Modeling and Problem Solving

Apply mathematical concepts to real-world problems

Modeling and Problem Solving (ACT Math)

What is Mathematical Modeling?

Mathematical modeling involves using math to represent real-world situations. On the ACT, this means:

  • Translating word problems into equations
  • Interpreting graphs and tables
  • Applying math to practical scenarios
  • Making predictions and drawing conclusions

Word Problem Strategy

The 4-Step Process

Step 1: Understand the Problem

  • What are you asked to find?
  • What information is given?
  • Are there any constraints or conditions?

Step 2: Translate to Math

  • Define variables
  • Write equations or inequalities
  • Identify which operation(s) to use

Step 3: Solve

  • Apply appropriate mathematical techniques
  • Work systematically
  • Check your work as you go

Step 4: Verify and Interpret

  • Does your answer make sense in context?
  • Are units correct?
  • Did you answer what was asked?

Common Word Problem Types

Distance, Rate, and Time

Formula: d=rtd = rt (distance = rate × time)

Also useful:

  • r=dtr = \frac{d}{t}
  • t=drt = \frac{d}{r}

Example: A car travels at 60 mph for 2.5 hours. How far does it go?

d=60×2.5=150 milesd = 60 \times 2.5 = 150 \text{ miles}

Example 2: Two cars leave the same point going opposite directions at 50 mph and 60 mph. How far apart after 3 hours?

Car 1: d1=50×3=150d_1 = 50 \times 3 = 150 miles
Car 2: d2=60×3=180d_2 = 60 \times 3 = 180 miles
Total distance apart: 150+180=330150 + 180 = 330 miles

Work Rate Problems

Formula: Work=Rate×Time\text{Work} = \text{Rate} \times \text{Time}

Key: If someone completes a job in nn hours, their rate is 1n\frac{1}{n} job per hour

Example: Alice can paint a room in 6 hours. Bob can paint it in 4 hours. How long if they work together?

Alice's rate: 16\frac{1}{6} room/hour
Bob's rate: 14\frac{1}{4} room/hour
Combined rate: 16+14=212+312=512\frac{1}{6} + \frac{1}{4} = \frac{2}{12} + \frac{3}{12} = \frac{5}{12} room/hour

Time together: 1512=125=2.4\frac{1}{\frac{5}{12}} = \frac{12}{5} = 2.4 hours

Mixture Problems

Strategy: Set up equation based on the component you're tracking

Example: How many liters of 20% acid solution must be added to 10 liters of 50% acid solution to get 30% solution?

Let xx = liters of 20% solution

Equation (acid amounts): 0.20x+0.50(10)=0.30(x+10)0.20x + 0.50(10) = 0.30(x + 10) 0.20x+5=0.30x+30.20x + 5 = 0.30x + 3 2=0.10x2 = 0.10x x=20 litersx = 20 \text{ liters}

Age Problems

Strategy: Set up equation comparing ages at different times

Example: Sarah is currently 3 times as old as Tom. In 6 years, she'll be twice as old as Tom. How old is Tom now?

Let tt = Tom's current age

Now: Sarah is 3t3t
In 6 years: Tom is t+6t + 6, Sarah is 3t+63t + 6

Equation: 3t+6=2(t+6)3t + 6 = 2(t + 6) 3t+6=2t+123t + 6 = 2t + 12 t=6t = 6

Tom is currently 6 years old.

Percent Increase/Decrease

Percent change: newoldold×100%\frac{\text{new} - \text{old}}{\text{old}} \times 100\%

Successive changes: Must apply one at a time (they don't add!)

Example: A price increases 20%, then decreases 20%. Is it back to original?

Start with $100:

  • After 20% increase: 100×1.20=120100 \times 1.20 = 120
  • After 20% decrease: 120×0.80=96120 \times 0.80 = 96

No! It's now 96,not96, not 100 (4% less than original)

Interpreting Graphs and Models

Linear Models

Form: y=mx+by = mx + b

  • mm = slope (rate of change)
  • bb = y-intercept (starting value)

Example: A gym charges 30initiationfeeplus30 initiation fee plus 15 per month.

