Absolute Value Equations
Solving equations involving absolute value
Absolute Value Equations
What is Absolute Value?
Absolute value is the distance a number is from zero on the number line. Distance is always positive or zero, never negative.
The absolute value of a number x is written as |x|.
Examples:
- |5| = 5 (5 is 5 units from zero)
- |-5| = 5 (-5 is also 5 units from zero)
- |0| = 0 (0 is 0 units from zero)
- |-3.7| = 3.7
- |2 - 7| = |-5| = 5
Key Property of Absolute Value
The absolute value makes all numbers non-negative:
- If x ≥ 0, then |x| = x
- If x < 0, then |x| = -x
Example: |-8| = -(-8) = 8
What is an Absolute Value Equation?
An absolute value equation is an equation that contains an absolute value expression.
Examples:
- |x| = 5
- |x - 3| = 7
- |2x + 1| = 9
- 2|x - 4| + 3 = 11
Why Two Solutions?
Most absolute value equations have TWO solutions because two different numbers can have the same absolute value.
Example: |x| = 5 Both x = 5 and x = -5 work because:
- |5| = 5 ✓
- |-5| = 5 ✓
Think about it: What numbers are 5 units away from zero? Both 5 and -5!
Solving Basic Absolute Value Equations
Form: |x| = a (where a ≥ 0)
Solution: x = a or x = -a
Example 1: |x| = 7 Solution: x = 7 or x = -7
Check:
- |7| = 7 ✓
- |-7| = 7 ✓
Example 2: |x| = 12 Solution: x = 12 or x = -12
Example 3: |x| = 0 Solution: x = 0 (only one solution when a = 0)
Solving |ax + b| = c
Steps:
- Isolate the absolute value expression
- Set up two equations:
- ax + b = c (positive case)
- ax + b = -c (negative case)
- Solve both equations
- Check both solutions
Example 1: |x + 3| = 8
Step 1: Already isolated
Step 2: Set up two equations Case 1: x + 3 = 8 Case 2: x + 3 = -8
Step 3: Solve both Case 1: x = 5 Case 2: x = -11
Step 4: Check
- |5 + 3| = |8| = 8 ✓
- |-11 + 3| = |-8| = 8 ✓
Solution: x = 5 or x = -11
Example 2: |2x - 1| = 7
Case 1: 2x - 1 = 7 2x = 8 x = 4
Case 2: 2x - 1 = -7 2x = -6 x = -3
Check:
- |2(4) - 1| = |7| = 7 ✓
- |2(-3) - 1| = |-7| = 7 ✓
Solution: x = 4 or x = -3
Example 3: |3x + 5| = 4
Case 1: 3x + 5 = 4 3x = -1 x = -1/3
Case 2: 3x + 5 = -4 3x = -9 x = -3
Solution: x = -1/3 or x = -3
Isolating the Absolute Value First
If the absolute value is not already isolated, isolate it BEFORE setting up two equations.
Example 1: 2|x - 3| = 10
Step 1: Divide both sides by 2 |x - 3| = 5
Step 2: Set up two equations x - 3 = 5 or x - 3 = -5
Step 3: Solve x = 8 or x = -2
Example 2: |x + 1| + 5 = 12
Step 1: Subtract 5 from both sides |x + 1| = 7
Step 2: Set up two equations x + 1 = 7 or x + 1 = -7
Step 3: Solve x = 6 or x = -8
Example 3: 3|2x - 4| - 5 = 10
Step 1: Add 5 to both sides 3|2x - 4| = 15
Step 2: Divide by 3 |2x - 4| = 5
Step 3: Set up two equations 2x - 4 = 5 or 2x - 4 = -5
Step 4: Solve 2x = 9 or 2x = -1 x = 4.5 or x = -0.5
Special Cases
Case 1: |expression| = 0 Only ONE solution (the expression equals 0)
Example: |x - 5| = 0 x - 5 = 0 x = 5 (only solution)
Case 2: |expression| = negative number NO SOLUTION (absolute value cannot be negative)
Example: |x + 2| = -3 No solution (absolute value is never negative)
Case 3: Expression equals its negative Example: |2x - 6| = 6 - 2x This happens when the expression is ≤ 0
2x - 6 = 6 - 2x 4x = 12 x = 3
Check: |2(3) - 6| = |0| = 0 and 6 - 2(3) = 0 ✓
Absolute Value with Variables on Both Sides
Form: |ax + b| = cx + d
This is more complex. Consider when the right side can be positive or negative.
