation by hand — just understand what it means!

Box Plots (Box-and-Whisker Plots)

Five-number summary:

  1. Minimum: Smallest value
  2. Q1 (First Quartile): Median of lower half
  3. Q2 (Median): Middle value
  4. Q3 (Third Quartile): Median of upper half
  5. Maximum: Largest value

Interquartile Range (IQR): IQR=Q3Q1\text{IQR} = Q3 - Q1

Example: Data: 2, 4, 6, 8, 10, 12, 14, 16, 18

  • Minimum: 2
  • Q1: 5 (median of 2, 4, 6, 8)
  • Median: 10
  • Q3: 15 (median of 12, 14, 16, 18)
  • Maximum: 18
  • IQR: 155=1015 - 5 = 10

Outliers

Definition: Data points significantly different from others

Rule: A value is an outlier if:

  • Less than Q11.5×IQRQ1 - 1.5 \times \text{IQR}, OR
  • Greater than Q3+1.5×IQRQ3 + 1.5 \times \text{IQR}

Example: With Q1=5Q1 = 5, Q3=15Q3 = 15, IQR=10\text{IQR} = 10:

  • Lower fence: 51.5(10)=105 - 1.5(10) = -10
  • Upper fence: 15+1.5(10)=3015 + 1.5(10) = 30
  • Any value < -10 or > 30 is an outlier

Probability on the ACT

Basic Probability

P(event)=Number of favorable outcomesTotal number of possible outcomesP(\text{event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}

Requirements:

  • 0P(event)10 \leq P(\text{event}) \leq 1
  • Probability of 0 = impossible
  • Probability of 1 = certain
  • Often expressed as fraction, decimal, or percent

Example: What's the probability of rolling a 4 on a standard die?

P(4)=16P(4) = \frac{1}{6}

Complementary Events

Complement rule: P(not A)=1P(A)P(\text{not } A) = 1 - P(A)

Example: If probability of rain is 0.3, probability of no rain is: P(no rain)=10.3=0.7P(\text{no rain}) = 1 - 0.3 = 0.7

Multiple Events

Independent Events: One event doesn't affect the other

Multiplication rule for independent events: P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B)

Example: Flip a coin and roll a die. What's the probability of heads AND rolling a 5?

P(heads and 5)=12×16=112P(\text{heads and 5}) = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12}

Dependent Events: First event affects the second

Example: Draw 2 cards from a deck without replacement. What's the probability both are aces?

First card: P(ace)=452P(\text{ace}) = \frac{4}{52}

Second card: P(acefirst was ace)=351P(\text{ace}|\text{first was ace}) = \frac{3}{51} (only 3 aces left in 51 cards)

Both aces: 452×351=122652=1221\frac{4}{52} \times \frac{3}{51} = \frac{12}{2652} = \frac{1}{221}

"OR" Probabilities

Addition rule for mutually exclusive events (can't happen together): P(A or B)=P(A)+P(B)P(A \text{ or } B) = P(A) + P(B)

Example: Drawing a 5 OR a 6 from a standard deck: P(5 or 6)=452+452=852=213P(5 \text{ or } 6) = \frac{4}{52} + \frac{4}{52} = \frac{8}{52} = \frac{2}{13}

If NOT mutually exclusive: P(A or B)=P(A)+P(B)P(A and B)P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)

Example: Drawing a heart OR a king: P(heart or king)=1352+452152=1652=413P(\text{heart or king}) = \frac{13}{52} + \frac{4}{52} - \frac{1}{52} = \frac{16}{52} = \frac{4}{13}

(Subtract 152\frac{1}{52} because king of hearts is counted twice)

Data Interpretation

Tables and Charts

ACT will give you data in tables — read carefully!

Example: Survey of 100 students

| | Freshman | Sophomore | Total | |-----------|----------|-----------|-------| | Own car | 5 | 20 | 25 | | No car | 45 | 30 | 75 | | Total | 50 | 50 | 100 |

Questions:

  • Probability a randomly selected student is a freshman who owns a car:
    P=5100=0.05P = \frac{5}{100} = 0.05

  • Probability a student owns a car, given they're a sophomore:
    P=2050=0.4P = \frac{20}{50} = 0.4

Scatterplots

Correlation types:

Positive correlation: As xx increases, yy increases
Negative correlation: As xx increases, yy decreases
No correlation: No clear relationship

Strong vs weak:

  • Strong: Points close to a line
  • Weak: Points scattered

ACT Question Types

Type 1: Calculate Mean, Median, Mode

Strategy:

  • Mean: Add all, divide by count
  • Median: Order data, find middle
  • Mode: Find most frequent

If they add a value and ask new mean: New mean=Old sum+New valueNew count\text{New mean} = \frac{\text{Old sum} + \text{New value}}{\text{New count}}

Type 2: Box Plot Interpretation

Strategy:

  • Know what each part represents
  • Q1, Q2 (median), Q3 are marked
  • IQR = Q3Q1Q3 - Q1

Type 3: Basic Probability

Strategy:

  • Count favorable outcomes (numerator)
  • Count total possible outcomes (denominator)
  • Simplify fraction

Type 4: Complementary Probability

Strategy:

  • If asked "at least one," use complement
  • P(at least one)=1P(none)P(\text{at least one}) = 1 - P(\text{none})

Example: Probability at least one head in 3 coin flips?