Model: C=15m+30C = 15m + 30

  • CC = total cost
  • mm = number of months
  • Slope (15) = monthly rate
  • Intercept (30) = one-time fee

Questions:

  • Cost for 8 months? C=15(8)+30=150C = 15(8) + 30 = 150
  • How many months for 180?180? 180 = 15m + 30m = 10$

Quadratic Models

Form: y=ax2+bx+cy = ax^2 + bx + c

Often models:

  • Projectile motion: h(t)=16t2+v0t+h0h(t) = -16t^2 + v_0t + h_0
  • Area: A=x(50x)A = x(50 - x) for optimization
  • Profit: P=2x2+100x500P = -2x^2 + 100x - 500

Example: A ball is thrown with height h(t)=16t2+64t+5h(t) = -16t^2 + 64t + 5 (in feet, tt in seconds)

Questions:

  • Maximum height? Find vertex: t=b2a=642(16)=2t = -\frac{b}{2a} = -\frac{64}{2(-16)} = 2 seconds
    h(2)=16(4)+64(2)+5=69h(2) = -16(4) + 64(2) + 5 = 69 feet

  • When does it hit ground? Set h(t)=0h(t) = 0 and solve

Exponential Models

Growth: y=a(1+r)ty = a(1 + r)^t where rr is growth rate
Decay: y=a(1r)ty = a(1 - r)^t where rr is decay rate

Example: Population starts at 10,000 and grows 3% per year.

Model: P(t)=10000(1.03)tP(t) = 10000(1.03)^t

After 5 years: P(5)=10000(1.03)511,593P(5) = 10000(1.03)^5 \approx 11,593

Setting Up Equations from Descriptions

Key Phrases

Addition:

  • sum, total, more than, increased by
  • "5 more than xx" → x+5x + 5

Subtraction:

  • difference, less than, decreased by, fewer
  • "5 less than xx" → x5x - 5
  • "5 fewer than xx" → x5x - 5
  • CAREFUL: "5 subtracted from xx" → x5x - 5 (NOT 5x5 - x)

Multiplication:

  • product, times, of (with percent/fraction)
  • "20% of xx" → 0.20x0.20x
  • "twice xx" → 2x2x

Division:

  • quotient, per, ratio
  • "xx divided by 5" → x5\frac{x}{5}
  • "the ratio of xx to 5" → x5\frac{x}{5}

Equals:

  • is, equals, is equal to, is the same as

Problem-Solving Strategies

Strategy 1: Plug In Answer Choices

When: Problem asks "which value" or gives numeric choices

How: Start with middle choice (often C), test if it works

Example: For what value of xx does 2x+5=132x + 5 = 13?
A) 2 B) 4 C) 6 D) 8 E) 10

Try C (6): 2(6)+5=172(6) + 5 = 17 (too big)
Try B (4): 2(4)+5=132(4) + 5 = 13

Strategy 2: Pick Numbers

When: Problem has variables and asks "which expression"

How: Choose simple numbers for variables, test each answer choice

Example: If nn is an even integer, which is always odd?

Pick n=4n = 4:

  • n+1=5n + 1 = 5 (odd) ✓
  • 2n=82n = 8 (even)
  • n2=16n^2 = 16 (even)

Strategy 3: Draw a Diagram

When: Geometry or spatial reasoning problems

How: Sketch the situation, label what you know

Helps with: Triangle problems, distance problems, optimization

Strategy 4: Work Backwards

When: You know the end result and need to find the start

Example: After increasing a number by 20% and then subtracting 15, the result is 45. What was the original number?

Work backwards:

  • Before subtracting 15: 45+15=6045 + 15 = 60
  • Before 20% increase: 601.20=50\frac{60}{1.20} = 50

Original number: 50

Strategy 5: Create a Table or List

When: Pattern problems or multiple cases to track

How: Organize information systematically

Example: A bacteria population doubles every hour. If it starts at 100, what's the population after 4 hours?

| Hour | Population | |------|------------| | 0 | 100 | | 1 | 200 | | 2 | 400 | | 3 | 800 | | 4 | 1600 |

Answer: 1600

ACT Question Types

Type 1: Direct Translation

Strategy: Convert words to math step-by-step

Type 2: Rate Problems

Strategy: Identify d=rtd = rt components, set up equation

Type 3: Optimization

Strategy:

  • Set up equation for what you're maximizing/minimizing
  • Often involves quadratic with vertex

Type 4: Graph Interpretation

Strategy:

  • Identify what each axis represents
  • Read slope as rate of change
  • Use points to answer questions

Type 5: Multi-Step Problems

Strategy:

  • Break into smaller steps
  • Solve one part at a time
  • Use first answer to get second

Common ACT Mistakes

Solving for wrong variable — read what they ask for!
Not checking answer in context — negative age? That's impossible!
Rushing translation — "5 less than xx" is x5x - 5, not 5x5 - x
Forgetting units — mixing hours and minutes, miles and feet
Adding percents — 20% increase then 30% increase ≠ 50% increase!
Not labeling variables clearly — leads to equation errors

Quick Tips for ACT

Underline what you're asked to find — stay focused
Define variables explicitly — write "xx = number of hours"
Draw pictures for geometry and distance problems
Check units — convert to same units before calculating
Estimate first — helps eliminate wrong answers
Use answer choices — can plug in to check
Read ENTIRE problem before starting