Example: |x - 2| = x + 4
Case 1: x - 2 = x + 4 -2 = 4 (no solution from this case)
Case 2: x - 2 = -(x + 4) x - 2 = -x - 4 2x = -2 x = -1
Check: |-1 - 2| = |-3| = 3 and -1 + 4 = 3 ✓
Solution: x = -1
Solving Equations with Two Absolute Values
Form: |expression₁| = |expression₂|
This means the expressions are equal OR opposites.
Set up two equations:
- expression₁ = expression₂
- expression₁ = -(expression₂)
Example: |2x - 1| = |x + 3|
Case 1: 2x - 1 = x + 3 x = 4
Case 2: 2x - 1 = -(x + 3) 2x - 1 = -x - 3 3x = -2 x = -2/3
Check both solutions in original equation:
- For x = 4: |2(4) - 1| = |7| = 7 and |4 + 3| = |7| = 7 ✓
- For x = -2/3: |2(-2/3) - 1| = |-7/3| = 7/3 and |-2/3 + 3| = |7/3| = 7/3 ✓
Solution: x = 4 or x = -2/3
Graphical Interpretation
The solutions to |x - a| = b are the x-values where the distance from x to a equals b.
Example: |x - 3| = 5 Find all x-values that are 5 units away from 3 x = 3 + 5 = 8 or x = 3 - 5 = -2
On a number line: -2 is 5 units to the left of 3 8 is 5 units to the right of 3
Common Mistakes to Avoid
-
Forgetting the negative case Wrong: |x + 2| = 5, so x + 2 = 5, x = 3 (missing x = -7) Right: Set up BOTH x + 2 = 5 and x + 2 = -5
-
Not isolating absolute value first For 2|x| + 3 = 11, must get |x| = 4 before setting up two equations
-
Thinking absolute value can be negative |x| = -5 has NO solution
-
Not checking solutions Sometimes algebraic solutions don't work in original equation
-
Distributing negative incorrectly -(2x + 3) = -2x - 3, not -2x + 3
Checking Your Solutions
Always substitute solutions back into the ORIGINAL equation.
Example: Solve |2x - 3| = 5 Solutions: x = 4 or x = -1
Check x = 4: |2(4) - 3| = |8 - 3| = |5| = 5 ✓
Check x = -1: |2(-1) - 3| = |-2 - 3| = |-5| = 5 ✓
Both solutions work!
Real-World Applications
Absolute value equations model situations involving distance, tolerance, and error.
Example 1: Manufacturing Tolerance A bolt must be 5 cm long with a tolerance of ±0.2 cm. |length - 5| ≤ 0.2 Acceptable lengths: 4.8 cm to 5.2 cm
Example 2: Temperature Range The temperature should be 70°F, varying by at most 3°. |T - 70| ≤ 3 Acceptable range: 67°F to 73°F
Example 3: Distance Two cars start from the same point and drive in opposite directions. When are they 100 miles apart? If they each travel x miles: |x - (-x)| = |2x| = 100 So 2x = 100, x = 50 miles each
Problem-Solving Strategy
- Isolate the absolute value expression
- Check if the right side is positive, zero, or negative
- Negative: no solution
- Zero: one solution
- Positive: usually two solutions
- Set up two equations (positive and negative cases)
- Solve both equations
- Check all solutions in the original equation
- Reject any solutions that don't work
Absolute Value Inequalities (Preview)
While this topic focuses on equations, you'll later learn:
- |x| < a means -a < x < a (between)
- |x| > a means x < -a or x > a (outside)
Quick Reference
| Equation Type | Setup | Number of Solutions | |---------------|-------|---------------------| | |x| = a (a > 0) | x = ±a | 2 solutions | | |x| = 0 | x = 0 | 1 solution | | |x| = a (a < 0) | No solution | 0 solutions | | |ax + b| = c | ax + b = ±c | Usually 2 | | |expr₁| = |expr₂| | expr₁ = ±expr₂ | Usually 2 |
Practice Tips
- Always isolate the absolute value first
- Set up both positive and negative cases
- Be systematic in your work
- Always check your solutions
- Remember: absolute value is never negative
- Draw number lines to visualize distance
- Look for special cases (0, negative, variables on both sides)
- Practice with different types of problems
📚 Practice Problems
1Problem 1easy
❓ Question:
Solve: |x| = 7
💡 Show Solution
Step 1: Understand absolute value: |x| = 7 means "the distance from 0 is 7"
Step 2: Consider both cases: Case 1: x = 7 (positive solution) Case 2: x = -7 (negative solution)
Step 3: Both solutions work because: |7| = 7 ✓ |-7| = 7 ✓
Answer: x = 7 or x = -7
2Problem 2easy
❓ Question:
Solve:
💡 Show Solution
The absolute value of is 9, so could be 9 or -9.