P(at least one H)=1P(all T)=1(12)3=118=78P(\text{at least one H}) = 1 - P(\text{all T}) = 1 - \left(\frac{1}{2}\right)^3 = 1 - \frac{1}{8} = \frac{7}{8}

Type 5: Multiple Events

Strategy:

  • Identify if independent or dependent
  • If independent: multiply probabilities
  • If dependent: adjust second probability

Type 6: Conditional Probability

"Given that" or "if" signals conditional probability

Strategy: Use only the subset that meets the condition

Example: Given a student is a sophomore (from table above), probability they own a car:

P(carsophomore)=2050=0.4P(\text{car}|\text{sophomore}) = \frac{20}{50} = 0.4

Use sophomore column as your total (50), not whole table (100)

Common ACT Mistakes

Forgetting to order data before finding median
Dividing by wrong number for mean (count ALL values)
Adding probabilities for "AND" (should multiply for independent)
Not adjusting for dependent events (deck gets smaller after first card)
Using whole population instead of subset for conditional probability
Confusing range with IQR (range = max - min; IQR = Q3 - Q1)

Quick Tips for ACT

Mean is affected by outliers — median is more resistant
Complement rule saves time for "at least one" problems
AND = multiply, OR = add (for mutually exclusive)
Dependent events: Adjust denominator and numerator
Conditional probability: Focus only on the given condition
Box plots: Middle line is MEDIAN, not mean
Probability is never > 1 — if you get > 1, you made an error

Formula Quick Reference

| Concept | Formula | |---------|---------| | Mean | xn\frac{\sum x}{n} | | Range | Max - Min | | IQR | Q3Q1Q3 - Q1 | | Basic Probability | favorabletotal\frac{\text{favorable}}{\text{total}} | | Complement | P(not A)=1P(A)P(\text{not } A) = 1 - P(A) | | Independent AND | P(AB)=P(A)×P(B)P(A \cap B) = P(A) \times P(B) | | Mutually Exclusive OR | P(AB)=P(A)+P(B)P(A \cup B) = P(A) + P(B) |

Practice Approach

  1. Read carefully — is it asking for mean, median, or mode?
  2. Organize data if needed (order for median)
  3. Identify probability type — basic, complement, AND, OR?
  4. Set up fraction with favorable/total
  5. Simplify — ACT usually wants simplified fractions or decimals
  6. Check reasonableness — probability should be between 0 and 1

Remember: Statistics and probability on the ACT test core concepts. Know your formulas, understand the difference between mean/median, and practice probability rules!

📚 Practice Problems

1Problem 1easy

Question:

The test scores for 5 students are: 72, 85, 90, 78, and 85. What is the mean score?

A) 78 B) 82 C) 85 D) 90 E) 410

💡 Show Solution

The mean (average) is the sum of all values divided by the number of values.

Step 1: Add all scores 72 + 85 + 90 + 78 + 85 = 410

Step 2: Divide by number of students Mean = 410 ÷ 5 = 82

Answer: B) 82

Note: E) 410 is the sum, not the mean. This is a common trap answer!

Mean vs. Median vs. Mode: • Mean: Average (sum ÷ count) • Median: Middle value when arranged in order • Mode: Most frequent value

For this data: • Mean = 82 • Median = 85 (middle of 72, 78, 85, 85, 90) • Mode = 85 (appears twice)

2Problem 2medium

Question:

A bag contains 3 red marbles, 5 blue marbles, and 2 green marbles. If one marble is randomly selected, what is the probability it is NOT blue?

F) 1/10 G) 1/5 H) 1/2 J) 3/5 K) 7/10

💡 Show Solution

Probability = (Number of favorable outcomes) / (Total outcomes)

Step 1: Find total marbles 3 red + 5 blue + 2 green = 10 total

Step 2: Find marbles that are NOT blue Red + Green = 3 + 2 = 5 marbles

Step 3: Calculate probability P(not blue) = 5/10 = 1/2

Answer: H) 1/2

Alternative method (complement): P(not blue) = 1 - P(blue) P(blue) = 5/10 = 1/2 P(not blue) = 1 - 1/2 = 1/2 ✓

ACT Tip: For "NOT" probability, you can:

  1. Count favorable outcomes directly, OR
  2. Use complement: P(not A) = 1 - P(A)

3Problem 3hard

Question:

The heights (in inches) of 7 basketball players are: 70, 72, 73, 75, 76, 78, 80. What is the interquartile range (IQR)?

A) 3 B) 4 C) 6 D) 8 E) 10

💡 Show Solution

The interquartile range (IQR) = Q3 - Q1

Data: 70, 72, 73, 75, 76, 78, 80 (already ordered, n = 7)

Step 1: Find the median (Q2) Middle value = 75 (4th value)

Step 2: Find Q1 (median of lower half) Lower half: 70, 72, 73 Q1 = 72 (middle of lower half)

Step 3: Find Q3 (median of upper half) Upper half: 76, 78, 80 Q3 = 78 (middle of upper half)

Step 4: Calculate IQR IQR = Q3 - Q1 = 78 - 72 = 6

Answer: C) 6

Why IQR matters: • Measures spread of middle 50% of data • Not affected by outliers (unlike range) • Used in box plots

Quartile Review: • Q1 = 25th percentile (1st quartile) • Q2 = 50th percentile (median) • Q3 = 75th percentile (3rd quartile) • IQR = Q3 - Q1 (middle 50%) • Range = Max - Min (entire spread)