Formula Reference

| Situation | Formula | |-----------|---------| | Distance | d=rtd = rt | | Work Rate | Rate=1time to complete\text{Rate} = \frac{1}{\text{time to complete}} | | Combined Work | Rate1+Rate2=Ratetogether\text{Rate}_1 + \text{Rate}_2 = \text{Rate}_{\text{together}} | | Percent Change | newoldold×100%\frac{\text{new} - \text{old}}{\text{old}} \times 100\% | | Linear Growth | y=mx+by = mx + b | | Exponential Growth | y=a(1+r)ty = a(1 + r)^t | | Projectile Height | h(t)=16t2+v0t+h0h(t) = -16t^2 + v_0t + h_0 |

Practice Approach

  1. Read twice — once for overall, once for details
  2. Identify what you're finding — circle or underline it
  3. List what you know — write down given information
  4. Choose a strategy — translate, plug in, draw, etc.
  5. Set up equation carefully — define variables
  6. Solve systematically — show work
  7. Check in context — does answer make sense?
  8. Verify you answered the question — did they ask for xx or 2x+52x + 5?

Remember: Modeling problems test your ability to apply math to real situations. Stay organized, translate carefully, and always check if your answer makes sense!

📚 Practice Problems

1Problem 1easy

Question:

A rectangular garden is 3 times as long as it is wide. If the width is w feet, which expression represents the perimeter in feet?

F) 4w G) 6w H) 8w J) 3w^2 K) 12w

💡 Show Solution

Set up the problem with variables and use the perimeter formula.

Given information: • Width = w feet • Length = 3w feet (3 times the width)

Step 1: Recall perimeter formula for rectangle Perimeter = 2(length) + 2(width) Or: P = 2L + 2W

Step 2: Substitute the expressions P = 2(3w) + 2(w) P = 6w + 2w P = 8w

Answer: H) 8w

Check with a specific example: If w = 5, then length = 15 Perimeter = 5 + 15 + 5 + 15 = 40 8w = 8(5) = 40 ✓

Common mistakes: • F) 4w - forgot the length is 3 times width • G) 6w - only added one length and one width • K) 12w - multiplied instead of using perimeter formula

2Problem 2medium

Question:

A car rental company charges 45perdayplus45 per day plus 0.25 per mile driven. Which equation represents the total cost C (in dollars) for renting a car for d days and driving m miles?

A) C = 45d + 0.25m B) C = 45m + 0.25d C) C = 45 + 0.25(d + m) D) C = (45 + 0.25)(d + m) E) C = 45d × 0.25m

💡 Show Solution

Identify each cost component and add them together.

Cost breakdown: • Daily charge: 45perday×ddays=45dMileagecharge:45 per day × d days = 45d • Mileage charge: 0.25 per mile × m miles = 0.25m

Step 1: Write total cost equation Total Cost = Daily Cost + Mileage Cost C = 45d + 0.25m

Answer: A) C = 45d + 0.25m

Test with an example: 3 days, 200 miles: C = 45(3) + 0.25(200) C = 135 + 50 = $185

Reasonable? Yes! • 3 days at 45=45 = 135 • 200 miles at 0.25=0.25 = 50 • Total = $185 ✓

ACT modeling tip: • Identify what each variable represents • Match units (dollars per day → multiply by days) • Check if answer makes sense with real numbers

3Problem 3hard

Question:

A population of bacteria doubles every 3 hours. If there are initially 500 bacteria, which function models the population P after t hours?

F) P(t) = 500 + 2t G) P(t) = 500(2)^t H) P(t) = 500(2)^(t/3) J) P(t) = 500(3)^(t/2) K) P(t) = 500 + 2^t

💡 Show Solution

This is exponential growth. Key: population doubles every 3 hours.

Exponential growth formula: P(t) = P₀(r)^(t/d) Where: • P₀ = initial amount = 500 • r = growth factor = 2 (doubles) • t = time elapsed • d = doubling period = 3 hours

Step 1: Build the function P(t) = 500(2)^(t/3)

Answer: H) P(t) = 500(2)^(t/3)

Verification: • At t = 0: P(0) = 500(2)^0 = 500(1) = 500 ✓ • At t = 3: P(3) = 500(2)^1 = 1000 ✓ (doubled!) • At t = 6: P(6) = 500(2)^2 = 2000 ✓ (doubled again!)

Why not the others? • F) Linear growth, not exponential • G) Doubles every hour, not every 3 hours • J) Wrong growth factor (3 instead of 2) • K) Linear growth with exponential component

Key: The exponent must be t/3 to account for doubling every 3 hours!