Check: ✓ and ✓
Answer: or
3Problem 3easy
❓ Question:
Solve: |x + 3| = 5
💡 Show Solution
Step 1: Set up two cases (remove absolute value bars): Case 1: x + 3 = 5 Case 2: x + 3 = -5
Step 2: Solve Case 1: x + 3 = 5 x = 2
Step 3: Solve Case 2: x + 3 = -5 x = -8
Step 4: Check both solutions: |2 + 3| = |5| = 5 ✓ |-8 + 3| = |-5| = 5 ✓
Answer: x = 2 or x = -8
4Problem 4medium
❓ Question:
Solve:
💡 Show Solution
Split into two cases:
Case 1:
Case 2:
Check:
- ✓
- ✓
Answer: or
5Problem 5medium
❓ Question:
Solve: |2x - 1| = 9
💡 Show Solution
Step 1: Set up two cases: Case 1: 2x - 1 = 9 Case 2: 2x - 1 = -9
Step 2: Solve Case 1: 2x - 1 = 9 2x = 10 x = 5
Step 3: Solve Case 2: 2x - 1 = -9 2x = -8 x = -4
Step 4: Check both solutions: |2(5) - 1| = |10 - 1| = |9| = 9 ✓ |2(-4) - 1| = |-8 - 1| = |-9| = 9 ✓
Answer: x = 5 or x = -4
6Problem 6medium
❓ Question:
Solve: 3|x - 2| + 4 = 13
💡 Show Solution
Step 1: Isolate the absolute value: 3|x - 2| + 4 = 13 3|x - 2| = 9 |x - 2| = 3
Step 2: Set up two cases: Case 1: x - 2 = 3 Case 2: x - 2 = -3
Step 3: Solve Case 1: x - 2 = 3 x = 5
Step 4: Solve Case 2: x - 2 = -3 x = -1
Step 5: Check both solutions in the original equation: 3|5 - 2| + 4 = 3|3| + 4 = 9 + 4 = 13 ✓ 3|-1 - 2| + 4 = 3|-3| + 4 = 9 + 4 = 13 ✓
Answer: x = 5 or x = -1
7Problem 7hard
❓ Question:
Solve:
💡 Show Solution
Step 1: Isolate the absolute value
Step 2: Split into two cases
Case 1:
Case 2:
Answer: or
8Problem 8hard
❓ Question:
Solve: |3x + 1| = |x - 5|
💡 Show Solution
Step 1: When two absolute values are equal, set up cases: Case 1: The expressions are equal 3x + 1 = x - 5
Case 2: The expressions are opposites 3x + 1 = -(x - 5)
Step 2: Solve Case 1: 3x + 1 = x - 5 2x = -6 x = -3
Step 3: Solve Case 2: 3x + 1 = -x + 5 4x = 4 x = 1
Step 4: Check both solutions: For x = -3: |3(-3) + 1| = |-9 + 1| = |-8| = 8 |-3 - 5| = |-8| = 8 ✓
For x = 1: |3(1) + 1| = |4| = 4 |1 - 5| = |-4| = 4 ✓
Answer: x = -3 or x = 1
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